উত্তর
ব্যাখ্যা
Solution:
The average price of three items of furniture is Rs. 30000.
total price = (30000 × 3) = 90000
their prices are in the ratio 3 : 5 : 7
∴ the price of the cheapest item is = 90000 × 3/15
= 18000 tk
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Both game is played by = 100 - (35 + 45) = 20% children
So, in all cricket can be played by = 55% of 80 children
= 55/100 × 80 = 44 children
Question: If the side of a square is increased by 10%, by what percent will the area be increased?
Solution:
Let the original side length = 10 units.
∴ Area = 10 × 10 = 100 square units
Again,
After a 10% increase, the new side length = 10 + 10% of 10
= 10 + 1 = 11 units
∴ New area = 11 × 11 = 121 square units
∴ Increase in area = 121 - 100 square units
= 21 square units
∴ Percentage increase in area = (21/100) × 100%
= 21%
So the area will increase by 21%
A + B can do the work in 12 days.
In a single day A + B will do 1/12th portion of the work.
B+C can do the work in 15 days.
In a single day B+C will do 1/15th portion of the work.
A + C can do the work in 20 days.
In a single day A+C will do 1/20th portion of the work.
In a day (A+B) + (A+C) + (C+A) will do = (1/12) + (1/15) + (1/20) portion of the work.
⇒ 2(A+B+C) = (1/12)+(1/15)+(1/20) = (5+4+3)/60 = 1/5 portion of the work.
Then, (A+B+C) will do = 1/10 portion of the work in a day
∴ A+B+C will complete the work in 10 days.
Question: Mr. Karim deposited a certain amount of money for a fixed period of time. On maturity, he received a total of Tk. 50,000 when the ratio of interest and investment became 1: 4. If the simple interest rate was 5%, calculate the time period for which the money was invested.
Solution:
প্রদত্ত তথ্য অনুযায়ী, আসল এবং সুদের অনুপাত = 4 : 1
মোট প্রাপ্ত টাকা = 50,000 টাকা
মোট অনুপাত = 4 + 1 = 5
সুতরাং, আসল = 50,000 টাকার (4/5) অংশ = 40,000 টাকা
এবং, সুদ = 50,000 টাকার (1/5) অংশ = 10,000 টাকা
এখানে,
I = সুদ = 10,000 টাকা
P = আসল = 40,000 টাকা
R = সুদের হার = 5%
T = সময়কাল = ?
আমরা জানি, সরল সুদের ক্ষেত্রে,
I = (P × R × T)/100
⇒ 10,000 = (40,000 × 5 × T)/100
⇒ 10,000 = 400 × 5 × T
⇒ 10,000 = 2,000 × T
⇒ T = 10,000/2,000
⇒ T = 5
সুতরাং, টাকাটি 5 বছরের জন্য বিনিয়োগ করা হয়েছিল।
Question: A train takes 10 seconds to cross a pole and 25 seconds to cross a platform of length 180m. What is the length of the train?
Solution:
মনে করি, ট্রেনটির দৈর্ঘ্য L মিটার।
আমরা জানি, একটি খুঁটি (pole) অতিক্রম করার সময় ট্রেনটি কেবল তার নিজের দৈর্ঘ্য অতিক্রম করে।
সুতরাং, ট্রেনের গতিবেগ = L/10 মি./সে. [গতিবেগ = দূরত্ব/সময়]
আবার, প্ল্যাটফর্ম অতিক্রম করার সময় ট্রেনটি (নিজের দৈর্ঘ্য + প্ল্যাটফর্মের দৈর্ঘ্য) অতিক্রম করে।
শর্তমতে, গতিবেগ = (L + 180)/25 মি./সে.
যেহেতু গতিবেগ একই, তাই,
L/10 = (L + 180)/25
⇒ 25L = 10(L + 180)
⇒ 25L = 10L + 1800
⇒ 25L - 10L = 1800
⇒ 15L = 1800
⇒ L = 1800/15
∴ L = 120
∴ ট্রেনটির দৈর্ঘ্য 120 মিটার।
Question: There are 8 black, 5 red and 7 green marbles in a jar. If a marble is picked at random, what is the probability of having either a black or a green marble?
Solution:
মোট মার্বেলের সংখ্যা = 8 + 5 + 7 = 20
কালো মার্বেল পাওয়ার সম্ভাবনা, P(Black) = 8/20
সবুজ মার্বেল পাওয়ার সম্ভাবনা P(Green) = 7/20
যেহেতু কালো এবং সবুজ মার্বেল পাওয়া দুটি বিচ্ছিন্ন (mutually exclusive) ঘটনা,
∴ কালো অথবা সবুজ মার্বেল পাওয়ার সম্ভাবনা (P(Black or Green) = P(Black) + P(Green)
= 8/20 + 7/20
= (8 + 7) / 20 = 15/20
= 3/4
অতএব, কালো অথবা সবুজ মার্বেল পাওয়ার সম্ভাবনা হলো 3/4।
• Shortcut:
মোট মার্বেলের সংখ্যা = 8 + 5 + 7 = 20
অনুকূল ঘটনা = কালো + সবুজ = 8 + 7 = 15টি
∴ সম্ভাবনা = অনুকূল ঘটনা/মোট ঘটনা = 15/20 = 3/4
Question: A chemist has two solutions, one containing 40% acid and the other containing 80% acid. How many liters of each solution should be mixed to get 12 liters of a solution containing 60% acid?
Solution:
Let x liters of 40% solution be used. Then (12 - x) liters of 80% solution will be used.
According to the problem:
40% × x + 80% × (12 - x) = 60% × 12
⇒ 40x + 80(12 - x) = 720
⇒ 40x + 960 - 80x = 720
⇒ -40x + 960 = 720
⇒ -40x = -240
⇒ x = 6
∴ 6 liters of 40% solution and 6 liters of 80% solution are needed.
Let the velocity or speed of the boat in still water is x km/hr.
And the Speed of the stream = 1km/hr
So, the speed of the boat along the stream = (x+1) km/hr.
The speed of the boat against the stream = (x-1) km/hr.
Note: time = Distance/Speed
So, [4/(x + 1)] + [4/(x - 1)] = 3 hrs.
⇒ [4 (x + 1 + x - 1)]/[(x + 1) (x - 1)] = 3
⇒ 8x = 3(x2 - 1)
⇒ 8x = 3x2 - 3
⇒ 3x2 - 8x - 3=0
⇒ 3x2 - 9x + x - 3 = 0
⇒ (x - 3) (3x + 1) = 0
Therefore x = 3 or, x = -1/3 (speed can't be -ve)
∴ Hence, the speed or velocity of the boat in still water is 3 km/hr.
First letter can be posted in 4 letter boxes in 4 ways.
Similarly the second letter can be posted in 4 letter boxes in 4 ways and so on.
Hence all the 5 letters can be posted in = 4 x 4 x 4 x 4 x 4 = 1024
Question: The ratio of a man's age to his son's age is 5 : 2, and the product of their ages is 490. What will the son's age be after 5 years?
Solution:
Let the man's age = 5x years
And, son's age = 2x years
∴ 5x × 2x = 490
⇒ 10x2 = 490
⇒ x2 = 49
⇒ x = 7
Son's age = 2 × 7 = 14 years
∴ Son's age after 5 years = 14 + 5 = 19 years
Question: What will be the difference between simple and compound interest at 5% on a sum of Tk. 8000 after 2 years?
Solution:
দেওয়া আছে,
Principal, P = 8000 টাকা
Rate of interest, r = 5%
Time, n = 2 বছর
Simple Interest (SI):
SI = (P × r × n) / 100 = (8000 × 5 × 2) / 100 = 800 টাকা
Compound Interest (CI):
CI = P × (1 + r/100)n - P
= 8000 × (1 + 5/100)2 - 8000
= 8000 × (1.05)2 - 8000
= 8000 × 1.1025 - 8000
= 8820 - 8000 = 820 টাকা
∴ Difference between CI and SI:
= 820 - 800 = 20 টাকা
Question: In a class of 92 students, 40 are taking English, 24 are taking Arabic, and 10 are taking both courses. How many students are not enrolled in either course?
Solution:
Total students = 92
Students taking English n(E) = 40
Students taking Arabic n(A) = 24
Students taking both English and Arabic = 10
We know,
n(E ∪ A) = n(E) + n(A) - n(E ∩ A)
n(E ∪ A) = 40 + 24 - 10 = 54
∴ Not enrolled = Total students - n(E ∪ A) = 92 - 54 = 38
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) cm2.
Required number of tiles
= (1517 x 902) / (41 x 41)= 814.
Numbers are in the ratio 4:5
Let the numbers be 4x and 5x
Hence, LCM = 20x
Hence, 20x = 180
Hence, x = 180/20 = 9
Hence the numbers are 36 and 45
Let cost price = x selling price = y
Then, profit = y − x
If selling price is doubled, selling price = 2y
profit = 2y − x
2y − x = 3 (y − x)
⇒ 2y − x = 3y − 3 x
⇒ y = 2x
profit = (y − x) = (2x − x) = x
∴ profit percent = (x × 100)/x = 100%
Question: Last year, Company Y earned p dollars in total profit. One-third of the profit was kept for reinvestment, and the remaining amount was divided equally among the company's 6 shareholders. In terms of p, how much did each shareholder receive?
Solution:
Here,
Company Y's profit is p dollars.
Amount kept for reinvestment = (1/3 of p)
= p/3
∴ Remaining Profit = p - p/3
= (3p - p)/3 = 2p/3
The remaining amount was divided among 6 shareholders.
∴ Each shareholder receives = (2p/3) ÷ 6
= (2p/3) × (1/6)
= p/9
Let,
A's salary = Tk. x.
Then, B's salary = Tk. (2000 - x)
According to the question,
(100 - 95)% of A = (100 - 85)% of B
⇒ (5x/100) = (15/100) × (2000 - x)
⇒ x = 1500.
Question: What is the largest four-digit number that is exactly divisible by 15, 20, 25, and 30?
Solution:
Greatest 4-digit number is 9999.
L.C.M. of 15, 20, 25 and 30 = 300.
On dividing 9999 by 300 the remainder is 99
(because 300 × 33 = 9900 and 9999 - 9900 = 99).
∴ Required number = 9999 - 99 = 9900.
Question: The sum of the two numbers is 22. Five times one number is equal to 6 times the other. The bigger of the two numbers is:
Solution:
Let,
The required number are x and y
Now
x + y = 22...........(1)
Five times one number is equal to 6 times the other,
5x = 6y
x = 6y/5..............(2)
(1)⇒
6y/5 + y = 22
(6y + 5y)/5 = 22
11y/5 = 22
y/5 = 2
y = 10
(2)⇒
x = (6 × 10)/5
x = 12
Relative speed = 5.5 - 5
= 0.5 kmph (because they walk in the same direction)
Distance = 8.5 km
Time = Distance/Speed
= 8.5/0.5
= 17 hr.
Let the profit be X% and loss be Y% . So,
Net profit or loss% = X + (-Y) + X×(-Y)/100
(Negative sign denotes that their is a loss)
Their is 10% loss and 10% profit then
∴ Net profit or loss% = 10 + (-10) + 10×(-10)/100
= 10 - 10 -100/100
= -1
∴ the net loss is 1%
'A' sells an article, which costs him Tk 400, to B at a profit of 20%.
profit of A = 400 × 20/100 = Tk 80
Cost Price for B = 400 + 80 = Tk 480
B then sells it to C, making a profit of 10% on the price he paid to A
Profit for B = 480 × 10/100 = Tk 48
Cost Price for C = 480 + 48 = Tk 528
Thus C pays Tk 528 to B.
Let the number of subjects = x
Total marks = 63x
If he had obtained 20 more marks for Geography and 2 more marks for history, his average would have been 65. That is, in this case, the total marks would have been 65x
Now we have,
65x - 63x = 20 + 2
⇒ 2x = 22
⇒ x = 11.
Question: In how many ways can the letters of the word 'ENGINEERING' be arranged such that the first letter is always 'R'?
Solution:
'ENGINEERING' শব্দটিতে মোট 11টি বর্ণ রয়েছে।
শর্ত: প্রথম স্থানে 'R' স্থির।
এখন বাকি 11 - 1 = 10টি স্থানে বাকি বর্ণগুলোকে সাজাতে হবে।
বাকি 10টি বর্ণের মধ্যে পুনরাবৃত্ত অক্ষর:
E (3 বার), N (3 বার), G (2 বার), I (2 বার)।
∴ বাকি ১০টি বর্ণের বিন্যাস সংখ্যা = 10!/(3! × 3! × 2! × 2!)
= 3,628,800/(6 × 6 × 2 × 2)
= 3,628,800/144
= 25,200
∴ প্রথম অক্ষর 'R' রেখে 'ENGINEERING' শব্দটির বিন্যাস সংখ্যা হলো 25,200.
Cost price = Tk 3000
Selling price = [{3600 × 100}/{100 + (10 × 2)}]
= Tk. 3000
Gain = 0%.
প্রশ্ন: If 5x - (5/x) = 15, then what is the value of x3 - (1/x)3?
সমাধান:
দেওয়া আছে,
5x - 5/x = 15
⇒ (5x - 5/x)/5 = 15/5
∴ x - 1/x = 3
এখন,
x3 - (1/x)3
= (x - 1/x)3 + 3 . x . (1/x)(x - 1/x)
= (x - 1/x)3 + 3(x - 1/x)
= 33 + 3 × 3
= 27 + 9
= 36
Question: If 8 workers can complete a task in 24 days, how many days will it take for 12 workers to complete the same task assuming they all work at the same rate?
Solution:
8 workers can complete work in 24 days
∴ 1 worker can complete work in = 8 × 24 days
∴ 12 workers can complete work in = (8 × 24)/12 days
= 16 days
It will take 12 workers 16 days to complete the same task.
Question: If both the length and the breadth of a rectangle are increased by 20%, what is the percentage increase in its area?
Solution:
Let the original length = x
and breadth = y
∴ Original area = x × y = xy
After 20% increase,
New length = x + 20% of x = x × (1 + 20/100)
= x × 1.2 = 1.2x
and new breadth = y × 1.2 = 1.2y
∴ New area = (1.2x) × (1.2y) = 1.44xy
∴ Increase in area = New area - Original area = 1.44xy - xy = 0.44xy
∴ Percentage increase in area = (Increase in area / Original area) × 100%
= (0.44xy/xy) × 100%
= 0.44 × 100%
= 44%
Question: A father is three times as old as his son. After 12 years, he will be twice as old as his son. Find the father’s present age.
Solution:
Let the son’s present age be x years.
Then, the father’s present age = 3x years.
After 12 years,
Son’s age = x + 12
Father’s age = 3x + 12
According to the question,
3x + 12 = 2(x + 12)
⇒ 3x + 12 = 2x + 24
⇒ 3x - 2x = 24 - 12
⇒ x = 12
∴ Father’s present age = 3 × 12 = 36 years.
Question: The area of a triangle is 216 cm2 and sides are in the ratio 3 : 4 : 5. The perimeter of the triangle is-
Solution:
32 + 42 = 52
It is a right-angled triangle.
let, the sides 3x, 4x, 5x
(1/2) × 3x × 4x = 216
⇒ 12x2 = 432
⇒ x2 = 36
⇒ x = 6
perimeter = (3 × 6) + (4 × 6) + (4 × 6)
= 72 cm
Length of the train = 150 m
Speed of the man = 2 km/hr
Relative speed = 150/3 = 50 m/s
= 50 × 18/5
= 180 km/hr
Relative speed = Speed of train - Speed of the man (as both are moving in the same direction).
Therefore,
Speed of the train = Relative speed + Speed of the man
= 180 + 2
= 182 km/hr
100 cm is read as 102 cm.
A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.
(A2 - A1) = [(102)2 - (100)2]
= (102 + 100) x (102 - 100)
= 404 cm2.
Percentage error =404/(100 x 100) x 100%= 4.04%
Question: In a particular country, one person is born every 6 seconds while one person dies every 10 seconds. Based on these birth and death rates, the net increase in population is one person after how many seconds?
Solution:
Let,
x be the number of seconds for the population to increase by one person.
We know,
Population growth = Birth rate - Death rate
ATQ,
⇒ 1 person/6 seconds - 1 person/10 seconds = 1 person/x seconds
⇒ (5 - 3) person/30 seconds = 1 person/x seconds
⇒ 2 persons/30 seconds = 1 person/x seconds
⇒ 1 person/15 seconds = 1 person/x seconds
∴ x = 15 seconds
Question: How many seconds will a 500 metre long train take to cross a man walking with a speed fo 3 km/ hr in the direction of the moving train if the speed of the train is 63 km/hr?
Solution:
Speed of the train =(63 - 3)km/hr
= 60km/hr
= (60 × 1000)/3600 m/sec
= 50/3
Time taken to pass the man = 500/(50/3) sec
= 500 × (3/50) sec
= 30 sec
Let 2nd = 3x,
therefore, 3x + 6x + 2x = 132, x = 12
so, 3x = 36
Question: A cake is divided into 24 pieces. Rahim takes 1/4 of the cake. Karim takes 1/3 of the rest. How many pieces are left?
Solution:
Given that,
A cake is divided into 24 pieces.
Now,
Rahim takes 1/4 of the cake = 24 × (1/4) = 6 pieces
So Rahim takes 6 pieces.
∴ Remaining after Rahim = 24 - 6 = 18 pieces
And
Karim takes 1/3 of the rest = 18 × (1/3) = 6 pieces
∴ Pieces left after Karim = 18 - 6 = 12 pieces
So, 12 pieces are still left.
Question: Ashik and Ruby run a race with their speed in the ratio of 5 : 3. They prefer to run on a circular track of circumference 2 km. What is the distance covered by Ashik when he passes Ruby for the sixth time?
Solution:
Since the speeds of Ashik and Ruby are in the ratio 5 : 3 i.e., when Ashik covers 5 rounds, then Ruby covers 3 rounds
∴ Relative speed = 5 – 3 = 2 parts
Now, the first time Ashik and Ruby meet, when Ashik completes (5/2 = 2.5) rounds, and Ruby completes 1/2 round.
∴ Ashik to pass Ruby for the sixth time, Ashik would have completed = (6 × 2.5) rounds
= 15 rounds
Since each round is 2 km,
Hence, the distance covered by Ashik = (15 × 2) km
= 30 km
Let x be Sumon's age, then Akib's age will be 2x
After 5 years their ages will be (x + 5) and (2x + 5) respectively.
Given that the ratio(after 5 Years) is = 6:11
According to the question,
6/11 = (x + 5)/(2x + 5)
⇒ 6(2x + 5) = 11(x + 5)
⇒ 12x + 30 = 11x + 55
⇒ x = 55 - 30
= 25
And 2x = 50
Hence the ages of Sumon and Akib will be 25 and 50.
Question: What is the smallest number divisible by 3, 5 and 9 with remainder 2?
Solution:
প্রদত্ত সংখ্যাগুলো দ্বারা বিভাজ্য ক্ষুদ্রতম সংখ্যা হবে সংখ্যাগুলোর ল. সা. গু।
তাহলে, ৩, ৫, ৯ এর ল. সা. গু এর সাথে ২ যোগ করলে ক্ষুদ্রতম সংখ্যাটি পাওয়া যাবে।
এখন,
৩ = ৩ × ১
৫ = ৫ × ১
৯ = ৩ × ৩
∴ ৩, ৫, ৯ এর ল. সা. গু = ৩ × ৩ × ৫ = ৪৫
নির্ণেয় ক্ষুদ্রতম সংখ্যা = (৪৫ + ২) = ৪৭
Given,
H.C.F. = 27
L.C.M. = 2079
one number = 189
Let another number be y
We know,
Product of numbers = L.C.M. × H.C.F.
∴ 189 x y = 27 × 2079
y = 297.