ব্যাখ্যা
Let C.P.=Tk. 100
Then,
M.P. = Tk. 135,
S.P. =Tk.108
∴Discount % =(27/135 ×100)% =20%
ব্যাংক নিয়োগ প্রস্তুতি ⎯ লং কোর্স · তারিখ অনির্ধারিত · ২৩ প্রশ্ন
Let C.P.=Tk. 100
Then,
M.P. = Tk. 135,
S.P. =Tk.108
∴Discount % =(27/135 ×100)% =20%
According to the question,
Loss = 20% Selling price
i.e.
Loss/ Selling price = 1/5
∴ Cost price = Selling price + Loss
= 5 + 1
= 6
∴Loss%=1/6 ×100=50/3%
CP of 1 orange
= Tk.34/8
= Tk.4.25
SP of 1 orange
=Tk. 57/12
=Tk.4.75
Profit on each apple = (4.75 - 4.25) = Tk. 0.50
∴ Number of apples required
= 45/ 0.50
=90
Money spent by X = Tk. 150000
Money received by X = 105% of Tk. 150000 = Tk. 157500
C.P. to X = 98% of Tk. 157500 = Tk. 154350
∴ X gains Tk. (157500 - 154350) = Tk. 3150
Given,
= MRP of book = Tk. 100
= Selling price of 3 books = Tk. 274.50
= Selling price of 1 book = Tk. 91.50
Discount on each book
= 100 - 91.50 = Tk. 8.50
Therefore discount %
=8.50/100×100%
=8.50%
Let the price paid by Prateek be Tk. x
Then,
140% of 120% of x=10500
⇒(140/100)×(120/100)×x=10500
⇒ x=(10500×25/42)=6250
According to the question,
Cost Price : Marked Price
(100 - Discount) : (100 + Profit)
100 - 10 : 100 + 12
90 : 112
45 : 56
C.P. of 70 kg wheat
= Tk. (30 × 9.50 + 40 × 8.50)
= Tk. (285 + 340)
= Tk. 625
S.P. of 70 kg wheat
= Tk. (70 × 8.90)
= Tk. 623
∴ Loss = Tk. (625 - 623) = Tk. 2
Given loss = 10% profit = 10%
Difference of overall profit and loss = 10 - (-10) = 20%
20% of cp = sp
20/ 100×cp = 108
20 × cp = 108 × 100
cp = 10800/20
∴ cp = 540
Let the new S.P. be Tk. x
Then,80:9=105:x
⇒x=(9×105/ 80)=11.81
According to the question,
Loss 20%
Selling price
=100%−20=80%
80%=480
1=480/80
∴(Profit 20%) = 480/ 80 ×120
=Tk. 720
Total C.P. = Cost + Overhead Expenses
= Tk. (150 + 12% of 150)
= Tk. (150 + 18)
= Tk. 168
∴S.P.=Tk.(110/100×168)=Tk. 184.80
A Total Profit = Tk 3600
Profit ratio,
A : B = 5 : 4
B : C = 8 : 9
As B is common in both ratio, we make B equal in both ratio by multiplying One B in another.
A : B = 5 : 4 × 8
B : C = 8 × 4 : 9
So, ratio of
A : B : C = 40 : 32 : 36 = 10 : 8 : 9
Now,
C shares in profit = (3600×9)/27
= Tk 1200
To gain 20% on whole he must sell all good for,
400 + 20% of 400 = 480
As he get 5% gain on half of the goods i.e.
200 + 5% of 200 = 210
So required balance = 480 - 210 = 270
He must gain Tk. 70 on rest Tk. 200
% gain on remainder goods =(70×100)/200 = 35%
Marked Price = 2000
SP after first Discount of 20% = 2000 - 20% of 2000 = 1600
SP after second Discount of 10% = 1600 - 10% of 1600 = 1440
Now, the final selling price at cash = 1440 - 5% of 1440 = Tk. 1368
C.P. of 56 kg rice = (26 x 20 + 30 x 36)
=(520 + 1080)
=1600.
S.P. of 56 kg rice = (56 x 30)
= 1680.
Gain = 80x100% = 5%.
C.P. = (100/122.5)x 392
= (1000/1225)x 392
= 320
Profit = (392 - 320) = 72.
Let the required number of rounds be x
More radius, Less rounds (Indirect proportion)
∴ 20:14::70:x
⇔(20×x)=(14×70)
⇔ x= (14×70)/ 20
⇔ x=49
Let the required number of days be x
7 men = 10 women
(14 men and 20 women) = (20 + 20) women = 40 women
More length, More days (Direct proportion)
More women, Less days (Indirect proportion)
Length 100:600 & Women 40:10} :: 10:x
∴ 100×40×x = 600×10×10
⇔ x = (600×10×10)(100×40)
⇔ x = 15
Let the required number of working hours per day be x
More pumps, Less working hours per day (Indirect proportion)
Less days, More working hours per day (Indirect proportion)
Pumps 4:3 & Days 1:2 } :: 8:x
∴ 4×1×x = 3×2×8
⇔ x = (3×2×8)/(4)
⇔ x = 12
Work done = 5/8
Balance work =(1 - 5/8) = 3/8
Let the required number of days be x.
Then,(5/8 : 3/8)= :: 10 : x ⇔ 5/8 × x = 3/8 × 10
x = 3/8 × 10 × 8/5
⇒ x = 6.
As it is given that food is there for 54 days for 2000 students,
But after 15 days, remaining food was sufficient for 2000 students for 39 days only ( as 54-15 = 39 )
Let x number of students came in hostel after 15 days,
=> Total number of students after 15 days = 2000 + x
=> Remaining food was enough for (2000 + x) students for 20 days
So here is indirect proportion, as more people and less food
=> 2000 : ( 2000 + x ) :: 20 : 39
=> 2000× 39 = (2000 + x )× 20
=> 3900 = 2000 + x
=> x = 3900 - 2000
=> x = 1900
Let the required number of revolutions made by larger wheel be x.
Then, More cogs, Less revolutions (Indirect Proportion)
14 : 6 :: 21 : x
or, 14 x x = 6 x 21
or, x = (6 x 21)/14
so, x = 9.