উত্তর
ব্যাখ্যা
Solution:
মনেকরি,
আসাদের ছিল = x টাকা
10টি কমলা কিনলে প্রতিটি কমলার দাম = x/10 টাকা
প্রশ্নমতে,
(x/10) - (x/12) = 3
(6x - 5x)/60 = 3
x/60 = 3
x = 180
আসাদের ছিল = 180 টাকা
PrepBank · বিষয়ভিত্তিক প্রশ্ন
PrepBank · পাতা ১৬ / ১৬১ · ১,৫০১–১,৬০০ / ১৬,১২৪
Question: A cricket team has a ratio of win to loss 4 : 3. After losing 5 games in a row, the team's ratio of win to loss became 9 : 8. How many games had the team loss before it played the last five games?
Solution:
মনে করি,
দলটির জেতা খেলার সংখ্যা ছিল 4p
দলটির হারা খেলার সংখ্যা ছিল 3p
পরপর 5 টি খেলা হারার পর,
জেতা খেলার সংখ্যা 4p
হারা খেলার নতুন সংখ্যা (3p + 5)
প্রশ্নমতে,
4p : (3p + 5) = 9 : 8
⇒ 4p/(3p + 5) = 9/8
⇒ 32p = 27p + 45
⇒ 32p - 27p = 45
⇒ 5p = 45
⇒ p = 45/5
⇒ p = 9
∴ p = 9
∴ ১ম অবস্থায় হারা খেলার সংখ্যা ছিল = 3 × 9 = 27
অতএব, শেষ 5 টি খেলা খেলার আগে দলটি 27 খেলায় হেরেছিল।
Question: If the average of m numbers is n2 and the average of n numbers is m2, find the average of all (m + n) numbers.
Solution:
Given that,
The average of m numbers is n2
Sum of m numbers = m⋅n2
And
The average of n numbers is m2
Sum of n numbers = n⋅m2
∴ Total sum = mn2 + nm2 = mn(m + n)
∴ Average = mn(m + n)/(m + n) = mn
Original ratio of the mixture 3:1
Taking out the mixture actually means just taking out the wine because the water anyways is going to be added back.
If we remove 1 part of wine, it makes the ratio 2:2 (1 part water is added to keep the volume constant )
so, what we have actually done is remove 1 part wine from 3 part Wine. i.e. 1/3.
So, 1/3 mixture drawn.
Question: The present age of a father is four times the age of his daughter. After 5 years, the ratio of their ages will be 3 : 1. What is the present age of the father?
Solution:
Let the daughter’s present age be x years.
Then father’s present age = 4x years.
After 5 years,
∴ (4x + 5)/(x + 5) = 3/1
⇒ 1(4x + 5) = 3(x + 5)
⇒ 4x + 5 = 3x + 15
⇒ 4x - 3x = 15 - 5
⇒ x = 10
∴ Present age of the father = 4x years
= 4 × 10
= 40 years
Question: The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:
Solution:
Let, the two numbers be 23 x and 23 y.
Since the other two factors of LCM are 13 and 14, the values of x and y are 13 and 14, respectively.
So, the largest number is 23y,
23y = 23 × 14 = 322
Question: If P : 6 = Q : 8 = R : 10, then (P + Q + R)/P =?
Solution:
P : 6 = Q : 8
or, P/6 = Q/8
or, 6Q = 8P
or, Q = 8P/6
or, Q = 4P/3
P : 6 = R : 10
or, P/6 = R/10
or, 6R = 10P
or, R = 10P/6
or, R = 5P/3
∴ (P + Q + R)
= P + (4P/3) + (5P/3)
= (3P + 4P + 5P)/3
= 12P/3
= 4P
∴ (P + Q + R)/P
= 4P/P
= 4
Let, the first and 2nd worker need X days.
Third worker needs 2X days
ATQ, 1/X + 1/X + 1/2x = 1/12
or, (2 + 2 + 1)/2x = 1/12
or, x = 30
Question: In a bag, there are 5 red, 3 green, and 2 blue balls. If two balls are drawn one after the other without replacement, what is the probability that the first one is green and the second one is blue?
Solution:
মোট বলের সংখ্যা = 5 (লাল) + 3 (সবুজ) + 2 (নীল) = 10টি
প্রথম বলটি সবুজ হওয়ার সম্ভাবনা = 3/10
প্রথম বল তোলার পর বাক্সে বলের সংখ্যা = 10 - 1 = 9
দ্বিতীয় বলটি নীল হওয়ার সম্ভাবনা = 2/9
সুতরাং, প্রথমটি সবুজ ও দ্বিতীয়টি নীল হওয়ার সম্ভাবনা = (3/10) × (2/9)
= 6/90
= 1/15
Question: Silver is 12 times as heavy as water, and lead is 8 times as heavy as water. In what ratio should these be mixed to get an alloy 9 times as heavy as water?
Solution:
Let silver be 12x times as heavy and lead 8y times as heavy as water.
12x + 8y = 9(x + y)
⇒ 12x + 8y = 9x + 9y
⇒ 12x - 9x = 9y - 8y
⇒ 3x = y
∴ x/y = 1/3 = 1 : 3
Question: An accurate clock shows 3:20 PM. How many degrees will the hour hand rotate from 3:20 PM to 11:50 PM on the same day?
Solution:
Given that,
From 3 : 20 PM to 11 : 20 PM = 8 hours
And from 11 : 20 PM to 11 : 50 PM = 30 minutes
∴ Total time = 8 hours 30 minutes
Now,
30 minutes = 30/60 = 0.5 hours
∴ Total time = 8 + 0.5 = 8.5 hours
We know,
The hour hand moves 360° in 12 hours.
∴ Speed of hour hand = 360°/12 = 30° per hour
∴ Degrees rotated by hour hand = 8.5 × 30° = 255°
So the hour hand will rotate 255°.
আমরা জানি,
Fibonacci সংখ্যা = 0, 1, 1, 2, 3, 5, 8, 13, 21 ... পরপর দুটি সংখ্যার যােগফল পরবর্তী সংখ্যার সমান।
সুতরাং, এই ধারার পরবর্তী সংখ্যা হবে = 21 + 13 = 34
Simple interest, I = pnr = 5000 × 5 × 10/100
= 2500 taka
Compound interest = Amount − Principal
Amount = 5000(1 + 10/100)5 = 8052.55
So, compound interest = 8052.55 - 5000 = 3052.55
∴ Difference = 3052.55 - 2500 = 552.55 ≅ 552 taka
Question: Karim can complete 2/5th of a certain work in 4 hours. Rahim works three times as fast as Karim and finishes the remaining work. How many hours did Rahim work?
Solution:
ধরি, সম্পূর্ণ কাজ = 1 অংশ
করিমের কাজের পরিমাণ = 2/5 অংশ
সময় = 4 ঘণ্টা
∴ পুরো কাজ (1 অংশ) করতে করিমের সময় লাগবে = 4 ÷ (2/5)
= 4 × 5/2
= 10 ঘণ্টা।
এখন, রহিম যেহেতু করিমের চেয়ে তিনগুণ দ্রুত কাজ করেন, তাই পুরো কাজটি সম্পন্ন করতে তার এক-তৃতীয়াংশ সময় লাগবে।
∴ পুরো কাজ করতে রহিমের সময় = 10 ÷ 3 = 10/3 ঘণ্টা।
বাকি কাজের পরিমাণ = 1 - (2/5) = 3/5 অংশ।
সুতরাং, রহিমের 3/5 অংশ কাজ করতে সময় লাগবে = (10/3) × (3/5) ঘণ্টা
= (10 × 3)/(3 × 5)
= 30/15
= 2 ঘণ্টা।
ধরি,
ক্ষুদ্রতর সংখ্যাটি 3x এবং বৃহত্তর সংখ্যাটি 4x
প্রশ্নমতে,
3x + 4x = 630
⇒ 7x = 630
⇒ x = 630/7
⇒ x = 90
অতএব, ক্ষুদ্রতর সংখ্যাটি = 3 × 90
= 270.
Answer: 270.
Question: An observer 1.6 m tall stands 20 meters away from a tree. The angle of elevation from his eye to the top of the tree is 45°. What is the height of the tree?
Solution:
মনে করি,
গাছটির উচ্চতা AB। পর্যবেক্ষকের চোখ C বিন্দুতে আছে এবং তার উচ্চতা CD = 1.6 m
পর্যবেক্ষক থেকে গাছটির দূরত্ব BD = 20 m
এখানে, A, C এবং E বিন্দু দ্বারা গঠিত ACE হলো একটি সমকোণী ত্রিভুজ, যার ∠C = 45°।
আমরা জানি,
tan θ = লম্ব/ভূমি
এখানে, লম্ব = AE এবং ভূমি = CE
∴ tan 45° = AE/20
∴ 1 = AE/20
∴ AE = 20 মিটার
গাছটির মোট উচ্চতা, AB = AE + EB
= 20 + 1.6
= 21.6 মিটার
সুতরাং, গাছটির উচ্চতা হলো 21.6 মিটার।
Two successive discount is equivalent
= 20+5− 20×5/100
= 25−1 = 24%
Question: In an isosceles triangle, each of the equal sides is 16 cm long and the included angle between the equal sides is 30°. What is the area of the triangle?
Solution:
Given that,
The included angle between the equal sides, θ = 30°
Each of the equal sides of the isosceles triangle, a = b = 16 cm
We know that,
Area of the triangle = (1/2) × a × b × sin θ
= (1/2) × 16 × 16 × sin 30°
= (1/2) × 16 × 16 × (1/2)
= 8 × 8
= 64 square cm
∴ The area of the triangle is 64 cm2.
Question: A clock gains (moves ahead) 10 minutes each day. How many days will it take to reach a point where the clock will indicate the correct time?
Solution:
একটি ঘড়িকে পুনরায় সঠিক সময় দেখাতে হলে তাকে 12 ঘণ্টা সময় এগিয়ে যেতে হবে।
কারণ একটি 12 ঘণ্টার ঘড়িতে যখন সঠিক সময় থেকে 12 ঘণ্টা এগিয়ে যাবে, তখন এটি আবার সঠিক সময় নির্দেশ করবে।
12 ঘণ্টা = 12 × 60 মিনিট = 720 মিনিট
এখন, যেহেতু ঘড়িটি প্রতিদিন 10 মিনিট করে সময় এগিয়ে যায়,
10 মিনিট সময় এগিয়ে যায় 1 দিনে
∴ 720 মিনিট সময় এগিয়ে যাবে = (1/10) × 720 দিনে
= 72 দিনে
সুতরাং, 72 দিন পর ঘড়িটি আবার সঠিক সময় দেখাবে।
The LCM of 12, 18, 21, 30 is 1260.
So, the number is 1260/2 = 630
Let the marked price = 100x
Shop Keeper gives 5% discount, therefore, Price becomes = 95x
Again if shopkeeper gives 6% discount then the price become = 94x
According to the question if he gives 6% discount his earning will Tk.15 less
∴ 95x - 94x = 15
⇒ x = 15
∴ Marked price = 100 × 15 = Tk. 1500
Let x be the market value,
we don't know face value so consider 100.
6% of 100 = 8% of x.
(6/100) × 100 = (8/100) × x.
6 = 8x/100.
x = 600/8.
x = 75.
Alternative Solution:
For an income of Tk. 8, investment = Tk. 100.
For an income of Tk. 6, investment = Tk.(100/8 × 6) = Tk. 75
Market value of Tk. 100 stock = Tk. 75.
Here, n(S) = 52
There are 26 red cards (including 2 kings) and there are 2 more kings.
Let E = event of getting a red card or a king.
Then, n(E) = 28
∴P(E)=n(E)/n(S)
=28/52
=7/13
The present age of Tomal = 5
Present age of Razib = 5 - 2 = 3
Let present age of Akib = x
Then, present age of Razib = (x - 6)/18
According to the question,
(x - 6)/18 = 3
x - 6 = 54
x = 54 + 6
x = 60 years.
Question: How much water be mixed in 45 litre of milk worth Tk. 6.40 per litre, so that value of mixture is Tk. 4.80 per litre?
Solution:
মনে করি, x লিটার পানি মেশাতে হবে।
মিশ্রণের মোট পরিমাণ = (45 + x) লিটার
45 লিটার দুধের দাম = 45 × 6.40 = 288 টাকা
পানির দাম = 0 টাকা
প্রশ্নমতে, মিশ্রণের মোট দাম = (45 + x) × 4.80
যেহেতু পানি বিনামূল্যে পাওয়া যায়, তাই মোট দাম অপরিবর্তিত থাকবে:
288 = (45 + x) × 4.80
⇒ 288/4.80 = 45 + x [উভয় পক্ষকে 4.80 দ্বারা ভাগ করে পাই]
⇒ 60 = 45 + x
⇒ x = 60 - 45
⇒ x = 15 litres
∴ 15 লিটার পানি মেশাতে হবে।
Given expression :
= (10.3)3+13 / (10.3)2−(10.3×1)+12
= (a3+b3 / a2−ab+b2)
=(a+b)
=(10.3+1)
=11.3
Question: A man spends 75% of his income. If his income increases by 25% and expenditure increases by 15%, find the percentage increase in his savings.
Solution:
Let,
Original income = 100 Taka
Original expenditure = 75% of 100 = 75 Taka
Original savings = Income - Expenditure = 100 - 75 = 25 Taka
After increase,
New income = 100 + 25% of 100 = 100 + 25 = 125 Taka
New expenditure = 75 + 15% of 75 = 75 + 11.25 = 86.25 Taka
New savings = 125 - 86.25 = 38.75 Taka
Percentage increase = [(New savings - Original savings) / Original savings] × 100
= [(38.75 - 25) / 25] × 100
= [13.75/ 25] × 100
= 0.55 × 100
= 55%
∴ Saving increased = 55%
Area or outer space = 2a x 2a = 4a2
From ABCD rectangle, In ΔBAD,
BD2 = (AD)2 + (AB)2
⇒ (2a)2 = x2 + x2
⇒ 4a2 = 2x2
⇒ 2a2 = x2
∴ x = √2a
Area of inner square = √2a × √2a = 2a2
∴ The difference between the areas of outer and inner squares is = 4a2 - 2a2 = 2a2
Question: If m/n = 1/4, then the value of (m2 + n2)/(m2 - n2) is-
Solution:
Given that,
m/n = 1/4
Now,
(m/n) = (1/4)
⇒ (m/n)2 = (1/4)2
⇒ m2/n2 = 1/16
∴ (m2 + n2)/(m2 - n2) = (1 + 16)/(1 - 16); [যোজন-বিয়োজন]
= 17/(- 15)
= - 17/15
Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 × 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 × (150 + P)
120 + 4P = 150 + P
=> P = 10 liters.
Question: A biker travels at 60 km/h. If instead, he had traveled at 80 km/h for the same duration, he would have covered 100 km more. How far did he actually travel?
Solution:
Let, the actual distance travelled be x km.
Then,
x/60 = (x + 100)/80
⇒ x/6 = (x + 100)/8
⇒ 6(x + 100) = 8x
⇒ 6x + 600 = 8x
⇒ 8x - 6x = 600
⇒ 2x = 600
⇒ x = 600/2
⇒ x = 300 km
Question: If 5 workers can collect 75 kg wheat in 3 days, how many kilograms of wheat will 8 workers collect in 5 days ?
Solution:
5 workers 3 days collection = 75 kg
1 worker 1 day collection = (75/15) kg
8 workers 5 days collection = (75 × 40)/15 kg
= 200 kg
∴ 8 workers will collect 200 kg in 5 days.
Question: A trader sets his products 50% above cost price and gives a discount of 20%. Find his profit percent.
Solution:
Let the cost price (CP) = Tk. 100
Marked Price (MP)
MP = CP + 50% of CP
= 100 + 50
= 150
Selling Price (SP) after discount:
SP = MP - 20% of MP
= 150 - 30
= 120
Profit = SP - CP
= 120 - 100
= 20
Profit percent:
Profit % = (Profit/CP) × 100
= (20/100) × 100
= 20%
∴ Profit = 20%
LCM of 6, 9, 15 and 18 = 90
Required Number = (90k + 4) which is a multiple of 7
Put k = 1. We get numbers as (90 × 1) + 4 = 94. But this is not a multiple of 7
Put k = 2. We get numbers as (90 × 2) + 4 = 184. But this is not a multiple of 7
Put k = 3. We get numbers as (90 × 3) + 4 = 274. But this is not a multiple of 7
Put k = 4. We get numbers as (90 × 4) + 4 = 364. This is a multiple of 7
Hence 364 is the answer.
Question: The sum of three consecutive multiples of 4 is 312. Find the largest number.
Solution:
Let,
First multiple = 4x
Second multiple = 4(x + 1) = 4x + 4
Third multiple = 4(x + 2) = 4x + 8
According to the question,
4x + (4x + 4) + (4x + 8) = 312
⇒ 12x + 12 = 312
⇒ 12x = 300
⇒ x = 25
∴ The largest number = 4x + 8
= 4 × 25 + 8
= 108
Question:
Solution:
শেষের মিনিটে সে slip করবে না, অর্থাৎ 54 মিটার উঠার পর 6 মিটার উঠে গেলে সে আর নিচে নামবে না।
তাই এখন দেখি এই 54 মিটার সে কত মিনিটে উঠে।
প্রতি 2 মিনিটে বানরটি উঠে = 6 - 3 = 3 মিটার।
অর্থাৎ 3 মিটার উঠে = 2 মিনিটে
∴ 54 মিটার উঠে = (2 × 54)/3
= 36 মিনিটে
∴ খুটি বেয়ে উঠতে সময় লাগবে = 36 + 1 = 37 মিনিট
সমাধান:
মোট খরচ = নির্দিষ্ট (বরাদ্দকৃত) টাকা + প্রতি পেন্সিলের অতিরিক্ত মূল্য × পেন্সিলের সংখ্যা
এখানে,
নির্দিষ্ট টাকা = ৫০০ টাকা
মোট পেন্সিল = ১২০০ টি
মোট প্রদানকৃত টাকা = ৪৭০০ টাকা
প্রতি পেন্সিলের অতিরিক্ত মূল্য = X টাকা
সুতরাং সমীকরণ,
৪৭০০ = ৫০০ + ১২০০X
বা। ৪৭০০ − ৫০০ = ১২০০X
বা, ৪২০০ = ১২০০X
বা, X = ৪২০০ ÷ ১২০০
বা, X = ৪২ ÷ ১২
∴ X = ৩.৫
সুতরাং, প্রতিটি অতিরিক্ত পেন্সিলের জন্য মূল্য X = ৩.৫ টাকা
Question: The height of a cylinder is four times its radius. If the cylinder’s volume is 32π cm3, what is the radius of the cylinder?
Solution:
ধরি,
সিলিন্ডারের ব্যাসার্ধ = r সেমি
∴ সিলিন্ডারের উচ্চতা = 4r সেমি
আমরা জানি,
সিলিন্ডারের আয়তন = πr2h ঘন সেমি
প্রশ্নমতে,
πr2h = 32π
⇒ πr2 × 4r = 32π
⇒ 4πr3 = 32π
⇒ 4r3 = 32
⇒ r3 = 32/4
⇒ r3 = 8
⇒ r = 2
Median is the middle element or the mean of two middle elements in a numerical data set with the elements ordered by their value.
The mode is the value in a set of data that has the most occurrences.
The mode is not unique and a data set may have more than one mode of no mode as well
Given set of numbers are 10, 70, 20, 40, 70, 90
Arrange in order: 10, 20, 40, 70, 70, 90
So, Median M = ( 40 + 70)/2 = 55
and, Mode m = 70
∴ average of M and m = (55 + 70)/2 = 62.5
Question: A committee of 3 members is to be selected out of 3 men and 2 women. What is the probability that the committee has at least one woman?
Solution:
Total member = 3 + 2 = 5
Committee can be form with at least 1 one woman:
1 woman, 2 men : 2C1 × 3C2 = 2 × 3 = 6
2 women, 1 man: 2C2 × 3C1 = 1 × 3 = 3
∴ The total number of ways to make committe with at least 1 one woman: 6 + 3 = 9
The total number of ways to make committe with all members = 5C3 = 10
∴ The probability that the committee has at least woman = 9/10
Question: Find out the missing number : 52, 64, 76, ____ , 100
Solution:
52 + 12 = 64
64 + 12 = 76
76 + 12 = 88
88 + 12 = 100