ব্যাখ্যা
Solution:
We have (log2x)2 - log2x4 - 32 = 0.
⇒ (log2x)2 - 4log2x - 32 = 0 ......(1)
Let log2x = y
(i) ⇒ y2 - 4y - 32 = 0
⇒ y2 - 8y + 4y - 32 = 0
⇒ y (y - 8) + 4(y - 8) = 0
⇒ (y - 8) (y + 4) = 0
⇒ y = 8, - 4
⇒ log2x = 8 or log2x = - 4
⇒ x = 28 = 256 or x = 2- 4 = 1/16
Since ‘x’ is an integer so x = 256.