ব্যাংক নিয়োগ প্রস্তুতি ⎯ লং কোর্স

Sum of the ages of A and B, 4 years ago = 18 × 2 = 36 years
Sum of the present age of A and B = 4 + 4 + 36 = 44 years
Sum of the present ages of A, B and C = 24 × 3 = 72 years
⇒ Present age of C = 72 - 44 = 28 years

∴ C's age after 4 years = 28 + 4 = 32 years.

Let
the daughter's present age be x years.
Then, mother  present age = 3x years

According to the question 
3x + 12 = 2 (x + 12)
⇒ 3x + 12 = 2x + 24
⇒ x = 12
Present age of daughter = 12 years

A + B + C = 45 × 3 =135 kg
A + B = 40 × 2= 80 kg
B + C = 43 × 2= 86 kg

now 
A + B  + B + C = 80 + 86 = 166kg
A + 2B + C = 166kg

Weight of B = 166 -135
                    = 31 kg

Let
the age of Ram and Mohan be 5x and 7x respectively
According to the question
⇒ 7x - 5x = 12
⇒ 2x = 12
⇒ x = 6

The age of Ram = 5 × 6 = 30 years
The age of Mohan = 7 × 6 = 42 years

∴ The required result will be "30 years and 42 years" respectively.

(Man + wife)'s age at marriage = 27 × 2 = 54years
(Man + wife)'s age after 4 years = 54 + 4 × 2 = 62 years
Total age of family = 62 + 1 = 63 years
Average age = 63/3 = 21 years

∴ The average age is 21 years.

Let present age of mother is x,
then present age of his son = 2x​/5

According to the question 
 (2x​/5) + 8 = (1/2)(x + 8)
(2x​/5) + 8 = x/2 + 4 
(2x​/5) - (x/2) = 4 - 8
(4x - 5x)/10 = - 4
- x/10 = - 4
x = 40

Hence, the present age of mother is 40

Let the present age of Akash be x years.
Age of Akash after 7 years = x + 7
Present age of wife = 23 years
Age of wife after 7 years = 30 years

According to the question, Ratio of ages of Akash and his wife after 7 years from now = 7 : 6
⇒ (x + 7)/30 = 7/6
⇒ x + 7 = 35
⇒ x = 28 years

∴ Age of Akash after 2 years = 30

Given that
average of 2, 7, 6, x is 5

Therefore,
5 = (2 + 7 + 6 + x​)/4
⇒ 20 = 15 + x
⇒ x = 20 - 15
    x = 5

Therefore,
10 = (18 + 1+ 6 + 5 + y​)/5
50 = 30 + y
y = 50 - 30 
y = 20

Average age of man and his daughter = 34 years
Their total age = (34 × 2) years = 68 years
Let man's age be x years,
Then daughter age = (68 - x) years
∴(x + 4)/(68 - x + 4) =14/5
⇒5(x + 4) = 14(72 −x)
⇒5x + 20= 1008 − 14x
⇒19x =988
⇒ x =52

∴ Daughter's present age
= (68 - 52) years
= 16 years

Sum of marks in 4 Subjects = 75 × 4 = 300
Sum of marks in 5 Subjects = 300 + 85 = 385 
New Average = 385/5 = 77

Sum of all numbers = 75 × 5 = 375
Later, marks in one subject was increased by 12 and marks in another subject was decreased by 17.
Corrected marks = 375 + 12 – 17
                       = 370
Corrected Average = Correct sum / number of subjects
                           = 370/5
                           = 74
∴ Corrected average is 74

Let
Akash’s present age be x years
Akash’s age before 10 years = (x – 10)
Akash’s age after 20 years = (x + 20)
According to question
(x + 20) = 10(x – 10)
⇒ x + 20 = 10x – 100
⇒ 9x = 120
⇒ x = 13.3 years

∴ Present age of Akash is 13.3 years.

Numbers between 6 and 34 divisible by 5 are 10, 15, 20, 25, 30.
Required average =(10 + 15 + 20 + 25 + 30​)/5
                             = 100/5
                             ​= 20

Sum of the ages of A and B, 4 years ago = 16 × 2 = 32 years
Sum of the present age of A and B = 4 + 4 + 32 = 40 years
Sum of the present ages of A, B and C = 23 × 3 = 69 years

⇒ Present age of C = 69 - 40 = 29 years

∴ C's age after 4 years = 29 + 4 = 33 years.

First five multiple of 3 are
3 × 1 = 3
3 × 2 = 6
3 × 3 = 9
3 × 4 = 12 and
3 × 5 = 15
Average of first five multiples of 3 are (3 + 6 + 9 + 12 + 15)/5
                                                      = 9
 
∴ The average of first five multiples of 3 is 9.

Let the age of Abir eight years ago be 5x
Let the age of Deepak eight years ago be 7x
Present age of Abir  would be 5x + 8
Present age of Deepak would be 7x + 8

According to question, 
7x + 8 - (5x + 8) = 14 
7x + 8 - 5x - 8 = 14 
2x = 14 
x = 7

Deepak's present age = 7 × 7 + 8 = 57 years

First 10 even natural number = 2, 4, 6, 8, 10, 12, 14, 16, 18, 20

  Mean = (2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20​)/10
            = 110/10
            = 11

Ratio of the present ages of Tina and Bina = 9 : 10
Let's consider the present ages of Tina and Bina as 9x and 10x

According to the question 
(9x - 20) : (10x - 20) = 4 : 5
(9x - 20) / (10x - 20) = 4/5
5(9x - 20) = 4(10x - 20)
45x - 100 = 40x - 80
45x - 40x = 100 - 80
5x = 20
x = 4 

the present age of Bina = 40 years

Total marks scored by 22 candidates = 22 × 45
                                                           = 990
Total marks scored by first 10 candidates =10 × 55
                                                                 = 550
Total marks scored by last 11 candidates =11 × 40
                                                                 =440
∴ Marks scored by 11th candidate = 990 - (550 + 440)
                                                        = 0

2 times the age of X = 3 times the age of Y
2X = 3Y
⇒ X : Y = 3 : 2

Let present age of X and Y be 3a and 2a respectively
3a - 8 - (2a - 8) = 16
⇒ 3a - 2a = 16
⇒ a = 16

∴ The present age of X is 16 × 3 years = 48 years

Let the present age of Kajol and Rohit is 7x and 8x respectively.
After 6 years, the age of Kajol = 7x + 6
After 6 years, the age of Rohit = 8x + 6
The ratio of age of Kajol and Rohit after 6 years is 9 : 10.
⇒ (7x + 6)/(8x + 6) = 9/10
⇒ 70x + 60 = 72x + 54
⇒ 2x = 6
⇒ x = 3

The age of Rohit after 5 years = 8 × 3 + 5 = 24 + 5 = 29 years

∴The age of Rohit after 5 years is 29 years.

Average of 6 numbers = 7
Sum of 6 numbers = 6 × 7 = 42
Average of three numbers = 5
Sum of three numbers = 5 × 3 = 15

∴ Sum of the remaining three numbers = 42 - 15
                                                                = 27

∴ Required average = 27/3 = 9

10 years ago age of Jamal = 2x
10 years ago age of Kamal= 3x
10 years ago age of Rashed= 4x

Now
2x + 10 + 3x + 10 +  4x + 10 = 93
9x + 30 = 93 
9x = 93 - 30 
9x = 63 
x = 7

∴present age of Rashed = (4 × 7) + 10
                                       = 28 + 10
                                       =38 years

First 9 prime numbers.= 2, 3, 5, 7, 11, 13, 17, 19, 23
Average = Sum of all numbers / Total numbers.
              = (2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 23)/9
              = 100/9
              = 11.11
Therefore the avg of first 9 prime numbers is 11.11

Let
the second of the three numbers be x.
the first one is 2x and the third is 4x.

Thus
x + 2x + 4x = 63×3 
7x= 189
x = 27.

The difference between the first and third numbers =4x - 2x
                                                                                    = 2x
                                                                                    = 2 × 27
                                                                                    = 54

Let
The four numbers be a, b, c and d 
According the question 
a = (1/4)(b + c + d)
b + c + d = 4a

again 
a + b + c + d = 70 × 4 
a + 4a = 280 
5a = 280 
a = 280/5
a = 56

Let
X's age be x years,
Y's age = 240/x years

According to the question
⇒ 2 × (240/x) - x = 4
⇒ 480/x - x = 4
⇒ (480 - x²)/x = 4
⇒ 480 - x² = 4x
⇒ x² + 4x - 480 = 0
⇒ x² + 24x - 20x - 480 = 0
⇒ x(x+24) - 20(x - 24) = 0
⇒ (x + 24) (x - 20) = 0
⇒ x = 20 

Y's age = 240/20 = 12 Years

According to the question,
(30 + 72 + 53 + 68 + x + 87)/6 = 60
310 + x = 360
x = 360 - 310 
x = 50