উত্তর
ব্যাখ্যা
প্রশ্নমতে, x+x+10+x+20+x+30 = x+40+x+50+x+60
বা,4x + 60 = 3x + 150
বা, x = 90
PrepBank · বিষয়ভিত্তিক প্রশ্ন
PrepBank · পাতা ৬ / ১১ · ৫০১–৬০০ / ১,০৭৬
In the 1st case,
1/9 part of the tank is emptied in 1 min
In the 2nd case,
1/6 part of the tank is emptied in 1 min
So, together in 1 min, they empties = (1/9 + 1/6) = 5/18 part
Now, 5/18 part is emptied in 1 minute
∴ 1 or, total part is emptied in = 18/5 = 3.6 minutes
We know,
M1D1T1W2 = M2D2T2W1 [Men = M; Days = D; Time/Hours = T; Work = W]
1 child binds half the number of books bound by 1 adult
∴ 1 adult = 2 children
Take work done = 1
∴ (20 adults + 16 children) x 10 days x 1 = (8 adults + 12 children) x ? days x 1
∴ 56 children x 10 days x 1 = 28 children x ? days x 1 [Convert either all adults to children or all children to adults.]
∴ ? = 20 days = they will need these many days.
40 ঘন্টার জন্য regular pay = (30 × 40) = 1200 টাকা।
Overtime এর টাকার পরিমান = (1680 - 1200) টাকা = 480 টাকা
যেহেতু, Overtime এর প্রতিদিনের টাকার পরিমান Regular Payment এর দ্বিগুন,
সেহেতু মোট overtime কাজ করার সময় = (480 ÷ (30×2) ঘন্টা = 8 ঘন্টা
Given that,
3 pumps, working 4 hours a day, can empty a tank in 2 days.
Therefore, it means that:
3 pumps take a total of 8 hours to empty the tank.
Hence, 1 pump will take 8 × 3 = 24 hours
As the number of pumps decreases, the time required increases.
So, if 4 pumps work, the time required decreases.
∴ 24/4 = 6 hours needed to empty the tank in 1 day.
Question: If Machine A can produce 500 units in 3 hours and Machine B can produce 500 units in 6 hours, in how many hours can Machines A and B, working together at these constant rates, produce 500 units?
Solution:
মেশিন A, 3 ঘণ্টায় তৈরি করে ৫০০টি ইউনিট।
∴ 1 ঘণ্টায় মেশিন A তৈরি করে = 500/3 ইউনিট
মেশিন B, 6 ঘণ্টায় তৈরি করে ৫০০টি ইউনিট।
∴ 1 ঘণ্টায় মেশিন B তৈরি করে = 500/6 ইউনিট
তারা একত্রে ১ ঘণ্টায় তৈরি করে = (500/3) + (500/6) ইউনিট
= (1000 + 500)/6
= 1500/6 = 250 ইউনিট
তারা একত্রে 250টি ইউনিট তৈরি করে 1 ঘণ্টায়।
∴ তারা একত্রে 500টি ইউনিট তৈরি করতে সময় নেবে = 500/250 = 2 ঘণ্টা
Question: Working alone, Rasel can complete a certain kind of job in 8 hours. Rasel and Shima working together at their respective rates, can complete one of these jobs in 6 hours. In how many hours can Shima working alone, complete one of these jobs?
Solution:
Working together Rasel and Shima can complete the job in 6 hours
which means
(1/Rasel) + (1/Shima) = (1/6)
⇒ (1/8) + (1/Shima) = (1/6) [Rasel can complete the job in 8 hours]
⇒ (1/Shima) = (1/6) - (1/8)
⇒ (1/Shima) = (4 - 3)/24
∴ (1/Shima) = 1/24
so, Shima working alone can complete the job in 24 hours
Question: Karim does a job 60 days quicker than Asad. If Karim works three times faster than Asad, how long will it take him to finish the job by himself?
Solution:
ধরি,
কাজটি আসাদ করে = x দিনে
করিম করে = (x - 60) দিনে
প্রশ্নমতে,
x - 60 = 3x
⇒ 3x - x = 60
⇒ 2x = 60
⇒ x = 60/2
⇒ x = 30
Question: If 5 identical machines, operating at a constant speed, can manufacture 200 pencils in one minute, how many pencils will 12 such machines produce in 10 minutes at the same rate?
Solution:
Given,
In 1 minute, 5 machines can produce 200 pencils
In 1 minute, 1 machine can produce 200/5 = 40 pencils
So, in 10 minutes, 12 machines can produce = (40 × 12 × 10) pencils
= 4800 pencils
Question: In a factory, 20 workers can make 20 toys in 10 days working 10 hours per day. Then, in how many days can 25 workers make 30 toys working 20 hours per day?
Solution:
Given:
Number of workers initially = 20
Number of days initially = 10
Hours per day initially = 10
Number of toys initially = 20
Number of workers later = 25
Hours per day later = 20
Number of toys later = 30
Number of days later = ?
∴ (Number of workers initially × Number of days initially × Hours per day initially × Number of toys later)
= (Number of workers later × Number of days later × Hours per day later × Number of toys initially)
⇒ 20 × 10 × 10 × 30 = 25 × (Number of days later) × 20 × 20
⇒ 20 × 10 = 200 → 200 × 10 = 2,000 → 2,000 × 30 = 60,000
⇒ 25 × 20 × 20 = 10,000 × (Number of days later)
⇒ 60,000 = 10,000 × (Number of days later)
∴ Number of days later = 60,000 ÷ 10,000 = 6 days
Question: Mr. Rahim can complete a task in 12 days, while his daughter can complete the same task in 18 days. How many days will it take for them to finish the work if they work together?
Solution:
Given,
Mr. Rahim can do the work in 12 days
∴ in 1 day he can do = 1/12 part
His daughter can do the work in 18 days
∴ in 1 day she can do = 1/18 part
∴ in 1 day, working together they can do = (1/12 + 1/18) part
= (3 + 2)/36 part
= 5/36 part
Hence, together they complete 5/36 of the work in 1 day
∴ They can complete the whole work in = 36/5 days
= 7.2 days
∴ If they work together, the work will be completed in 7.2 days.
Question: If 3 men or 9 boys can finish a task in 36 days, how long will it take 9 men and 9 boys to finish the same task?
Solution:
এখানে, 3 জন পুরুষ = 9 জন বালক
∴ 1 জন পুরুষ = 9/3 = 3 জন বালক
এখন, 9 জন পুরুষ + 9 জন বালক
= (9 × 3) জন বালক + 9 জন বালক
= 27 জন বালক + 9 জন বালক
= 36 জন বালক
প্রশ্নমতে,
9 জন বালক কাজটি করে 36 দিনে
∴ 1 জন বালক কাজটি করে (36 × 9) দিনে
∴ 36 জন বালক কাজটি করে (36 × 9)/36 দিনে
= 9 দিনে
∴ কাজটি 9 দিনে শেষ হবে।
1-minute work done by both the punctures = (1/9) + (1/6)
= (4 + 6)/36
= 10/36
= 5/18
So both punctures will make the type flat in = (18/5) min
= 3(3/5) min
x adults = 2x children
to complete in d days 2x children is required.
∴ to complete in (d + 2) days (2x × d)/(d + 2) children is required.
April has 30 days. So Protik takes 30 days to build the pavement.
Mahmud is 25% faster than Protik
25% = 25/100 = .25
This means, if Protik is 1, then Mahmud is (1 + 0.25) = 1.25
Protik takes 30 days to do the work.
Mahmud will take = 30/1.25 = 24 days to get the work done.
Work is done by 10 men in 1 day = 1/7
Work is done by 1 man in 1 day = (1/7)/10 = 1/70
Work is done by 10 women in 1 day = 1/14
Work is done by 1 woman in 1 day = 1/140
Work done by 5 men and 10 women in 1 day = 5 × (1/70) + 10 × (1/140)
= 5/70 + 10/140 = 1/7
∴ 5 men and 10 women can complete the work in 7 days.
A's share : B's share = Ratio of their 1 day's work
= 1/8 : 1/12
= 3 : 2.
∴ B's share = Tk. 200 × (2/5)
= Tk. 80.
Question: Sakib can paint 10 desks in 20 minutes. Tamim can paint the same number of desks in only 10 minutes. Sakib paints the first 5 desks, then Tamim paints for 3 minutes, and finally Sakib finishes the remaining desks. How long will it take them to paint 15 desks in total?
Solution:
তামিম 10 মিনিটে রঙ করে 10টি ডেস্ক।
∴ 3 মিনিটে সে রঙ করতে পারে = (10 × 3)/10
= 3টি ডেস্ক
সাকিব প্রথমে রঙ করে 5টি ডেস্ক।
∴ এপর্যন্ত মোট সম্পন্ন কাজ = 5 (সাকিব) + 3 (তামিম) = 8টি ডেস্ক
বাকি থাকে = 15 - 8 = 7টি ডেস্ক
সাকিব 10টি ডেস্ক রঙ করতে সময় নেয় 20 মিনিট।
∴ সাকিবের প্রথম 5টি ডেস্ক রঙ করতে সময় লেগেছে = (20 × 5)/10 = 10 মিনিট
∴ সাকিবের অবশিষ্ট 7টি ডেস্ক রঙ করতে সময় লাগবে = (20 × 7)/10 = 14 মিনিট
∴ মোট সময় = 10 (সাকিব) + 3 (তামিম) + 14 (সাকিব) = 27 মিনিট।
In a days P does 1/20 work; And in 1 day Q does 1/25 work
As seen above, Q works alone for 10 days.
In 1 days Q completes (1/25) × 10 = 2/5 work
Remaining work = 1 - (2/5) = 3/5 = Done by P and Q together
Total Work done = Total days x Work done by all in 1 day
Let P and Q work together for total K days.
∴ 3/5 = K × (1/20 + 1/25)
K = 20/3 = 6(2/3) days = Days when P and Q worked together
Thus P leaves after 6(2/3) days.
Question: Sumon and Noyon can complete a task together in 6 days. Noyon alone can do it in 9 days. How many days will Sumon take to complete the task alone?
Solution:
ধরা যাক, সুমন একা কাজটি করতে x দিন সময় নেয়।
∴ সুমনের 1 দিনের কাজ = 1/x অংশ
∴ নয়নের 1 দিনের কাজ = 1/9 অংশ (যেহেতু সে একা ৯ দিনে করে)
তারা দুজনে মিলে 6 দিনে কাজটি শেষ করে।
∴ তাদের একত্রে 1 দিনের কাজ = 1/6 অংশ
শর্তমতে,
(1/x) + (1/9) = 1/6
⇒ 1/x = (1/6) - (1/9)
⇒ 1/x = (3 - 2)/18
⇒ 1/x = 1/18
⇒ x = 18
∴ সুমন একা কাজটি করতে 18 দিন সময় নেবে।
Question: A barrack has enough food for 200 soldiers or 400 sailors. If 120 sailors have taken the food, how many soldiers will be able to eat with the remaining food?
Solution:
এখানে,
400 জন নাবিকের খাবার = 200 জন সৈন্যের খাবার।
মোট নাবিক যাদের জন্য খাবার ছিল = 400 জন।
খাবার গ্রহণ করেছে = 120 জন।
অবশিষ্ট খাবার = (400 - 120) জন নাবিকের খাবার
= 280 জন নাবিকের খাবার।
এখন,
400 জন নাবিকের খাবার = 200 জন সৈন্যের খাবার।
∴ 1 জন নাবিকের খাবার = (200/400) জন সৈন্যের খাবার।
∴ 280 জন নাবিকের খাবার = (200 × 280)/400
= (1/2) × 280
= 140 জন সৈন্যের খাবার।
সুতরাং, অবশিষ্ট খাবার দিয়ে 140 জন সৈন্যকে দেওয়া যাবে।
Question: A can complete a work in 20 days, while B can complete the same work in 30 days. If both A and B work together, in how many days will they complete the entire work?
Solution:
A's 1 day work = 1/20
B's 1 day work = 1/30
Together 1 day work = 1/20 + 1/30
= (3 + 2)/60 = 5/60 = 1/12
∴ Total time = 1/Combined work rate
= 1/(1/12) days
= 12 days
Question: If A can do 1/4 of a work in 3 days and B can do 1/9 of the same work in 4 days, how much will A get if both work together and paid Tk 800 in all?
Solution:
Whole work is done by A in (3 × 4) = 12 days
∴ A's 1 day's work = 1/12 part
Whole work is done by B in (4 × 9) = 36 days
∴ B's 1 day's work = 1/36 part
A's 1 day's work : B's 1 day's work
= A's wages : B's wages
= 1/12 : 1/36
= 3 : 1
∴ A's share = (800 × 3/4) Tk
= 600 Tk
Question: A worker earns Tk. 500 on the first day and spends Tk. 200 on the second day, earns Tk. 500 on the third day and again spends Tk. 200 on the fourth day, and so on. On which day would he have had Tk. 2000?
Solution:
1ম দিনে আয় = 500 টাকা
2য় দিনে ব্যয় = 200 টাকা
∴ প্রতি 2 দিনে প্রকৃত জমা হয় = (500 - 200) = 300 টাকা
শেষ দিনে আয় করার পর কাঙ্ক্ষিত লক্ষ্যে পৌঁছাবে, তাই শেষ দিনের আয় বাদ দিলে থাকে = (2000 - 500) = 1500 টাকা
এখন, 300 টাকা জমা হয় = 2 দিনে
∴ 1500 টাকা জমা হয় = (2 × 1500) / 300 = 10 দিনে
অর্থাৎ, 10 দিনের শেষে তার হাতে জমা থাকবে 1500 টাকা।
পরের দিন অর্থাৎ 11-তম দিনে তিনি আবার 500 টাকা আয় করবেন।
∴ মোট সঞ্চয় হবে = 1500 + 500 = 2000 টাকা
∴ 11-তম দিনে তার কাছে মোট 2000 টাকা থাকবে।
Question: To complete a work, P takes 25% more time than Q. If together they take 20 days to complete the work, how much time will Q take to do it?
Solution:
Let,
Q takes x days to complete the work
Then P will take 25% more time
i.e. 125% of x days
i.e. (5/4)x days
So, the one day’s work of P and Q together will be
(1/x) + {1/(5x/4)} = 1/20
⇒ (1/x) + (4/5x) = 1/20
⇒ (9/5x) = 1/20
⇒ x = 36
∴ Q takes 36 days to complete the work.
Question: A can finish a task in 36 days, B in 54 days, and C in 72 days. All three start working together, but A leaves 8 days before the work is completed, and B leaves 12 days before completion. C works alone until the task is finished. How many days does it take to complete the work?
Solution:
Let the work be completed in y days.
C works for y days
Therefore, A works for (y - 8) days
and, B works for (y - 12) days.
According to the question,
{(y - 8)/36} + {(y - 12)/54} + (y/72) = 1
⇒ {6(y - 8) + 4 (y - 12) + 3y}/216 = 1
⇒ 6(y - 8) + 4 (y - 12) + 3y = 216
⇒ 6y - 48 + 4y - 48 + 3y = 216
⇒ 13y = 216 + 96 = 312
⇒ y = 312/13
∴ y = 24
Question: A can complete a piece of work in 36 days, B in 54 days and C in 72 days. All the three began the work the work together but A left 8 days before the completion of the work and B, 12 days before the completion of work. Only C worked up to the end. In how many days was the work completed?
Solution:
Let,
the work be completed in y days. So C works for y days
Therefore, A works for (y - 8) days B works for (y - 12) days.
ATQ,
{(y - 8)/36} + {(y - 12)/54} + (y/72) = 1
⇒ {6(y - 8) + 4(y - 12) + 3y}/216 = 1
⇒ 6y - 48 + 4y - 48 + 3y = 216
⇒ 13y = 216 + 96
⇒ 13y = 312
⇒ y = 312/13
∴ y = 24
Question: Machine P prints x units in 20 minutes and machine Q prints 2x units in 10 minutes. In how many minutes will P and Q, working together, print 100x units?
Solution:
Machine P প্রতি মিনিটে প্রিন্ট করে = x/20 ইউনিট
Machine Q প্রতি মিনিটে প্রিন্ট করে = 2x/10 = x/5 ইউনিট
∴ P এবং Q একত্রে প্রতি মিনিটে প্রিন্ট করে = (x/20) + (x/5)
= (x + 4x)/20
= 5x/20
= x/4 ইউনিট
এখন,
x/4 ইউনিট প্রিন্ট করতে সময় লাগে 1 মিনিট।
∴ 100x ইউনিট প্রিন্ট করতে সময় লাগবে = (100x × 4)/x = 400 মিনিট
= 6 ঘণ্টা 40 মিনিট
Question: Tamim can do a work in 12 days and Sakib in 15 days. If they work on it together for 5 days, then the fraction of the work that is left is:
Solution:
Tamim's 1 day's work = 1/12
Sakib's 1 day's work = 1/15
∴ (Tamim + Sakib)'s 1 day's work = (1/12 + 1/15) part
= (5 + 4)/60 part
= 9/60 part
= 3/20 part
∴ (Tamim + Sakib)'s 5 day's work = [5 × (3/20)] part
= 15/20 part
= 3/4 part
Therefore, Remaining work = (1 - 3/4) part
= 1/4 part
প্রতি লাইনে 11 words, প্রতি page এ 36 লাইন বিশিষ্ট 125 pages এ
word আছে 11× 36 × 125
5 দিনে 11 × 36 × 125 words হয়
1 দিনে (11 × 36 × 125)/5 words হয়
∴ 6 দিনে (11 × 36 × 125 × 6)/5 words হয়
= (11 × 36 × 125 × 6)/(5 × 12) lines
= (11 × 36 × 125 × 6)/(5 × 12 ×30) pages
= 165 pages.
Assume first child (the youngest) get = Tk. x
According to the question ;
each son having Tk. 30 more than the younger one
Second child will get = Tk. x + 30
Third child will get = Tk. x + 30 + 30 = x + 60
Fourth child will get = Tk. x + 30 + 30 + 30 = x + 90
Fifth child will get = Tk. x + 30 + 30 + 30 + 30 = x + 120
Total amount they got = Tk. 2000
x + (x+30) + (x+60) + (x+90) + (x+120) = 2000
5x + 300 = 2000
5x = 1700
x = Tk. 340
So the youngest child will get Tk. 340.
From M1D1 = M2D2
⇒ M1D1 / M2D2 = 5/6
⇒ (x−1)(x+1)/(x+1)(x+2) = 5/6
⇒ (x−1)/(x+2) = 5/6
⇒ 6x−6 = 5x+10
⇒ x = 16
Question: If a dozen bananas cost 30 Taka, what is the price of the number of bananas that is 2 less than a dozen?
Solution:
A dozen bananas costs = 30 Taka.
A dozen = 12 bananas
So, the cost of 12 bananas = 30 Taka
∴ Cost of 1 banana = 30/12 = 2.5 Taka.
Now, 2 less than a dozen of bananas = 12 - 2 = 10 bananas.
Then, cost of 10 bananas,
= 10 × 2.5
= 25 Taka.
Number of rotation in one hour = 10 × 60 = 600
So, Distance moved = (600 × 20) = 12000 m
Question: 3 pumps, working 12 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day?
Solution:
3 pumps need 2 days by working 12 hours
1 pump needs 1 day by working 12 × 3 × 2 hours
4 pumps need 1 day by working (12 × 3 × 2)/4 hours
= 18 hours
Question: There is a group of 7 boys and 4 girls. The two groups working together can do five times as much work as a boy and a girl. Ratio of working capacities of a boy and a girl is:
Solution:
Let 1 boy's 1 day's work = x
And 1 girl's 1 day's work = y
Now,
(7 boys + 4 girls)'s work = 7x + 4y
Given,
7x + 4y is equal to 5 times work done by a boy and a girl
Thus,
7x + 4y = 5(x + y)
⇒ 7x + 4y = 5x + 5y
⇒ 7x - 5x = 5y - 4y
⇒ 2x = y
⇒ x/y = 1/2
⇒ x : y = 1 : 2
Hence, the required ratio is 1 : 2
Question: A machine produces 300 pens in 5/2 hours. How many pens can it produce in 50 minutes?
Solution:
দেওয়া আছে,
সময় = 5/2 ঘণ্টা = (5/2) × 60 = 150 মিনিট
150 মিনিটে কলম উৎপাদিত হয় = 300টি
1 মিনিটে কলম উৎপাদিত হয় = 300 / 150 = 2টি
50 মিনিটে কলম উৎপাদিত হয় = 2 × 50 = 100টি
∴ মেশিনটি 50 মিনিটে 100টি কলম উৎপাদন করতে পারবে।
First daughter, in 1 hour, did 1/3 part
Second daughter, in 1 hour, did 1/6 part
Mother, in 1 hour, did (1/3 + 1/6) part
= 3/6 part
= 1/2 part
so, mother did it in 2 days.
Let the required number of rounds be x
More radius, less rounds(Indirect proportion)
Hence we can write as
(radius) 14 : 20 :: x : 70
⇒ 14 × 70 = 20x
⇒ 14 × 7 = 2x
⇒ x = 7 × 7
= 49 days.
Question: A truck can carry 24 motorcycles or 36 scooters at a time. If there are 10 motorcycles on the truck, how many scooters can be loaded onto it?
Solution:
Here,
24 motorcycles = 36 scooters
∴ 1 motorcycle = 36/24 scooters = 3/2 scooters
∴ 10 motorcycles = (36 × 10)/24 scooters = 15 scooters
∴ Maximum number of scooters that can still be loaded = 36 - 15 = 21 scooters