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Therefore, person's present age = 2x/5 years
(x + 8)/2 = 2x/5 + 8
⇒ (x + 8)/2 = (2x + 40)/5
⇒ 5x + 40 = 4x + 80
⇒ x = 40 years
PrepBank · বিষয়ভিত্তিক প্রশ্ন
PrepBank · পাতা ২ / ৭ · ১০১–২০০ / ৬০৭
Question: The present ages of P and Q are in the ratio 2 : 7. After 8 years, the ratio of their ages will be 3 : 8. What is the difference in their present ages?
Solution:
Let the present ages be,
P = 2x and Q = 7x
Ages after 8 years,
P = 2x + 8, Q = 7x + 8
According to the problem, the ratio becomes 3:8
(2x + 8)/(7x + 8) = 3/8
⇒ 8(2x + 8) = 3(7x + 8)
⇒ 16x + 64 = 21x + 24
⇒ 64 - 24 = 21x - 16x
⇒ 40 = 5x
⇒ x = 8
P = 2 × 8 = 16 years
Q = 7 × 8 = 56 years
∴ Difference = 56 - 16 = 40 years
Question: Rahim is currently four times as old as Kabir. Five years ago, Rahim was seven times as old as Kabir. What will be the sum of their ages after 12 years?
Solution:
Let Kabir's current age = x years
Rahim's current age = 4x years
5 years ago:
Rahim's age = 4x - 5
Kabir's age = x - 5
According to the question,
4x - 5 = 7(x - 5)
⇒ 4x - 5 = 7x - 35
⇒ - 5 + 35 = 7x - 4x
⇒ 30 = 3x
∴ x = 10
So, Kabir's age = 10 years, Rahim's age = 4 × 10 = 40 years
After 12 years:
Kabir's age: 10 + 12 = 22
Rahim's age: 40 + 12 = 52
∴ Sum: 22 + 52 = 74
Present age of A + B = 50
A + 4 = C
So, A = C - 4
B = C + 2
Now,
C + 2 + C - 4 = 50
Or, 2C = 52
Or, C = 26
So,
B = 26 + 2
= 28
8 years Ago B age = (28 - 8) = 20 years
The age before 10 years increased by 25 % in 10 years.
In other words, the age before 10 years would have increased by 100 % in 40 years.
That is, the age before 10 years is 40 years. Therefore, the present age is 50.
Question: The sum of the ages of a father and his son is 45 years. Five years ago, the product of their ages was 4 times the father's age at that time. What are the present ages of the father and son?
Solution:
ধরি,
বর্তমানে বাবার বয়স = x বছর
বর্তমানে ছেলের বয়স = (45 - x) বছর
5 বছর আগে,
বাবার বয়স = x - 5
ছেলের বয়স = (45 - x) - 5 = 40 - x
প্রশ্নমতে,
(x - 5)(40 - x) = 4(x - 5)
⇒ 40 - x = 4
⇒ x = 40 - 4 = 36
∴ বাবার বর্তমান বয়স = 36 বছর
ছেলের বর্তমান বয়স = 45 - 36 = 9 বছর
Let A's age 10 year ago = x year.
Then, B's age 10 year ago = 2x year.
(x + 10) / (2x+ 10) = 3/4
=> x = 5.
So, the total of their present ages
=(x + 10 + 2x + 10)
= (3x + 20)
= 35 year.
Question: The ratio of the present ages of P and Q is 3 : 4. Five years ago, the ratio of their ages was 5 : 7. Find their present ages.
Solution:
As the ratio of their present ages is 3 : 4 ,
let their present ages be 3x and 4x.
So, 5 years ago, as the ratio of their ages was 5 : 7,
According to the question,
(3x - 5) : (4x - 5) = 5 : 7
⇒ (3x - 5)/(4x - 5) = 5/7
⇒ 21x - 35 = 20x - 25
⇒ x = 10
Hence, their present ages are 3x = 30 and 4x = 40
ধরি, C এর বয়স x বছর
তাহলে B এর বয়স = 2x বছর এবং A এর বয়স = (2x + 2) বছর
প্রশ্নমতে, x + 2x + 2x + 2 = 27
⇒ 5x = 27 - 2
⇒ x = 25/5
⇒ x = 5
∴ B এর বয়স (2×5) বছর = 10 বছর
Let the son's present age be x years.
Then, man's present age = (x + 24) years
=> (x + 24) + 2 = 2(x + 2)
=> x + 26 = 2x + 4
So, x = 22
Question: The combined ages of 5 children, with each child 4 years older than the next, equal 70 years. How old is the oldest?
Solution:
Let the ages of children be x, (x + 4), (x + 8), (x + 12) and (x + 16) years.
Then,
x + (x + 4) + (x + 8) + (x + 12) + (x + 16) = 70
5x + 40 = 70
5x = 70 - 40
⇒ 5x = 30
⇒ x = 6
∴ Age of the eldest child = x + 16 = 6 + 16 = 22 years.
Question: The present ages of Rahim and Sakib are in the ratio 4 : 5. After 6 years, the ratio of their ages will be 5 : 6. What is the difference in their present ages?
Solution:
Let, their present ages be 4x and 5x.
After 6 years,
Rahim's age = 4x + 6
Sakib's age = 5x + 6
According to the question,
(4x + 6)/(5x + 6) = 5/6
⇒ 6(4x + 6) = 5(5x + 6)
⇒ 24x + 36 = 25x + 30
⇒ 25x - 24x = 36 - 30
⇒ x = 6
Rahim's present age = 4 × 6 = 24 years
Sakib's present age = 5 × 6 = 30 years
∴ Difference = 30 - 24 = 6 years
Question: The present ages of A and B are in the ratio 3 : 5. After 10 years, the ratio of their ages will be 4 : 6. What is the difference in their present ages?
Solution:
Let the present ages be,
A = 3x and B = 5x
Ages after 10 years,
A = 3x + 10
B = 5x + 10
According to the problem, the ratio becomes 4 : 6
(3x + 10) : (5x + 10) = 4 : 6
⇒ (3x + 10)/(5x + 10) = 4/6
⇒ 3(3x + 10) =2(5x + 10)
⇒ 9x + 30 = 10x + 20
⇒ 10x - 9x = 30 - 20
∴ x = 10
A = 3 × 10 = 30 years
B = 5 × 10 = 50 years
∴ Difference = 50 - 30 = 20 years
Sum of the present age of husband, wife and child
= (23 × 2 + 5 × 2) + 1 = 57 years
∴ Required average = (57/3) years
= 19 years
Let Siya's age = x
Then Riya's age = 4x
But given Riya's age = 24
=> 4x = 24
=> x = 6
Hence Siya's age = 6 years
=> The age difference = 24 - 6 = 18 years.
If Ratul age is x,
then Sahin age is x - 7,
so, (x - 7)/x = 7/9
9x - 63 = 7x
2x = 63
x = 31.5
So, Sahin age is = 31.5 - 7
= 24.5
Let,
The son's present age is x years.
Then, the man's present age is = (x + 24)
∴ (x + 24) + 2 = 2(x+ 2)
⇒ x + 26 = 2x + 4
⇒ x = 22
Question: The present ages of Kamal and Jamal are in the ratio 5 : 7. After 8 years, the ratio of their ages will be 3 : 4. What is the difference in their present ages?
Solution:
Let, their present ages be 5x and 7x.
After 8 years,
Kamal's age = 5x + 8
Jamal's age = 7x + 8
According to the question,
(5x + 8)/(7x + 8) = 3/4
⇒ 4(5x + 8) = 3(7x + 8)
⇒ 20x + 32 = 21x + 24
⇒21x - 20x = 32 - 24
∴ x = 8
Kamal's Present age = 5 × 8 = 40 years
Jamal's Present age = 7 × 8 = 56 years
∴ Difference = 56 - 40 = 16 years
Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
According to the question,
(2x + 2) + 2x + x = 27
5x = 25
⇒ x = 5
Hence, B's age = 2x = 10 years.
Let the son's present age be x years.
Then,
man's present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
Question: Ten years ago, the ratio of ages of S and T was 4 : 3. Now the ratio is 5 : 4. Find the present age of T.
Solution:
Let the ages of S and T ten years ago be 4x and 3x.
Present ages of
S = 4x + 10 and T = 3x + 10
Now ratio = 5 : 4
⇒ (4x + 10)/(3x + 10) = 5/4
⇒ 4(4x + 10) = 5(3x + 10)
⇒ 16x + 40 = 15x + 50
⇒ 16x - 15x = 50 - 40
⇒ x = 10
∴ Present age of T = 3x + 10
= (10 × 3) + 10
= 30 + 10
= 40
Question: Sadia is currently three times older than Rina. Ten years ago, Sadia’s age was seven times Rina’s age.
What will be the sum of their ages after 8 years?
Solution:
Let Rina’s current age = x years
Sadia’s current age = 3x years
10 years ago:
Sadia’s age = 3x - 10
Rina’s age = x - 10
According to the question,
3x - 10 = 7(x - 10)
⇒ 3x - 10 = 7x - 70
⇒ - 4x = - 60
⇒ x = 15
So, Rina’s age = 15 years, Sadia’s age = 45 years
After 8 years:
Rina = 15 + 8 = 23
Sadia = 45 + 8 = 53
Sum = 23 + 53 = 76
Question: Product of present age of Rahim and Latif is 2223 years and their present age ratio is 19 : 13 find the difference age of Rahim and Latif.
Solution:
Let, age of Rahim be 19x and age of Latif be 13x
Then, product of their ages = 19x × 13x = 247x2
Now,
247x2 = 2223
⇒ x2 = 9
∴ x = 3
Hence, required difference = 19x - 13x = 6x = 6 × 3 = 18 years
Question: A person's present age is two-fifth of the age of his father. After 10 years, he will be one half of the age of his father. What is the present age of the father?
Solution:
Let the age of the person's father be 'x' years
∴ Age of the person = (2x/5)
After 10 years, age of the person's father = 'x + 10' years
Age of the person after 10 years = (2x/5) + 10 years
According to question,
(2x/5) + 10 = (1/2)(x + 10)
⇒ (2x/5) + 10 = (x/2) + 5
⇒ (x/2) - (2x/5) = 10 - 5
⇒ (5x - 4x)/10 = 5
⇒ x/10 = 5
⇒ x = 50
So, the present age of his father is 50 years
Bubli's age = 14 years
⇒ Sakib's age = (14 - 9) years
= 5 years
Let the present age of Zayed Khan be x years.
∴ (x - 10)/14 = 5
⇒ x - 10 = 70
⇒ x = 80 years.
Answer: Zayed Khan age is 80 years.
Question: The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of second youngest
one?
Solution:
মনে করি,
সবচেয়ে ছোট শিশুটির বয়স x বছর
যেহেতু প্রত্যেক শিশুর জন্মের ব্যবধান 3 বছর
তাই 5 জন শিশুর বয়স হবে:
প্রথম অর্থাৎ সবচেয়ে ছোট শিশুটির বয়স x বছর
দ্বিতীয় অর্থাৎ দ্বিতীয় ছোট শিশুটির বয়স (x + 3) বছর
তৃতীয় শিশুটির বয়স (x + 3 + 3) বা (x + 6) বছর
চতুর্থ শিশুটির বয়স (x + 6 + 3) বা (x + 9) বছর
পঞ্চম শিশুটির বয়স (x + 9 + 3) বা (x + 12) বছর
প্রশ্নমতে,
x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
⇒ 5x + 30 = 50
⇒ 5x = 50 - 30
⇒ 5x = 20
⇒ x = 20/5
∴ x = 4
∴ দ্বিতীয় কনিষ্ঠ অর্থাৎ দ্বিতীয় ছোট শিশুটির বয়স = (4 + 3) বছর
= 7 বছর
Let C's age be x years.
Then,
B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence,
B's age = 2x = 10 years.
Question: Father is aged three times more than his son Rakib. After 8 years, he would be two and a half times of Rakib's age. After further 8 years, how many times would he be of Rakib's age?
Solution:
Let,
Rakib's present age be x years.
Then, father's present age =(x + 3x) years
= 4x years.
ATQ,
(4x + 8) = {5(x + 8)}/2
⇒ 8x + 16 = 5x + 40
⇒ 3x = 24
∴ x = 8
Now,
(4x + 16)/(x + 16) = 48/24 = 2
∴ Father would be 2 times of Rakib's age.