উত্তর
ব্যাখ্যা
Solution:
Let, ten’s digit = x.
Then, unit’s digit = x².
∴ number = 10x + x².
Since x² > x,
so, the number formed by interchanging the digits is greater than the original number.
∴ (10x² + x) - (10x + x²) = 54
⇒ 9x² - 9x = 54
⇒ x² - x = 6
⇒ x² - x - 6 = 0
⇒ x² - 3x + 2x - 6 = 0
⇒ x(x - 3) + 2(x - 3) = 0
⇒ (x - 3) (x + 2) = 0
⇒ x = 3. [∵ it is positive number]
So, ten’s digit = 3, unit’s digit = 3² = 9.
∴ Original number = 39.
Required result = 40% of 39
= (40/100) × 39 = 15.6.