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A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 42, the how old is A?
ব্যাখ্যা
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 42, the how old is A?
Solution:
Let,
C is = x years old
B is 2x years old
A is (2x + 2) years old
Now,
2x + 2x + 2 + x = 42
⇒ 5x + 2 = 42
⇒ 5x = 40
∴ x = 8
A is (2 × 8) + 2 years old
= 16 + 2 years old
= 18 years old
Solution:
Let,
C is = x years old
B is 2x years old
A is (2x + 2) years old
Now,
2x + 2x + 2 + x = 42
⇒ 5x + 2 = 42
⇒ 5x = 40
∴ x = 8
A is (2 × 8) + 2 years old
= 16 + 2 years old
= 18 years old