ব্যাখ্যা
According to the question,
15% of 1st no. =21% of 2nd no.
1% of 1st no.= (21/15) % of 2nd no.
18% of 1st no.= {(21/15) × 18} % of 2nd no.
=25.2%
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According to the question,
15% of 1st no. =21% of 2nd no.
1% of 1st no.= (21/15) % of 2nd no.
18% of 1st no.= {(21/15) × 18} % of 2nd no.
=25.2%
Question: If both the length and the breadth of a rectangle are increased by 20%, what is the percentage increase in its area?
Solution:
মনে করি,
দৈর্ঘ্য = x একক এবং
প্রস্থ = y একক
∴ ক্ষেত্রফল = xy বর্গ একক
২০% বৃদ্ধিতে,
নতুন দৈর্ঘ্য = x + x এর ২০%
= ১২x /১০ একক
২০% বৃদ্ধিতে,
প্রস্থ = y + y এর ২০%
= ১২y /১০ একক
∴ নতুন ক্ষেত্রফল = (১২x/১০) ×( ১২y/১০) = ১৪৪xy/১০০ বর্গ একক
∴ ক্ষেত্রফল বৃদ্ধি =১৪৪xy/১০০ - xy
=(১৪৪xy - ১০০xy)/১০০
= ৪৪xy/১০০
∴ শতকরা ক্ষেত্রফল বৃদ্ধি = {(৪৪xy/১০০) × (১/xy) × ১০০}%
= ৪৪%
Let, the C.P (cost price) of 1 kg goods be 1 tk
Then, S.P. of ⟮100 - (25/2%) of 1 kg} i.e., g 875 g goods = .9375 tk
S.P of 1 kg goods = (.9375/875 × 1000) tk = 1 (1/14) tk
& there4; Profit % = (1/14 × 100)% = 7(1/7)%
Answer : 7(1/7)%
Suppose, number of articles bought = L.C.M. of 6 and 5 = 30.
C.P. of 30 articles = TK.(5/6)x 30 = Tk. 25.
S.P. of 30 articles = Tk. (6/5)x 30 = Tk. 36.
Gain % = (11/25)x 100 = 44%.
Question: The price of cooking oil is reduced by 10%. A family buys 4 litres more for Tk. 720 after the reduction. What was the original price per litre?
Solution:
Let
Original price of cooking oil = x Tk/litre.
Original quantity = 720/x litre
New price = 0.90x Tk/litre
New quantity = 720/0.90x = 720/(9x/10) = (720 × 10)/9x = 800/x litre
ATQ,
(800/x) - (720/x) = 4
⇒ (800 - 720)/x = 4
⇒ 80/x = 4
⇒ x = 80/4
∴ x = 20
∴ Original price of cooking oil = 20 Tk/litre.
We are given that,
1) Total population of city = 6500
2) Increase in male and female population = 5% & 10% respectively.
3) Final population of city = 7000
Hence,
Let’s assume that number of males = x
Number of female = 6500 – x
Therefore, after an increase in 5% male and 10% female, the population becomes 7000
5% male +10% female = Difference between new and original population
⇒ (5/100)x + (10/100) (6500 - x) = 7000 - 6500
⇒ 5x + 65000 - 10x = 50000
⇒ 5x = 15000
⇒ x = 3000
Number of males = 3000
Number of females = 3500.
Question: In an election between two candidates, the winner got 65% of the total votes cast and won the election by a majority of 2748 votes. What is the total number of votes cast if no vote is declared invalid?
Solution:
Winner gets 65% of valid votes and loser gets 35% of votes
Difference between this two = 2748
(65 - 35)% = 2748
⇒ 30% = 2748
Total number of voters, 100% = (2748 × 100)/30
= 9160
Let,
C's income = 100
So, B's income = 100-25 = 75
And,
A's income = 75 + 75×(20/100) = 75+15 = 90
∴ A’s income less from C’s income is = {(100 - 90)/100}×100 = 10%
Question: A fruit salad is made by mixing 3 kgs of mango costing Tk 120 per kg and 2 kgs of papaya costing Tk 100 per kg and 2 kgs of grapes costing Tk 140 per kg. At what price (in Taka) per kg should the mixture be sold to make profit of 25 percent?
Solution:
3 কেজি আমের মূল্য = 120 × 3 = 360 টাকা
2 কেজি পেঁপের মূল্য = 100 × 2 = 200 টাকা
2 কেজি আঙ্গুরের মূল্য = 140 × 2 = 280 টাকা
মোট = 360 + 200 + 280 = 840 টাকা
25% লাভে
বিক্রয়মূল্য = 840 + 840 এর 25%
= 840 + 840 এর 25/100
= 840 + 210
= 1,050
7 কেজি বিক্রয় করতে হবে = 1050 টাকা
1 কেজি বিক্রয় করতে হবে = 1050/7 টাকা
= 150 টাকা
Let the price of one loaf of bread is 100x
So, price of 300 loaves of bread is 30000x
At 20% increase,
Price of one loaf of bread is 120x
So, with 30000x taka = 30000x/120x = 250 loaves of bread can be purchased
Question: A merchant sells one table for Tk. 1200, making a profit of 25%, and another table for Tk. 1500, incurring a loss of 10%. What is his overall gain or loss percentage?
Solution:
C.P. of 1st table = Tk.(100 × 1200)/125 = Tk. 960
C.P. of 2nd table = Tk.(100 × 1500)/90 = Tk. 1667
So, total C.P. = Tk.(960 + 1667) = Tk. 2627
Total S.P. = Tk.(1200 + 1500) = Tk. 2700
∴ Gain% = {(2700 - 2627) × 100}/2627%
= (73 × 100)/2627%
= 2.78%
Profit earned by manufacturer = 20 %
Profit earned by wholesaler = 25 %
Profit earned by retailer = 30%
S.P. of shoes = Tk. 50
Therefore,
130 % of 125 % of 120 % of x = 50.50
⇒ (120/100) × (125/100) × (130/100) × x = 5050/100
⇒ (195/100) x = 5050/100
⇒ x = (5050 × 100)/(195 × 100)
⇒ x = 25.89
Cost price of shoes = Tk. 25.89.
Question: If one number is 20% smaller than another number, and that second number is 10% greater than 150, what is the value of the first number?
Solution:
Let,
First number x
Second number y
ATQ,
y is 10% more than 150
⇒ y = 150 + [(150 × 10)/100]
= 165
and x is 20% less than y
⇒ x = 165 - [(165 × 20)/100]
= 165 - 33
= 132
∴ First number 132
Question: A shopkeeper sold one item at a 15% profit and another item at a 5% loss. If the cost price of both items is the same, find the overall profit percent.
Solution:
ধরি,
প্রতিটি দ্রব্যের ক্রয়মূল্য = x টাকা
15% লাভে,
একটি দ্রব্যের বিক্রয়মূল্য = x + 15% of x
= x + (15x/100)
= x + (3x/20)
= 23x/20 টাকা
5% ক্ষতিতে,
অপর দ্রব্যের বিক্রয়মূল্য = x - 5% of x
= x - (5x/100)
= x - (x/20)
= 19x/20 টাকা
মোট ক্রয়মূল্য = x + x = 2x টাকা
মোট বিক্রয়মূল্য = (23x/20 + 19x/20) টাকা
= 42x/20
= 21x/10 টাকা
∴ মোট লাভ = বিক্রয়মূল্য - ক্রয়মূল্য
= (21x/10) - 2x
= x/10 টাকা
∴ শতকরা লাভ = (লাভ/ক্রয়মূল্য) × 100%
= (x/10 ÷ 2x) × 100%
= (1/20) × 100%
= 5%
Number of students (passed) = 20×30% + 30×50% + 40×60%
= 6 + 15 + 24
= 45
Percentage of passed students of the entire school = 45/90 × 100 = 50%
According to the question,
Loss = 20% Selling price
i.e.
Loss/ Selling price = 1/5
∴ Cost price = Selling price + Loss
= 5 + 1
= 6
∴Loss%=1/6 ×100=50/3%
Question: A seller mixes 26 kg of rice at Tk. 20 per kg with 30 kg of rice of other variety at Tk. 36 per kg and sells the mixture at Tk. 30 per kg. His profit percentage is:
Solution:
Given, Cost of 1kg of rice = Tk. 20
∴ Cost of 26kg of rice = 20 × 26 = 520 Tk.
Again, Cost of 1kg of rice = Tk. 36
∴ Cost of 30kg of rice = 36 × 30 =1080 Tk.
∴ Total C.P = Tk. (520 + 1080)
= Tk. 1600
Total rice weight = (30 + 26) kg = 56 kg
So,
Trader sold this 56kg of rice at Tk. 30 per kg
∴ Total S.P = Tk. (56 × 30)
= Tk. 1680.
Hence,
Profit = 1680 - 1600 = Tk. 80
Profit percentage = (80/1600) × 100
= 5%
Question: A book seller allowed 10% discount on printed price. He gets 30% commission from publisher. His profit in percent will be?
Solution:
let, the marked price of book is 100 taka
buying price 100 × 0.7 taka
= 70 taka
selling price of book seller = 100 × 0.9 taka
= 90 taka
Profit in percent = {(90 - 70)/70} × 100%
= (200/7)%
Question: A trader mixes 26 kg of rice at Tk 20 per kg with 30 kg of rice of other variety at Tk. 36 per kg and sells the mixture at Tk. 30 per kg. His profit percent is:
Solution:
C.P. of 56 kg rice = (26 × 20 + 30 × 36)
= (520 + 1080)
=1600 taka
S.P. of 56 kg rice = (56 × 30)
= 1680 taka
∴ Profit = 1680 - 1600
= 80 taka
∴ Profit percentage = (80/1600) × 100% = 5%
Salary Increased = 8100-7200 = 900
Percent increased = (900/7200) × 100 = 12.5%
Question: A student scores 55% marks in 8 papers, each carrying 100 marks. He obtains 15% of his total obtained marks in the Bangla paper. How many marks did he score in Bangla?
Solution:
৮ টি বিষয়ে মোট নম্বর = 8 × 100 = 800
সে নম্বর পেয়েছে = 800 এর 55%
= 800 এর 55/100
= 440
∴ সে বাংলায় নম্বর পেয়েছে = 440 এর 15%
= 440 এর 15/100
= 66
Question: A company's profits have doubled for each of the last 6 years. If the total profits for the last 6 years were Tk. 126 lacs, what were the profits in the first year?
Solution:
মনে করি, প্রথম বছরে কোম্পানির লাভ ছিল x টাকা।
যেহেতু প্রতি বছর লাভ দ্বিগুণ হচ্ছে, তাই 6 বছরের লাভগুলো হবে যথাক্রমে: x, 2x, 4x, 8x, 16x এবং 32x
প্রশ্নমতে,
x + 2x + 4x + 8x + 16x + 32x = 1,26,00,000
⇒ 63x = 1,26,00,000
⇒ x = 1,26,00,000/63
⇒ x = 2,00,000
∴ প্রথম বছরে কোম্পানির লাভ ছিল 2,00,000 টাকা।
According to the question,
Retail price 40 Tk. (per pen).
20% discount = 40 × (20/100)
= 8 Tk.
অর্থ্যাৎ,
প্রতি pen এ save হয় = 8 Tk.
Total savings = 240 Tk.
∴ Number of pen = 240/8
= 30 pen.
Question: By selling an article at 1/2 of the marked price, there is a 25% loss. Find the profit percent if the article is sold at the marked price.
Solution:
Let the marked price be x TK
Then,
Selling price = (1/2)x , loss = 25%
∴ Cost price = TK. (100/75) × (x/2)
= TK. (2x/3)
If an article is sold at marked price.
Then profit = TK. {x - (2x/3)}
= TK. (x/3)
∴ profit%
= {(x/3) × (3/2x) × 100}%
= 50%
Question: A man bought 40 shares of Tk. 50 at 5tk discount, the rate of dividend being 27%. The rate of interest obtained is-
Solution:
Given,
Total investment = Tk. [40 × (50 - 5)] = Tk. 1800.
Face value = Tk. (50 × 40) = Tk. 2000.
∴ Dividend = (27/100) × 2000
= Tk. 540
∴ Interest obtained = (540/1800) × 100%
= 30%
Increase = 7.5 - 6
= 1.5
percentage of increase= (1.5/6) × 100
= 25%
so, consumption must be reduced by (r/100+r) × 10
= (25/100+25) × 100
= 20%
CP of 1 orange
= Tk.34/8
= Tk.4.25
SP of 1 orange
=Tk. 57/12
=Tk.4.75
Profit on each apple = (4.75 - 4.25) = Tk. 0.50
∴ Number of apples required
= 45/ 0.50
=90
Let the new S.P. be Tk . x
Then, 85 : 18700 = 115 : x
⇒ x = (18700 × 115)/85
⇒ x = 25300
Cloth is required for 1 shirt
= 2 m, 60 cm or 260 cm
Cloth is required for 7 shirt
= 260 × 7
= 1820 cm or 18 m 20 cm
First increase by 20%
So, per share value is = 40 + 40×20% = 48
Then, decrease by 25%,
So new value will become = 48 - 48×25% = 36
Question: If 60% of a number is equal to three-fourths of another number, what is the ratio of the first number to the second number?
Solution:
ধরি,
প্রথম সংখ্যাটি x এবং দ্বিতীয় সংখ্যাটি y।
প্রশ্নমতে,
60% of x = (3/4) of y
⇒ (60/100) × (x) = (3/4) × y
⇒ (3/5)x = (3/4)y
⇒ x/5 = y/4
⇒ 4x = 5y
⇒ x/y = 5/4
∴x : y = 5 : 4
Question: What percent of 10 kg is 50 grams?
Solution:
Required Percentage = {(50gm/10kg) × 100}%
= {(50/10000) × 100}% [1kg = 1000gm]
= (5000/10000)%
= 0.5%