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৪৯তম বিসিএস ⎯ ফলিত রসায়ন [৫৪১]

পরীক্ষা৪৯তম বিসিএস ⎯ ফলিত রসায়ন [৫৪১]তারিখতারিখ অনির্ধারিতসময়30 minutes
মোট প্রশ্ন৫০
সিলেবাস
Exam - 13 Topics: Caustic-Chlorine Industries & Plastic Industry 1. Methods of production of caustic soda and soda ash. 2. Electrolytic process for caustic soda and chlorine. 3. Diaphragm, Mercury and Membrane processes. [Source: Class - 09 and Relevant Books]
ঘনত্ব
উত্তর
উত্তরিতবর্তমানপুনরায় দেখুনঅসম্পূর্ণ

৪৯তম বিসিএস ⎯ ফলিত রসায়ন [৫৪১]

৪৯তম বিসিএস ⎯ ফলিত রসায়ন [৫৪১] · তারিখ অনির্ধারিত · ৫০ প্রশ্ন

.
In the diaphragm cell process for caustic soda production, the primary role of the diaphragm is to: 
  1. Increase the current efficiency by preventing hydrogen back-diffusion
  2. Reduce energy consumption by lowering cell voltage
  3. Separate chlorine and caustic soda while allowing brine flow
  4. Act as a catalyst for chlorine evolution reaction
সঠিক উত্তর:
Separate chlorine and caustic soda while allowing brine flow
উত্তর
সঠিক উত্তর:
Separate chlorine and caustic soda while allowing brine flow
ব্যাখ্যা

In the diaphragm cell process for caustic soda (NaOH) production:
1. The anode compartment produces chlorine gas (Cl₂) from chloride ions.
2. The cathode compartment produces hydrogen gas (H₂) and caustic soda (NaOH) from water reduction.
3. If these two compartments were not separated, chlorine could react with NaOH to form hypochlorite, reducing efficiency and causing safety hazards.

The diaphragm (usually made of asbestos or modern polymeric materials) serves these functions:
✔ It separates the anode and cathode compartments so that chlorine and caustic soda do not mix.
✔ It is porous, allowing brine (NaCl solution) to flow through to the cathode side to maintain ionic conductivity.

.
In the membrane cell process for caustic soda production, the membrane is usually made of: 
  1. Polypropylene fibers
  2. Cation-exchange polymer like perfluorinated resin (e.g., Nafion)
  3. Anion-exchange polymer
  4. Porous ceramic material
সঠিক উত্তর:
Cation-exchange polymer like perfluorinated resin (e.g., Nafion)
উত্তর
সঠিক উত্তর:
Cation-exchange polymer like perfluorinated resin (e.g., Nafion)
ব্যাখ্যা

In the membrane cell process for caustic soda (NaOH) production:
The membrane separates the anode (Cl₂ generation) and cathode (NaOH + H₂ generation) compartments.
It allows only Na⁺ ions (cations) to pass from the anode side to the cathode side while blocking Cl⁻ ions and OH⁻ back-migration.
This selectivity prevents the formation of hypochlorite (ClO⁻) and ensures high-purity caustic soda.
The membranes are usually made from perfluorinated cation-exchange polymers such as Nafion, which have sulfonic acid groups (-SO₃H) for ionic conduction

​Other Options:

​ক) Polypropylene fibers → Used in diaphragm cells, not in membrane cells.
গ) Anion-exchange polymer → Would allow Cl⁻ passage, which is undesirable.
ঘ) Porous ceramic material → Too permeable and non-selective for modern processes.

.
Which of the following best explains why the mercury cell process for caustic soda production is being phased out globally? 
  1. High electrical energy consumption only
  2. Low product purity
  3. Environmental hazards due to mercury contamination
  4. Poor current efficiency
সঠিক উত্তর:
Environmental hazards due to mercury contamination
উত্তর
সঠিক উত্তর:
Environmental hazards due to mercury contamination
ব্যাখ্যা

The mercury cell (Castner-Kellner) process is being phased out primarily because:
1. Mercury is highly toxic and poses severe environmental and health risks.
2. During operation, mercury can escape into the environment through brine, air emissions, and solid wastes, contaminating ecosystems and entering the food chain.
3. International regulations like the Minamata Convention on Mercury aim to eliminate such practices.

Why not the others?

ক) High electrical energy consumption only → While mercury cells do consume more energy compared to membrane cells, this is not the main reason for their phase-out.
খ) Low product purity → Actually, mercury cells produce very pure caustic soda (50% NaOH solution, almost chloride-free).
ঘ) Poor current efficiency → Mercury cells generally have good current efficiency, so this isn’t the primary issue.

.
In the Solvay process for soda ash production, the main purpose of bubbling ammonia into brine is to: 
  1. Facilitate precipitation of NaHCO3 by reducing NaCl concentration
  2. Increase solubility of NaCl
  3. Shift equilibrium to precipitate CaCO3
  4. Reduce decomposition of NH4Cl
সঠিক উত্তর:
Facilitate precipitation of NaHCO3 by reducing NaCl concentration
উত্তর
সঠিক উত্তর:
Facilitate precipitation of NaHCO3 by reducing NaCl concentration
ব্যাখ্যা

In the Solvay process (used for soda ash – Na₂CO₃ production):
Ammonia is bubbled into brine (NaCl solution) to make it ammoniacal brine.
When CO₂ is introduced, the following reaction occurs in the ammoniacal solution:
NaCl+NH3+CO2+H2O⟶NaHCO3(↓)+NH4Cl
 
​The role of NH₃ is to convert water into a weak base medium, which allows CO₂ to form bicarbonate ions without significantly reducing pH. This promotes precipitation of NaHCO₃ (which is sparingly soluble), while NH₄Cl remains dissolved.

So, ammonia essentially helps precipitate NaHCO₃ by controlling solubility and equilibrium,

.
In the Solvay process, which step regenerates ammonia for reuse?
  1. Heating NaHCO3 to form Na2CO3
  2. Carbonation of brine
  3. Saturating brine with NH3
  4. Decomposing NH4Cl with Ca(OH)2 to release NH3
সঠিক উত্তর:
Decomposing NH4Cl with Ca(OH)2 to release NH3
উত্তর
সঠিক উত্তর:
Decomposing NH4Cl with Ca(OH)2 to release NH3
ব্যাখ্যা

During carbonation, NH₄Cl is formed as a byproduct.

To reuse NH₃, NH₄Cl is treated with Ca(OH)₂ (milk of lime):
                  
2NH4Cl+Ca(OH)2⟶2NH3↑+CaCl2+2H2O

The released NH₃ is returned to the brine saturation step.

Byproduct: CaCl₂ (disposed or used in de-icing).

.
Which factor at the anode most significantly affects the formation of Na–Hg amalgam at the cathode and the overall current efficiency? 
  1. Anode current density and brine purity
  2. Anode material composition
  3. Mercury flow rate
  4. Cathode overpotential
সঠিক উত্তর:
Anode current density and brine purity
উত্তর
সঠিক উত্তর:
Anode current density and brine purity
ব্যাখ্যা

In a mercury cell, sodium is deposited at the cathode and forms a Na–Hg amalgam.

The anode current density directly affects the rate of chlorine evolution, which in turn influences the rate of sodium deposition at the cathode. Too high or too low current density can reduce current efficiency.

Brine purity is critical because impurities (like calcium or magnesium ions) can poison the anode, reduce chlorine evolution efficiency, and lead to lower sodium amalgam formation.

While mercury flow rate and cathode overpotential are important for proper amalgam handling and hydrogen suppression, the anode conditions (current density and brine purity) are the most significant factors for overall efficiency.

.
Which of the following statements correctly distinguishes the dual-ammonia (Hou’s) process from the classical Solvay process for soda ash production?
  1. In Hou’s process, ammonia is not recycled, whereas in Solvay it is.
  2. Hou’s process uses two ammonia absorption steps, increasing CO2 utilization efficiency compared to Solvay
  3. In Hou’s process, NaHCO3 precipitates directly from concentrated NaOH, unlike Solvay.
  4. Hou’s process does not produce NH4Cl as a byproduct, unlike Solvay.
সঠিক উত্তর:
Hou’s process uses two ammonia absorption steps, increasing CO2 utilization efficiency compared to Solvay
উত্তর
সঠিক উত্তর:
Hou’s process uses two ammonia absorption steps, increasing CO2 utilization efficiency compared to Solvay
ব্যাখ্যা

Dual-ammonia (Hou’s) process improves CO₂ efficiency by using a two-step ammonia absorption.

Like the Solvay process, NH₄Cl is still formed, but the second ammonia step recovers more CO₂ and reduces ammonia loss.

Ammonia is still recycled in both processes.

Precipitation does not occur in concentrated NaOH; it is still in ammoniacal brine.

.
In the Solvay process for soda ash production, which of the following steps is correctly matched with its primary energy or chemical requirement?
  1. Calcination of CaCO3 – Low-temperature exothermic reaction providing CO2 and CaO
  2. Carbonation of ammoniacal brine – Major electrical energy input to maintain brine circulation
  3. Ammonia recovery from NH4Cl with Ca(OH)2 – Chemical reaction requiring lime and moderate heat
  4. Filtration of NaHCO3 – Endothermic step requiring high thermal input to separate solids
সঠিক উত্তর:
Ammonia recovery from NH4Cl with Ca(OH)2 – Chemical reaction requiring lime and moderate heat
উত্তর
সঠিক উত্তর:
Ammonia recovery from NH4Cl with Ca(OH)2 – Chemical reaction requiring lime and moderate heat
ব্যাখ্যা

ক) Calcination of CaCO₃ – Incorrect statement:
True: It requires high thermal energy (~900°C) and is endothermic, not low-temperature/exothermic.

খ) Carbonation of ammoniacal brine – Incorrect statement:
This is a low-temperature, exothermic reaction, no significant electrical energy is required.

গ) Ammonia recovery from NH₄Cl with Ca(OH)₂ – Correct
NH₄Cl reacts with slaked lime to release NH₃ gas:
2NH4Cl+Ca(OH)2→2NH3↑+CaCl2+2H2O

Requires chemical energy (via lime preparation) and moderate heat to drive the reaction.

ঘ) Filtration of NaHCO₃ – Incorrect statement:
Filtration is a mechanical process; it does not require high thermal energy.

.
What is the primary reason for using pure brine in membrane cell caustic soda plants instead of raw brine? 
  1. To prevent electrode corrosion
  2. To increase chlorine production rate
  3. To avoid contamination of NaOH with Ca2+ and Mg2+ ions that damage the membrane
  4. To reduce current density
সঠিক উত্তর:
To avoid contamination of NaOH with Ca2+ and Mg2+ ions that damage the membrane
উত্তর
সঠিক উত্তর:
To avoid contamination of NaOH with Ca2+ and Mg2+ ions that damage the membrane
ব্যাখ্যা

In membrane cell caustic soda production:
The membrane is a cation-exchange polymer that selectively allows Na⁺ ions to pass while blocking Cl⁻, OH⁻, and other cations.
Hardness ions (Ca²⁺, Mg²⁺) from raw brine can:
Deposit on the membrane, reducing its efficiency.
Increase electrical resistance, raising energy consumption.
Cause mechanical damage or early failure of the membrane.
Therefore, pure brine (deionized or softened) is required to maintain long membrane life and high-purity NaOH.

​ক) Prevent electrode corrosion → Corrosion is mostly controlled by anode material and operating conditions, not brine purity.
খ) Increase chlorine production rate → Brine purity doesn’t significantly affect the rate; current density is the main factor.
ঘ) Reduce current density → Current density is set for efficiency and production rate, not brine purity.

১০.
In modern caustic soda plants, which process achieves the highest current efficiency and lowest energy consumption?
  1. Diaphragm cell
  2. Mercury cell
  3. Membrane cell
  4. Lime-soda process
সঠিক উত্তর:
Membrane cell
উত্তর
সঠিক উত্তর:
Membrane cell
ব্যাখ্যা

In modern caustic soda (NaOH) production, the membrane cell process is preferred because:

1. Highest current efficiency (~90–98%)
The cation-exchange membrane allows only Na⁺ ions to pass to the cathode side.
This minimizes side reactions, such as formation of hypochlorite or loss of OH⁻.

2. Lowest energy consumption (~2,500–3,000 kWh/ton NaOH)
Unlike diaphragm cells (~3,000–3,500 kWh/ton) or mercury cells (~2,800–3,200 kWh/ton), the membrane process uses less electrical energy per ton.

3. High-purity NaOH (~32% without contamination)
Free of Cl⁻, Hg, or other cations because the membrane blocks them.

১১.
In the mercury cell process, the cathode reaction produces amalgam. Which of the following correctly represents the cathodic reaction? 
  1. Na+ + H2O → NaOH + (1/2)H2
  2. Cl- → (1/2)Cl2 + e-
  3. 2H2O + 2e- → H2 + 2OH-
  4. Na+ + e- → Na (amalgam)
সঠিক উত্তর:
Na+ + e- → Na (amalgam)
উত্তর
সঠিক উত্তর:
Na+ + e- → Na (amalgam)
ব্যাখ্যা

In the mercury cell (Castner-Kellner) process:

Cathode: Mercury acts as a liquid cathode.
Reaction: Sodium ions are reduced to metallic sodium, which immediately forms an amalgam with mercury:
Na⁺+e→ Na (in Hg, amalgam)

The amalgam is then reacted with water in a separate reactor to produce NaOH and H₂ gas:
2Na(Hg) + 2H2O → 2NaOH + H2 + 2Hg

​Other options:
​ক) Na⁺ + H₂O → NaOH + ½ H₂ → This is the reaction of metallic Na with water, not the cathode reaction.
খ) Cl⁻ → ½ Cl₂ + e⁻ → This occurs at the anode, producing chlorine gas.
গ) 2H₂O + 2e⁻ → H₂ + 2OH⁻ → This is the cathode reaction in diaphragm or membrane cells, but not in mercury cells.

১২.
In diaphragm cells, the main factor limiting the concentration of NaOH to ~12% is:
  1. Back-diffusion of hydroxide ions to the anode
  2. Membrane swelling due to high pH
  3. Formation of hypochlorite side products
  4. Energy inefficiency at high concentrations
সঠিক উত্তর:
Back-diffusion of hydroxide ions to the anode
উত্তর
সঠিক উত্তর:
Back-diffusion of hydroxide ions to the anode
ব্যাখ্যা

The diaphragm is porous, allowing brine (NaCl solution) to pass but separating the cathode and anode compartments.

Cathode compartment: NaOH is produced along with H₂.

Limiting factor: As the NaOH concentration rises above ~12%, OH⁻ ions tend to diffuse back through the diaphragm toward the anode, where they react with chlorine.

This reduces current efficiency and prevents further concentration increase inside the cell.

​খ) Membrane swelling due to high pH → Membranes are used in membrane cells, not diaphragm cells.
গ) Formation of hypochlorite side products → This can happen if NaOH and Cl₂ mix, but the main limitation is back-diffusion.
ঘ) Energy inefficiency at high concentrations → Energy loss is secondary; the primary physical limitation is ion back-diffusion.

১৩.
The overall cell reaction in a membrane cell for caustic soda production can be written as:
  1. 2NaCl → 2Na + Cl2
  2. 2NaCl + 2H2O → 2NaOH + Cl2 + H2
  3. 2NaCl + H2O → Na2CO3 + H2 + Cl2
  4. NaCl + H2O → NaOH + (1/2)Cl2
সঠিক উত্তর:
2NaCl + 2H2O → 2NaOH + Cl2 + H2
উত্তর
সঠিক উত্তর:
2NaCl + 2H2O → 2NaOH + Cl2 + H2
ব্যাখ্যা

In a membrane cell process for NaOH production:

Anode reaction (oxidation of chloride):
2Cl→Cl2+2e-
Cathode reaction (reduction of water):
2H2O+2e→H2+2OH
Overall reaction:
2NaCl+2H2O→2NaOH+Cl2+H2

This shows the simultaneous production of:
1. NaOH in the cathode compartment
2. Chlorine gas at the anode
3. Hydrogen gas at the cathode

১৪.
In a membrane cell, which of the following is the most critical property of the cation-exchange membrane? 
  1. High selectivity for Cl- ions
  2. High electrical conductivity with OH-
  3. High Na+ ion conductivity and chemical resistance
  4. Mechanical strength to support the anode
সঠিক উত্তর:
High Na+ ion conductivity and chemical resistance
উত্তর
সঠিক উত্তর:
High Na+ ion conductivity and chemical resistance
ব্যাখ্যা

In a membrane cell for NaOH production:

The cation-exchange membrane separates the anode (Cl₂) and cathode (NaOH + H₂) compartments.

Critical requirements:
           1. High Na⁺ conductivity – allows sodium ions to pass from the anode side to the cathode side efficiently.
           2. Chemical resistance – must withstand highly corrosive alkaline NaOH on the cathode side and chlorine on the anode side without degradation.​
           3. Selectivity – blocks Cl⁻ and OH⁻ ions to prevent side reactions and maintain high current efficiency. 

​​Other options:

          ​ক) High selectivity for Cl⁻ ions → Wrong; the membrane should block Cl⁻, not conduct it.
          খ) High electrical conductivity with OH⁻ → Membrane does not conduct OH⁻; it conducts Na⁺ ions only.
          ঘ) Mechanical strength to support the anode → Some strength is required, but chemical stability and ion selectivity are more critical.ent efficiency.

১৫.
One advantage of the membrane cell over the diaphragm cell is:
  1. Higher energy consumption per ton of NaOH
  2. Production of caustic soda at higher purity (~99%)
  3. Back-diffusion of OH- is enhanced
  4. Requires mercury as a cathode
সঠিক উত্তর:
Production of caustic soda at higher purity (~99%)
উত্তর
সঠিক উত্তর:
Production of caustic soda at higher purity (~99%)
ব্যাখ্যা

Membrane cell advantages over diaphragm cell:

1. High purity NaOH (~99%)
          The cation-exchange membrane blocks Cl⁻, Mg²⁺, Ca²⁺, and other impurities from reaching the cathode compartment.
          Diaphragm cells produce only ~30–32% NaOH, which still contains some NaCl.

2. Higher current efficiency (~90–98%)
          Membrane cells minimize side reactions like Cl⁻ back-diffusion.

3. Lower energy consumption per ton
          Membrane cells are more energy-efficient than diaphragm cells.

​Other Options:

          ​ক) Higher energy consumption →
False; membrane cells consume less energy than diaphragm cells.
          গ) Back-diffusion of OH⁻ is enhanced →
False; the membrane prevents back-diffusion, which improves efficiency.
          ঘ) Requires mercury as a cathode →
False; mercury is only used in mercury cells, not membrane cells.

১৬.
The main limitation of increasing current density in a diaphragm cell is:
  1. Reduced chlorine evolution efficiency due to mass transport limitations
  2. Overheating of the diaphragm
  3. Membrane chemical degradation
  4. Formation of sodium chlorate as a side product
সঠিক উত্তর:
Reduced chlorine evolution efficiency due to mass transport limitations
উত্তর
সঠিক উত্তর:
Reduced chlorine evolution efficiency due to mass transport limitations
ব্যাখ্যা

In a diaphragm cell:

Increasing current density means more charge passes per unit area of the electrode.
Limitation: At high current densities:

1.  Mass transport of Cl⁻ ions to the anode surface becomes slower than the rate of reaction.
2. This leads to reduced chlorine evolution efficiency and possibly increased side reactions (like oxygen evolution).

The diaphragm is porous, so OH⁻ can also back-diffuse, but the main limiting factor for high current density is mass transport of chloride ions.

​Other Options:
খ) Overheating of the diaphragm → 
Diaphragms are usually designed for proper cooling; not the main limitation.
গ) Membrane chemical degradation →
Diaphragm cells use porous diaphragms, not polymer membranes; chemical degradation is minimal
ঘ) Formation of sodium chlorate → 
Chlorate forms at high temperatures or very high current densities over time, but mass transport limitation occurs first, making it the primary limitation.

১৭.
In the mercury cell process, the Na-Hg amalgam reacts with water in the decomposer to produce NaOH. Which parameter is crucial to control during this step to prevent explosion?
  1. Temperature and flow rate
  2. Chlorine partial pressure
  3. Cathode surface area
  4. Brine concentration
সঠিক উত্তর:
Temperature and flow rate
উত্তর
সঠিক উত্তর:
Temperature and flow rate
ব্যাখ্যা

In the mercury cell process:

Na-Hg amalgam is formed at the cathode:

Na++e→Na(amalgam)

Decomposer reaction with water produces NaOH and H₂:

2Na(Hg)+2H2O→2NaOH+H2↑+2Hg

Other Options:

                 ​খ) Chlorine partial pressure →
Relevant in the anode compartment, not the decomposer.
                 গ) Cathode surface area →
Affects amalgam formation but not the safety in the decomposer.
                  ঘ) Brine concentration →
Affects electrolysis efficiency but not directly explosion risk during decomposer reaction.

১৮.
In the membrane cell process for caustic soda production, what is the primary reason for using a cation-exchange membrane instead of a diaphragm?
  1. To allow selective migration of hydroxide ions to increase current efficiency
  2. To prevent migration of chloride ions into the catholyte, reducing contamination of NaOH
  3. To facilitate hydrogen gas recombination in the cathode compartment
  4. To increase the brine concentration in the anode compartment for higher chlorine yield
সঠিক উত্তর:
To prevent migration of chloride ions into the catholyte, reducing contamination of NaOH
উত্তর
সঠিক উত্তর:
To prevent migration of chloride ions into the catholyte, reducing contamination of NaOH
ব্যাখ্যা

In the membrane cell process for caustic soda production:
The cation-exchange membrane allows only Na⁺ ions to pass from the anolyte (brine) to the catholyte (where NaOH is formed).
This prevents Cl⁻ ions and OH⁻ ions from migrating across compartments.

As a result:
NaOH solution in the cathode compartment remains pure (without chloride contamination).
Current efficiency improves because unwanted side reactions are minimized.

​Other Options:
​ক) Incorrect: Hydroxide ions (OH⁻) do not migrate through the membrane; only Na⁺ moves. The design is to stop OH⁻ migration, not enhance it.
গ) Incorrect: Hydrogen recombination is not a function of the membrane; it's related to the cathode reaction.
ঘ) Incorrect: The membrane doesn't increase brine concentration; that depends on feed control and circulation, not the membrane.

১৯.
In the mercury cell process, the Na–Hg amalgam formation is crucial. Which factor has the greatest effect on amalgam formation and overall current efficiency?
  1. Cathode overpotential for hydrogen evolution
  2. Chlorine solubility in the catholyte
  3. Anode current density and brine purity
  4. Flow rate of mercury and cell temperature
সঠিক উত্তর:
Anode current density and brine purity
উত্তর
সঠিক উত্তর:
Anode current density and brine purity
ব্যাখ্যা

In the mercury cell process, the formation of the sodium–mercury amalgam at the cathode depends heavily on brine purity and proper anode current density:
Brine purity: Even trace impurities like Ca²⁺, Mg²⁺, Fe, heavy metals, or organics catalyze hydrogen evolution on the mercury surface. This reduces sodium deposition and drastically lowers current efficiency.
Anode current density: If it's too high or too low, side reactions increase, chlorine back-reaction occurs, and energy losses rise—affecting overall efficiency.

​Other Options:
​(ক) Cathode overpotential for hydrogen evolution – This matters, but the biggest factor influencing it is actually brine purity. On its own, it's not the primary determinant of efficiency.
(খ) Chlorine solubility in the catholyte – Less relevant because in the mercury cell, NaOH forms later in a separate decomposer, not in the main cell.
(ঘ) Flow rate of mercury and cell temperature – These affect the transport and concentration of amalgam, but they are optimization factors, not the dominant determinant of current efficiency.

২০.
In a diaphragm cell, why is maintaining a high brine concentration in the anode compartment essential for safe and efficient operation? 
  1. To prevent membrane hydration and swelling
  2. To reduce oxygen evolution and increase chlorine purity
  3. To maintain a positive hydrostatic head preventing backflow of caustic soda into the anode compartment
  4. To minimize the solubility of chlorine in catholyte
সঠিক উত্তর:
To maintain a positive hydrostatic head preventing backflow of caustic soda into the anode compartment
উত্তর
সঠিক উত্তর:
To maintain a positive hydrostatic head preventing backflow of caustic soda into the anode compartment
ব্যাখ্যা

In a diaphragm cell:
The anode and cathode compartments are separated by a porous diaphragm, which is permeable to the brine but not fully selective like a membrane.
To avoid back-migration of caustic soda (NaOH) from the cathode compartment to the anode compartment (where it could react with chlorine, forming hypochlorite or chlorate), a positive hydrostatic pressure on the anode side is maintained.
This is achieved by keeping the brine level slightly higher in the anode compartment.

​Other Options:
​(ক) Incorrect – Diaphragm cells do not use ion-exchange membranes; hydration/swelling is an issue for membrane cells, not diaphragms.
(খ) Incorrect – High brine concentration affects chlorine purity only indirectly; oxygen evolution is controlled by electrode material and overpotential, not brine head.
(ঘ) Incorrect – Chlorine solubility in catholyte is a concern, but the hydrostatic head primarily addresses backflow, not gas solubility.

২১.
In diaphragm cells, why is asbestos or modified polymeric material commonly used for the diaphragm instead of a true ion-exchange membrane?
  1. To permit controlled migration of brine without significant electrical resistance
  2. To reduce chlorine solubility in the anolyte and prevent its transfer to the catholyte
  3. To act as a catalytic surface for hydrogen evolution
  4. To allow only sodium ions to pass while blocking hydroxyl ions completely
সঠিক উত্তর:
To permit controlled migration of brine without significant electrical resistance
উত্তর
সঠিক উত্তর:
To permit controlled migration of brine without significant electrical resistance
ব্যাখ্যা

In diaphragm cells:
The diaphragm is porous (traditionally asbestos, now often modified polymer fibers) and its purpose is not ion-selective like a membrane.
It:
   1. Allows brine to flow from the anode compartment to the cathode compartment.
   2. Prevents rapid mixing of chlorine (from anode) with caustic soda (formed at cathode).
   3. Maintains low electrical resistance to keep energy consumption reasonable.

​Other Options:

​(খ) Incorrect – It does not significantly control chlorine solubility; that depends more on temperature and brine saturation.

(গ) Incorrect – The diaphragm is not a catalyst; hydrogen evolution occurs at the cathode.

(ঘ) Incorrect – That’s the role of a cation-exchange membrane in membrane cells, not a diaphragm.

২২.
Which operational parameter is most critical in mercury cell design to prevent secondary hydrogen evolution at the cathode? 
  1. Maintaining low catholyte pH
  2. Ensuring sufficient mercury depth and proper flow velocity
  3. Operating at high brine temperatures to reduce viscosity
  4. Increasing current density to favor sodium deposition over hydrogen
সঠিক উত্তর:
Ensuring sufficient mercury depth and proper flow velocity
উত্তর
সঠিক উত্তর:
Ensuring sufficient mercury depth and proper flow velocity
ব্যাখ্যা

In a mercury cell, sodium is deposited on the mercury cathode as an amalgam instead of producing hydrogen. To suppress secondary hydrogen evolution, two factors are crucial:

Mercury depth: A deeper mercury layer ensures uniform current distribution and minimizes spots where hydrogen evolution can compete.

Proper mercury flow velocity: Continuous movement of mercury helps remove freshly deposited sodium quickly, preventing its reaction with water and reducing local alkalinity, which favors hydrogen evolution.

২৩.
In membrane cells, the concentration of NaOH is generally limited to 32–35%. What is the primary reason for this limitation? 
  1. Higher concentration increases the solubility of chlorine in NaOH, forming hypochlorite
  2. Increasing concentration drastically raises the viscosity, reducing ion transport
  3. Increased concentration leads to more hydrogen overpotential, reducing efficiency
  4. Higher concentration causes membrane dehydration, reducing its selectivity and life
সঠিক উত্তর:
Higher concentration causes membrane dehydration, reducing its selectivity and life
উত্তর
সঠিক উত্তর:
Higher concentration causes membrane dehydration, reducing its selectivity and life
ব্যাখ্যা

In membrane cell technology:
The ion-exchange membrane relies on being fully hydrated to maintain ionic conductivity and selectivity (allowing Na⁺ to pass, blocking OH⁻ and Cl⁻).
When NaOH concentration exceeds ~32–35%, water activity in the catholyte drops sharply, causing membrane dehydration.
Dehydration → loss of ion-exchange sites, increase in resistance, and mechanical shrinkage, ultimately damaging the membrane and lowering efficiency.

​​Other Options:

​(ক) Hypochlorite formation due to chlorine solubility happens if chlorine and NaOH mix, but in membrane cells, chlorine and NaOH are in separate compartments, so it’s not the primary limitation.
(খ) Viscosity does rise with concentration, but pumping and ion transport are still manageable; membrane stability is the real bottleneck.
(গ) Hydrogen overpotential does increase slightly, but it’s a minor effect compared to membrane failure risk.

২৪.
In the mercury process, the decomposer converts Na–Hg amalgam to NaOH. Which reaction condition must be tightly controlled to prevent hazardous conditions?
  1. High brine concentration in the decomposer to reduce Na loss
  2. Low amalgam flow rate to minimize mercury entrainment
  3. Excessive temperature rise and improper water addition rate
  4. High chlorine partial pressure in the decomposer to suppress hydrogen evolution
সঠিক উত্তর:
Excessive temperature rise and improper water addition rate
উত্তর
সঠিক উত্তর:
Excessive temperature rise and improper water addition rate
ব্যাখ্যা

In the mercury process, the decomposer (also called denuder) reacts sodium–mercury amalgam with water to form NaOH and hydrogen gas:
2Na(Hg)+2H2O→2NaOH+H2↑+Hg

This reaction is highly exothermic.
If temperature rises uncontrollably or water is added too rapidly, it can cause:
1. Rapid hydrogen evolution, leading to an explosion hazard.
2. Local overheating, damaging equipment and increasing mercury vaporization (toxic risk).

Hence, careful control of water addition and heat removal is critical.

২৫.
Comparing diaphragm, mercury, and membrane processes, which statement is most accurate regarding energy consumption and product purity? 
  1. Mercury cells have the lowest energy consumption and produce the purest NaOH
  2. Membrane cells consume less energy than mercury cells and produce high-purity NaOH
  3. Diaphragm cells consume the least energy but produce the most contaminated NaOH
  4. Membrane cells require the highest energy but eliminate brine treatment
সঠিক উত্তর:
Membrane cells consume less energy than mercury cells and produce high-purity NaOH
উত্তর
সঠিক উত্তর:
Membrane cells consume less energy than mercury cells and produce high-purity NaOH
ব্যাখ্যা

Membrane cells are designed with a cation-exchange membrane that prevents chloride ions from migrating into the cathode compartment, allowing the production of high-purity NaOH (low Cl⁻ content, around 32–35%).
Their design also minimizes electrical losses, so energy consumption is lower compared to mercury cells.
Mercury cells produce very pure NaOH as well, but the process consumes more energy and has significant environmental and safety concerns due to mercury handling.
Diaphragm cells use a porous diaphragm, which allows some mixing of chlorine and caustic soda, producing lower-purity NaOH. Although their energy consumption is moderate, the product typically contains NaCl and requires further purification if high purity is needed.

২৬.
Which of the following is a key advantage of producing caustic soda via electrolysis of brine compared to the lime-soda process for NaOH production? 
  1. Produces NaOH at lower temperatures with minimal CO2 emissions
  2. Requires less water but produces lower-purity NaOH
  3. Generates Na2CO3 as a by-product instead of chlorine
  4. Avoids the use of hazardous electrolytes entirely
সঠিক উত্তর:
Produces NaOH at lower temperatures with minimal CO2 emissions
উত্তর
সঠিক উত্তর:
Produces NaOH at lower temperatures with minimal CO2 emissions
ব্যাখ্যা

Electrolysis of brine directly converts NaCl into NaOH, Cl₂, and H₂ at ambient or slightly elevated temperatures, without using limestone or generating CO₂.
This is a major advantage over the lime-soda process, which involves:
1. Heating Na₂CO₃ with Ca(OH)₂ to produce NaOH.
2. Significant CO₂ release from lime (CaCO₃ → CaO + CO₂) and higher energy input due to high temperatures.

The electrolysis route also produces valuable by-products (chlorine and hydrogen) rather than just Na₂CO₃.
 Other Options:​

​(খ) Incorrect – Electrolysis actually produces high-purity NaOH; water consumption is moderate, but purity is higher, not lower.
(গ) Incorrect – Na₂CO₃ is not a by-product; chlorine and hydrogen are.
(ঘ) Incorrect – Electrolysis uses concentrated brine (NaCl solution) and sometimes caustic electrolyte handling, so “avoiding hazardous electrolytes entirely” is not accurate.

২৭.
Why is chemical resistance an essential property for the cation-exchange membrane in a membrane cell? 
  1. To maintain brine concentration in the anode compartment
  2. To facilitate hydrogen recombination at the cathode
  3. To allow selective OH⁻ transport to the anode
  4. To withstand highly corrosive NaOH and chlorine environments without degradation
সঠিক উত্তর:
To withstand highly corrosive NaOH and chlorine environments without degradation
উত্তর
সঠিক উত্তর:
To withstand highly corrosive NaOH and chlorine environments without degradation
ব্যাখ্যা

In a membrane cell, the cation-exchange membrane separates the anode (chlorine evolution) and cathode (NaOH and H₂ evolution) compartments.

The membrane is constantly exposed to highly corrosive chemicals: concentrated NaOH on the cathode side and chlorine/brine on the anode side.

Chemical resistance ensures that the membrane maintains its structural integrity, selectivity, and longevity under these harsh conditions.

The membrane allows Na⁺ ions to pass but blocks OH⁻ and Cl⁻; it does not transport OH⁻ to the anode, nor is its primary function related to hydrogen recombination or maintaining brine concentration.

২৮.
In a diaphragm cell, what operational condition primarily prevents caustic soda from back-diffusing into the anode compartment?
  1. Increasing current density
  2. Cooling the catholyte
  3. Using a cation-selective diaphragm
  4. Maintaining a positive hydrostatic head in the anode compartment
সঠিক উত্তর:
Maintaining a positive hydrostatic head in the anode compartment
উত্তর
সঠিক উত্তর:
Maintaining a positive hydrostatic head in the anode compartment
ব্যাখ্যা

In a diaphragm cell, the diaphragm separates the anode (chlorine evolution) and cathode (NaOH and H₂ evolution) compartments.

A positive hydrostatic head (higher brine level in the anode compartment) ensures that the flow of solution is from anode to cathode through the diaphragm.

This prevents the back-diffusion of caustic soda (OH⁻) into the anode compartment, which would otherwise react with chlorine and reduce current efficiency or create safety hazards.

Using a cation-selective diaphragm is a feature of membrane cells, not conventional diaphragm cells. Increasing current density or cooling the catholyte does not prevent backflow.

২৯.
Which of the following factors allows membrane cells to consume less energy than mercury and diaphragm cells? 
  1. Direct generation of Na2CO3 as a co-product
  2. Higher NaOH concentration (~50%) reduces current
  3. Lower voltage requirement due to reduced brine concentration
  4. Absence of mercury handling and decomposer step
সঠিক উত্তর:
Absence of mercury handling and decomposer step
উত্তর
সঠিক উত্তর:
Absence of mercury handling and decomposer step
ব্যাখ্যা

Membrane cells produce NaOH directly in the cathode compartment without forming a Na–Hg amalgam.

Mercury cells require an additional decomposer step to convert Na–Hg amalgam into NaOH, which consumes extra energy.

Diaphragm cells produce lower-concentration NaOH and require additional purification or evaporation, increasing energy consumption.

By eliminating the mercury handling and decomposer step, membrane cells reduce both energy usage and environmental hazards, making them more efficient.

৩০.
Which of the following correctly ranks chlor-alkali processes in terms of NaOH purity from highest to lowest? 
  1. Mercury > Membrane > Diaphragm
  2. Mercury > Diaphragm > Membrane
  3. Membrane > Mercury > Diaphragm
  4. Diaphragm > Membrane > Mercury
সঠিক উত্তর:
Mercury > Membrane > Diaphragm
উত্তর
সঠিক উত্তর:
Mercury > Membrane > Diaphragm
ব্যাখ্যা

Mercury cells produce ultra-pure NaOH with chloride content <0.001%, the highest among all processes.

Membrane cells produce high-purity NaOH (~32–35%) with very low chloride contamination.

Diaphragm cells produce moderate-purity NaOH (~10–12%) containing significant NaCl, which may require further purification for industrial use.

Summary Ranking of NaOH Purity:
Mercury > Membrane > Diaphragm

৩১.
In the lime-soda process for NaOH production, which factor primarily limits the yield of NaOH?
  1. Solubility of Na2CO3 in water
  2. Particle size of Ca(OH)2
  3. Reaction temperature and residence time
  4. Presence of Mg2+ and Ca2+ impurities
সঠিক উত্তর:
Presence of Mg2+ and Ca2+ impurities
উত্তর
সঠিক উত্তর:
Presence of Mg2+ and Ca2+ impurities
ব্যাখ্যা

The lime-soda (causticization) process involves treating sodium carbonate (Na₂CO₃) with slaked lime (Ca(OH)₂) to produce NaOH:
Na2​CO3​+Ca(OH)2​→2NaOH+CaCO3​
Magnesium (Mg²⁺) and excess calcium (Ca²⁺) ions in the feedwater or soda can form insoluble hydroxides or double salts, which:
     1. Precipitate before reacting completely,
     2. Reduce NaOH yield, and
     3. Cause operational difficulties like scaling.

Other Options:
ক) Solubility of Na₂CO₃ in water → Na₂CO₃ is highly soluble; not a limiting factor.
খ) Particle size of Ca(OH)₂ → Affects reaction rate slightly, but not the primary yield limitation.
গ) Reaction temperature and residence time → Mildly affects kinetics, but yield is mainly limited by impurities.

৩২.
Which raw material combination is typically used in the Solvay process for industrial-scale soda ash production?
  1. Na2SO4 + CaCO3
  2. NaCl + CaCO3
  3. NaCl + Na2CO3
  4. Na2CO3 + Ca(OH)2
সঠিক উত্তর:
NaCl + CaCO3
উত্তর
সঠিক উত্তর:
NaCl + CaCO3
ব্যাখ্যা

1.The Solvay process is the most common industrial method for producing sodium carbonate (soda ash, Na₂CO₃).
2.The key raw materials are:
     Sodium chloride (NaCl) – common salt
     Calcium carbonate (CaCO₃) – limestone
3.The overall sequence involves:
Ammonia absorption in brine (NaCl solution).
Reaction with CO₂ (from calcined limestone, CaCO₃ → CaO + CO₂) to precipitate NaHCO₃.
Thermal decomposition of NaHCO₃ to Na₂CO₃.
                 2NaCl+CaCO3→Na₂CO₃+CaCl₂ 

Other Options:
ক) Na₂SO₄ + CaCO₃ →
Used in Leblanc process, not Solvay.
গ) NaCl + Na₂CO₃ →
Na₂CO₃ is the product, not a raw material.
ঘ) Na₂CO₃ + Ca(OH)₂ →
Used in lime-soda process for NaOH, not Solvay soda ash.

৩৩.
which side product can be environmentally problematic if not handled properly?
  1. NaHCO3
  2. CO2
  3. NH4Cl
  4. Na2CO3·H2O
সঠিক উত্তর:
NH4Cl
উত্তর
সঠিক উত্তর:
NH4Cl
ব্যাখ্যা

In the Solvay process, ammonia is used to absorb CO₂ and precipitate sodium bicarbonate (NaHCO₃), which is later calcined to produce soda ash (Na₂CO₃). However, during regeneration of ammonia using Ca(OH)₂, ammonium chloride (NH₄Cl) is produced as a by-product.
1.NH₄Cl is highly soluble in water and can cause severe water pollution and soil contamination if discharged without treatment.
2.The usual practice is to convert NH₄Cl into fertilizers like ammonium sulfate (NH₄)₂SO₄) or use recovery systems.

Other Options:
ক)NaHCO₃ → Main intermediate, not a pollutant.
খ)CO₂ → Recycled in the process, minimal emission if well-controlled.
ঘ)Na₂CO₃·H₂O → Hydrated soda ash, a product, not a pollutant.

৩৪.
In the lime-soda process, why is a large excess of Ca(OH)2 often used?
  1. To improve crystallization of NaOH
  2. To reduce reaction time
  3. To increase the solubility of Na2CO3
  4. To ensure complete conversion of Na2CO3 to NaOH
সঠিক উত্তর:
To ensure complete conversion of Na2CO3 to NaOH
উত্তর
সঠিক উত্তর:
To ensure complete conversion of Na2CO3 to NaOH
ব্যাখ্যা

In the lime-soda process, the main reaction is:
Na2CO3+Ca(OH)2⟶2NaOH+CaCO3

1. Ca(OH)₂ (lime) is sparingly soluble, so the reaction is heterogeneous.
2. If the amount of Ca(OH)₂ is just stoichiometric, some Na₂CO₃ might remain unreacted because of incomplete contact and equilibrium limitations.
3. Adding excess Ca(OH)₂ shifts the equilibrium to the right, ensuring almost all Na₂CO₃ converts to NaOH.

Other Options:
ক) Improve crystallization of NaOH → NaOH remains in solution; no crystallization occurs during the main reaction.
খ) Reduce reaction time → Excess Ca(OH)₂ might speed up the reaction slightly, but the main reason is not time, it’s completeness.
গ) Increase the solubility of Na₂CO₃ → Solubility of Na₂CO₃ is not influenced by Ca(OH)₂.

৩৫.
In an industrial diaphragm cell, which phenomenon primarily limits the achievable NaOH concentration beyond ~12%?
  1. OH- back-diffusion
  2. Chlorine solubility in catholyte
  3. Membrane dehydration
  4. Hydrogen overpotential
সঠিক উত্তর:
OH- back-diffusion
উত্তর
সঠিক উত্তর:
OH- back-diffusion
ব্যাখ্যা

In a diaphragm cell:
1.The anode side generates Cl₂ gas, and the cathode side produces NaOH solution + H₂ gas.
2.The diaphragm is porous, allowing brine to pass but not gases.
3.As NaOH concentration rises in the catholyte, the concentration gradient for OH⁻ ions increases.
4.Beyond about 10–12% NaOH, OH⁻ back-diffuses through the diaphragm to the anode compartment.
5.There, OH⁻ reacts with Cl₂, forming hypochlorite (ClO⁻) and chlorate (ClO₃⁻):
           Cl2+2OH→Cl+ClO+H2O
This reduces NaOH yield and causes contamination.

Other Options:
খ) Chlorine solubility in catholyte → Leads to contamination and safety risks, but not the main concentration limit.
গ) Membrane dehydration → Relevant for membrane cells, not diaphragm cells.
ঘ) Hydrogen overpotential → Impacts energy efficiency, not concentration limitation.

৩৬.
Which factor most strongly affects the cell voltage in a mercury cell?
  1. Brine concentration and anode-cathode distance
  2. Catholyte temperature
  3. Membrane ion selectivity
  4. Mercury purity
সঠিক উত্তর:
Brine concentration and anode-cathode distance
উত্তর
সঠিক উত্তর:
Brine concentration and anode-cathode distance
ব্যাখ্যা

In a mercury cell process for caustic soda production:
1.The anode is usually titanium or graphite, and the cathode is a flowing layer of mercury.
2.Sodium ions are reduced at the mercury cathode to form sodium amalgam, which is later decomposed to NaOH.
The cell voltage depends on:
1. Brine concentration:
      Higher brine concentration = higher conductivity = lower resistance = lower cell voltage.
      As brine gets depleted, resistance rises, and cell voltage increases.
2. Anode-cathode distance:
     This is crucial because the mercury cathode layer is mobile and the gap affects the ohmic resistance of the electrolyte.

Greater distance → higher resistance → higher cell voltage.


Other Options:
খ) Catholyte temperature → Affects kinetics slightly, but the mercury cell operates at nearly constant temperature; not the dominant factor.
গ) Membrane ion selectivity → There is no membrane in mercury cells (applies to membrane cells).
ঘ) Mercury purity → Important for amalgam stability, but has negligible effect on cell voltage compared to brine concentration and gap.

৩৭.
In a membrane cell, the selectivity of the cation-exchange membrane ensures that:
  1. Only OH- ions move to the cathode
  2. Only Na+ ions migrate from anode to cathode
  3. Cl- ions are recombined at the cathode
  4. H2 gas is absorbed in the membrane
সঠিক উত্তর:
Only Na+ ions migrate from anode to cathode
উত্তর
সঠিক উত্তর:
Only Na+ ions migrate from anode to cathode
ব্যাখ্যা

In a membrane cell for chlor-alkali production:
1.The anode compartment contains brine (NaCl solution), where Cl₂ gas evolves.
2.The cathode compartment produces H₂ gas and NaOH solution.
3.A cation-exchange membrane (usually perfluorinated sulfonic polymer like Nafion) separates the compartments.
The membrane is selective for cations (Na⁺), so:
   1. Na⁺ ions migrate through the membrane to the cathode side.
   2. Cl⁻ ions and OH⁻ ions are blocked to prevent:
              Cl⁻ migration → which would contaminate NaOH.
              OH⁻ back-diffusion → which would cause side reactions (chlorate formation).

Other Options:
ক) Only OH⁻ ions move to the cathode → OH⁻ cannot cross the membrane; that’s the whole point.
গ) Cl⁻ ions are recombined at the cathode → Cl⁻ stays on the anode side to form Cl₂, not recombine at the cathode.
ঘ) H₂ gas is absorbed in the membrane → H₂ forms at the cathode and bubbles out; membrane does not absorb it.

৩৮.
Which condition must be controlled to prevent hypochlorite formation in diaphragm cells?
  1. Anode temperature
  2. Mercury depth
  3. Cathode overpotential
  4. Brine purity and current density
সঠিক উত্তর:
Brine purity and current density
উত্তর
সঠিক উত্তর:
Brine purity and current density
ব্যাখ্যা

In a diaphragm cell, hypochlorite (ClO⁻) forms when Cl₂ reacts with OH⁻ in the electrolyte:
 Cl2 + 2OH⟶ Cl+ ClO+ H2O
the following conditions are critical:
1.Brine purity:
    Impurities like Fe, Mg, and Ca increase side reactions and reduce current efficiency, promoting hypochlorite formation.
2.Current density:
    If too low → less Cl₂ evolution rate relative to OH⁻ accumulation → more time for Cl₂ to dissolve and react with OH⁻.
    If too high → other issues, but generally, proper current density helps maintain efficient Cl₂ evolution and limits its contact with OH⁻.

Other Options:
ক) Anode temperature → Temperature does affect reaction kinetics, but it is not the primary control factor for hypochlorite formation.
খ) Mercury depth → Relevant to mercury cells, not diaphragm cells.
গ) Cathode overpotential → Influences energy efficiency, not directly hypochlorite formation.

৩৯.
In electrolysis of brine, increasing temperature generally affects chlorine evolution efficiency by:
  1. Increasing overpotential at the cathode
  2. Decreasing chlorine solubility at the anode
  3. Accelerating side reactions forming oxygen
  4. Reducing NaOH solubilit
সঠিক উত্তর:
Accelerating side reactions forming oxygen
উত্তর
সঠিক উত্তর:
Accelerating side reactions forming oxygen
ব্যাখ্যা
When the temperature increases during brine electrolysis:
1.The oxygen evolution reaction (OER) at the anode and side reactions forming hypochlorite or chlorate accelerate.
2.This leads to a reduction in chlorine current efficiency, even though chlorine solubility decreases slightly with temperature.
3.Other options are less relevant:
        Cathode overpotential usually decreases slightly with temperature.
        NaOH solubility actually increases with temperature, not decreases.
৪০.
In diaphragm cells, what is the main reason for using porous asbestos or polymer diaphragms instead of a solid insulating barrier?
  1. To catalyze chlorine formation
  2. To prevent any ion migration
  3. To allow brine flow while separating Cl₂ and NaOH
  4. To enhance hydrogen recombination
সঠিক উত্তর:
To allow brine flow while separating Cl₂ and NaOH
উত্তর
সঠিক উত্তর:
To allow brine flow while separating Cl₂ and NaOH
ব্যাখ্যা
In a diaphragm cell:
1.The anode produces Cl₂ gas, and the cathode produces NaOH solution + H₂ gas.
2.A solid barrier would block ion movement, stopping the reaction.
3.A porous diaphragm (asbestos or polymer) allows:
     Brine (Na⁺ and Cl⁻ ions) to flow from anode to cathode side.
     Separation of Cl₂ and NaOH to prevent immediate reaction between them.

Other Options:
ক) To catalyze chlorine formation → Diaphragm is not a catalyst; the anode surface catalyzes Cl₂ evolution.
খ) To prevent any ion migration → Actually, it allows Na⁺ migration; it’s not a complete barrier.
ঘ) To enhance hydrogen recombination → Not relevant; hydrogen is collected separately.
৪১.
Which process produces NaOH with the highest concentration without additional evaporation?
  1. Diaphragm cell
  2. Mercury cell
  3. Membrane cell
  4. Lime-soda process
সঠিক উত্তর:
Mercury cell
উত্তর
সঠিক উত্তর:
Mercury cell
ব্যাখ্যা
Diaphragm cell: Produces NaOH around 12% maximum due to OH⁻ back-diffusion through the porous diaphragm.
Membrane cell: Produces 30–32% NaOH, but usually requires some evaporation to reach higher commercial concentrations.
Mercury cell: Can directly produce ~50% NaOH without additional evaporation because sodium forms an amalgam with mercury, which is then decomposed to a concentrated NaOH solution.
Lime-soda process: Produces NaOH in solution; concentration is limited (~20–25%) and often requires evaporation.
৪২.
Which of the following is a major environmental concern specific to mercury cells?
  1. Ammonia loss
  2. Hypochlorite formation
  3. Mercury contamination
  4. Excess NaOH in effluent
সঠিক উত্তর:
Mercury contamination
উত্তর
সঠিক উত্তর:
Mercury contamination
ব্যাখ্যা
1.Mercury cells use liquid mercury as the cathode, forming a sodium-mercury amalgam.
2.Environmental concern:
   Mercury is highly toxic.
   Spillage or improper disposal can contaminate water and soil, affecting humans and wildlife.

Other Options:
ক) Ammonia loss → Relevant to the Solvay process, not mercury cells.
খ) Hypochlorite formation → Common in diaphragm cells due to Cl₂–OH⁻ reactions.
ঘ) Excess NaOH in effluent → Can occur in any caustic production process if wastewater is not treated, not specific to mercury cells.
৪৩.
In membrane cells, which operational factor is most critical to prevent membrane damage?
  1. Current density
  2. Catholyte NaOH concentration
  3. Brine flow rate
  4. Chlorine partial pressure
সঠিক উত্তর:
Catholyte NaOH concentration
উত্তর
সঠিক উত্তর:
Catholyte NaOH concentration
ব্যাখ্যা
In a membrane cell:
1.The cation-exchange membrane allows Na⁺ ions to pass but blocks OH⁻ and Cl⁻.
2.High NaOH concentration at the membrane surface can chemically attack the polymer, causing membrane degradation or failure.
3.Therefore, controlling the NaOH concentration in the catholyte near the membrane is critical for long-term operation.

Other Options:
ক) Current density → Affects efficiency and energy consumption, but not the main cause of membrane damage.
গ) Brine flow rate → Important for Na⁺ supply and cooling, but excess NaOH at the membrane is more damaging.
ঘ) Chlorine partial pressure → Cl₂ is on the anode side; the membrane is not exposed to high Cl₂.
৪৪.
Why is hydrogen evolution minimal in mercury cells at the cathode?
  1. High brine concentration suppresses H2
  2. Sodium forms amalgam with mercury, preventing direct H2 evolution
  3. Membrane selectively blocks OH-
  4. Diaphragm restricts water reduction
সঠিক উত্তর:
Sodium forms amalgam with mercury, preventing direct H2 evolution
উত্তর
সঠিক উত্তর:
Sodium forms amalgam with mercury, preventing direct H2 evolution
ব্যাখ্যা

In a mercury cell:
1.The cathode is liquid mercury.
2.Instead of water being reduced to H₂ at the cathode, sodium ions are reduced to sodium metal, which immediately forms a sodium-mercury amalgam.
3.This prevents direct hydrogen evolution, allowing sodium to be safely transported in the amalgam to a separate decomposition vessel where it reacts with water to produce NaOH and H₂ in a controlled manner.

Other Options:
ক) High brine concentration suppresses H₂ → Minor effect; the main mechanism is amalgam formation.
গ) Membrane selectively blocks OH⁻ → Applies to membrane cells, not mercury cells.
ঘ) Diaphragm restricts water reduction → Applies to diaphragm cells, not mercury cells.

৪৫.
Which process generally requires the least downstream purification of NaOH?
  1. Diaphragm cell
  2. Mercury cell
  3. Membrane cell
  4. Lime-soda process
সঠিক উত্তর:
Membrane cell
উত্তর
সঠিক উত্তর:
Membrane cell
ব্যাখ্যা
Membrane cell:
Uses a cation-exchange membrane that allows only Na⁺ ions to pass to the cathode side.
Cl⁻ and other impurities are blocked, so the NaOH solution is highly pure.
Minimal downstream purification (filtration or treatment) is needed.
Diaphragm cell:
Produces NaOH with suspended salts (NaCl, Na₂CO₃), requiring filtration or evaporation.
Mercury cell:
Produces NaOH from sodium amalgam, which may contain trace mercury, so extra purification is needed.
Lime-soda process:
Produces NaOH containing CaCO₃ and other solids, requiring filtration and purification.
৪৬.
The formation of sodium amalgam in mercury cells is most sensitive to:
  1. Cathode surface area and brine purity
  2. Chlorine solubility
  3. Diaphragm porosity
  4. Membrane selectivity
সঠিক উত্তর:
Cathode surface area and brine purity
উত্তর
সঠিক উত্তর:
Cathode surface area and brine purity
ব্যাখ্যা
In a mercury cell:
1.The cathode is liquid mercury, where sodium ions are reduced to form sodium-mercury amalgam.
2.The efficiency and rate of amalgam formation depend strongly on:
       Cathode surface area – Larger surface allows more sodium to be reduced efficiently.
       Brine purity – Impurities (like Mg²⁺, Ca²⁺, Fe³⁺) can deposit on the mercury surface, poisoning the cathode and hindering amalgam formation.

Other Options:
খ) Chlorine solubility → Affects Cl₂ evolution but not directly amalgam formation.
গ) Diaphragm porosity → Relevant to diaphragm cells, not mercury cells.
ঘ) Membrane selectivity → Relevant to membrane cells, not mercury cells.
৪৭.
Compared to diaphragm cells, membrane cells achieve higher current efficiency mainly because:
  1. They operate at lower temperatures
  2. Mercury is used as the cathode
  3. OH⁻ back-diffusion is blocked
  4. Chlorine solubility is higher
সঠিক উত্তর:
OH⁻ back-diffusion is blocked
উত্তর
সঠিক উত্তর:
OH⁻ back-diffusion is blocked
ব্যাখ্যা
In membrane cells:
1.A cation-exchange membrane separates the anode and cathode compartments.
2.The membrane allows only Na⁺ ions to pass, while blocking OH⁻ ions from diffusing back to the anode side.
3.This prevents the parasitic reaction where OH⁻ reacts with Cl₂ to form hypochlorite/chlorate.
4.As a result, current efficiency is higher compared to diaphragm cells, where OH⁻ back-diffusion occurs due to the porous diaphragm.

Other Options:
ক) Lower temperatures → Helps slightly with side reactions but is not the main reason.
খ) Mercury cathode → Relevant only to mercury cells.
ঘ) Chlorine solubility → Affects gas handling but not current efficiency directly.
৪৮.
In diaphragm cells, why is a positive hydrostatic head maintained in the anode compartment?
  1. To increase NaOH concentration
  2. To prevent back-diffusion of NaOH to the anode
  3. To reduce chlorine evolution
  4. To enhance hydrogen recombination
সঠিক উত্তর:
To prevent back-diffusion of NaOH to the anode
উত্তর
সঠিক উত্তর:
To prevent back-diffusion of NaOH to the anode
ব্যাখ্যা
In diaphragm cells:
1.The anode compartment produces Cl₂, and the cathode compartment produces NaOH + H₂.
2.The diaphragm is porous, so NaOH from the cathode side could diffuse back into the anode compartment.
3.Maintaining a positive hydrostatic head (slightly higher liquid level) in the anode compartment:
     Creates a pressure gradient that prevents NaOH solution from flowing back.
     Minimizes OH⁻ back-diffusion, which would otherwise reduce efficiency and promote side reactions (hypochlorite formation).

Other Options:
ক) Increase NaOH concentration → Head doesn’t directly concentrate NaOH.
গ) Reduce chlorine evolution → Cl₂ generation depends on current and brine concentration, not head.
ঘ) Enhance hydrogen recombination → Not relevant in diaphragm cells.
৪৯.
Which of the following is a key design advantage of membrane cells over mercury cells?
  1. Avoids toxic mercury handling
  2. Lower capital cost
  3. Can operate at higher NaOH concentrations than mercury cells
  4. Produces sodium amalgam for further reactions
সঠিক উত্তর:
Avoids toxic mercury handling
উত্তর
সঠিক উত্তর:
Avoids toxic mercury handling
ব্যাখ্যা
1.Membrane cells use a cation-exchange membrane instead of liquid mercury as the cathode.
2.This eliminates the need for mercury, which is toxic and environmentally hazardous, a major concern in mercury cell operations.

Other Options:
খ) Lower capital cost → Membrane cells are generally more expensive to build than mercury cells.
গ) Higher NaOH concentration than mercury cells → Mercury cells can produce more concentrated NaOH (~50%), whereas membrane cells typically produce 30–32%.
ঘ) Produces sodium amalgam → This is a feature specific to mercury cells, not membrane cells.
৫০.
During operation of diaphragm cells, what is the main effect of impurities such as Ca2+ and Mg2+ in brine?
  1. Increase chlorine purity
  2. Reduce current efficiency and deposit in diaphragm pores
  3. Promote NaOH crystallization
  4. Enhance hydrogen evolution
সঠিক উত্তর:
Reduce current efficiency and deposit in diaphragm pores
উত্তর
সঠিক উত্তর:
Reduce current efficiency and deposit in diaphragm pores
ব্যাখ্যা

In diaphragm cells:
1.The diaphragm is porous to allow ionic flow but prevent mixing of Cl₂ and NaOH.
2.Impurities like Ca²⁺ and Mg²⁺ in the brine:
     React with OH⁻ to form insoluble hydroxides (Ca(OH)₂, Mg(OH)₂).
     These deposit in the diaphragm pores, blocking ion flow.
      Result: Reduced current efficiency, increased cell resistance, and lower NaOH yield.

Other Options:
ক) Increase chlorine purity → Impurities do not improve Cl₂ purity; they mainly hinder the process.
গ) Promote NaOH crystallization → Unrelated; deposits mainly block pores.
ঘ) Enhance hydrogen evolution → Not significant; hydrogen evolution is mostly controlled by cathode potential.