পরীক্ষা আর্কাইভ

ব্যাংক নিয়োগ প্রস্তুতি ⎯ লং কোর্স

পরীক্ষাব্যাংক নিয়োগ প্রস্তুতি ⎯ লং কোর্সতারিখতারিখ অনির্ধারিতসময়38 minutes৩৪ বৈধ · অসম্পূর্ণ
মোট প্রশ্ন৩৫
সিলেবাস
বিষয়ভিত্তিক সম্পূর্ণ সিলেবাস: সাধারণ গণিত (৩৫) [২০২১ সাল ভিত্তিক ০৭টি ব্যাংকে 'অফিসার (ক্যাশ)/অফিসার (টেলর)' পরীক্ষার জন্য]
ঘনত্ব
উত্তর
উত্তরিতবর্তমানপুনরায় দেখুনঅসম্পূর্ণ

ব্যাংক নিয়োগ প্রস্তুতি ⎯ লং কোর্স

ব্যাংক নিয়োগ প্রস্তুতি ⎯ লং কোর্স · তারিখ অনির্ধারিত · ৩৫ প্রশ্ন

.
How many prime numbers are there from 1 to 50?
  1. 13
  2. 14
  3. 15
  4. None of the above
সঠিক উত্তর:
15
উত্তর
সঠিক উত্তর:
15
ব্যাখ্যা
Question: How many prime numbers are there from 1 to 50?

Solution:
মৌলিক সংখ্যা:
১ এর চেয়ে বড় যে সকল সংখ্যাকে শুধু ১ এবং ঐ সংখ্যা ছাড়া আর কোনো সংখ্যা দ্বারা ভাগ করা যায় না, তাদেরকে মৌলিক সংখ্যা বলে। অর্থাৎ মৌলিক সংখ্যার উৎপাদক হবে দুইটি: ১ এবং শুধুমাত্র সেই সংখ্যাটি।

১ থেকে ৫০ পর্যন্ত মোট মৌলিক সংখ্যা ১৫টি। এগুলো হলো  ⇒ ২, ৩, ৫, ৭, ১১, ১৩, ১৭, ১৯, ২৩, ২৯, ৩১, ৩৭, ৪১, ৪৩, ৪৭।
.
If a + b = 7 and ab = 12, then what is 1/a + 1/b?
  1. 19
  2. 5
  3. 5/12
  4. 7/12
সঠিক উত্তর:
7/12
উত্তর
সঠিক উত্তর:
7/12
ব্যাখ্যা
Question: If a + b = 7 and ab = 12, then what is 1/a + 1/b?

Solution:
1/a + 1/b
= (b + a)/ab
= (a + b)/(ab)
= 7/12
.
Sum of 4 consecutive even numbers is (P + 12) and there are 4 consecutive odd numbers in which 2nd highest number is 37 more than the 2nd lowest even number in the previous series. Sum of the Highest number of both series is 105. Find the value of P.
  1. 116
  2. 122
  3. 124
  4. 118
অনির্ধারিত
ব্যাখ্যা

প্রশ্নটির লজিকে ভুল থাকায় প্রশ্নটি বাতিল করা হলো।
------------------------

Question: Sum of 4 consecutive even numbers is (P + 12) and there are 4 consecutive odd numbers in which 2nd highest number is 37 more than the 2nd lowest even number in the previous series. Sum of the Highest number of both series is 105. Find the value of P.
Solution:
Consecutive even numbers = (x - 3), (x - 1), (x + 1), (x + 3)
∴ x - 3 + x - 1 + x + 1 + x + 3 = P + 12
⇒ 4x = P + 12 ...............(1)

2nd lowest even number = (x - 1)
∴ (x - 1) + 37 = (x + 36) = 2nd highest odd number

Consecutive odd numbers = (x + 38), (x + 36), (x + 34) and (x + 32)
∴ (x + 3) + (x + 38) = 105
⇒ 2x + 41 = 105
⇒ 2x = 64
∴ x = 32

Now from (1),
4 × 32 = (P + 12)
⇒ 128 = (P + 12)
∴ P = 116

.
In an examination, 41% of students failed in Economics, 35% of students failed in Geography and 39% of students failed in History, 5% of students failed in all the three subjects, 14% of students failed in Economics and Geography, 21% of students failed in Geography and History and 18% of students failed in History and Economics. Find the percentage of students who failed in only Economics.
  1. 16%
  2. 14%
  3. 12%
  4. 10%
সঠিক উত্তর:
14%
উত্তর
সঠিক উত্তর:
14%
ব্যাখ্যা
Question: In an examination, 41% of students failed in Economics, 35% of students failed in Geography and 39% of students failed in History, 5% of students failed in all the three subjects, 14% of students failed in Economics and Geography, 21% of students failed in Geography and History and 18% of students failed in History and Economics. Find the percentage of students who failed in only Economics.

Solution:

Now,
e = 5%
b + e = 14%
⇒ b = 9%

and, d + e = 18%
⇒ d = 13%
Therefore, Percentage of students who failed only in Economics = a = 41% - (b + e + d)
⇒ a = 41% - (9 + 5 + 13)%
⇒ a = 41% - 27%
⇒ a = 14%
Hence, 14% is the correct answer.
.
What is the remainder when 337 is divided by 10?
  1. 1
  2. 3
  3. 6
  4. 7
সঠিক উত্তর:
3
উত্তর
সঠিক উত্তর:
3
ব্যাখ্যা
Question: What is the remainder when 337 is divided by 10?

Solution:
When dividing a positive integer by 10, the remainder is always the units digit of that integer. For instance, 123 divided by 10 yields the remainder of 3. Hence, essentially we need to find the units digit of 337.
 
For that,
we can use the cyclicity of 3 in positive integer power, which is four, meaning that the units digit of 3 in positive integer power repeats in blocks of four {3, 9, 7, 1}{3, 9, 7, 1}...
31 = 3
32 = 9
33 = 27
34 = 81
35 = 243
...

The power, 37, is 1 greater than a multiple of 4, so the units digit of 337 will be the first number in the cyclicity block, which is 3, giving the remainder of 3 when divided by 10.
.
A parking garage rents parking spaces for Tk. 10 per week or Tk. 30 per month. How much does a person save in a year by renting by the month rather than by the week?
  1. Tk. 140
  2. Tk. 160
  3. Tk. 220
  4. Tk. 240
সঠিক উত্তর:
Tk. 160
উত্তর
সঠিক উত্তর:
Tk. 160
ব্যাখ্যা
Question: A parking garage rents parking spaces for Tk. 10 per week or Tk. 30 per month. How much does a person save in a year by renting by the month rather than by the week?

Solution:
Tk. 10 per week
An year has 52 weeks.
Annual charges per year at Tk. 10 per week  = 52 × 10 = 520
 
Tk. 30 per month
An year has 12 months.
Annual charges per year at Tk. 30 per month = 12 × 30 = 360
 
∴ Save = 520 - 360 = 160
.
If y = 5x2 - 2x, and x = 3, then y =?
  1. 24
  2. 27
  3. 39
  4. 51
সঠিক উত্তর:
39
উত্তর
সঠিক উত্তর:
39
ব্যাখ্যা
Question: If y = 5x2 - 2x, and x = 3, then y =?

Solution:
Put x = 3 in the equation y = 5x2 - 2x
⇒ y = 5 × (3)2 - (2 × 3)
⇒ y = 45 - 6
∴ y = 39
.
A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
  1. 3/4
  2. 4/7
  3. 1/8
  4. 3/7
সঠিক উত্তর:
4/7
উত্তর
সঠিক উত্তর:
4/7
ব্যাখ্যা
Question: A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?

Solution:
Let number of balls = (6 + 8) = 14.
Number of white balls = 8.
P (drawing a white ball) = 8/14 = 4/7.
.
A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is-
  1. 5.15 kmph
  2. 4.4 kmph
  3. 4.25 kmph
  4. 4.14 kmph
সঠিক উত্তর:
4.14 kmph
উত্তর
সঠিক উত্তর:
4.14 kmph
ব্যাখ্যা
Question: A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is-

Solution:
A's speed = 5 × (5/18) m/sec = 25/18 m/sec.
Time taken by A to cover 100 m = 100 × (18/25) sec = 72 sec.
∴ Time taken by B to cover 92 m = (72 + 8) = 80 sec.

 B's speed = (92/80) ×(18/5) kmph = 4.14 kmph.
১০.
How many kilograms of sugar costing Tk. 9 per kg must be mixed with 27 kg of sugar costing Tk. 7 per Kg so that there may be a gain of 10% by selling the mixture at Tk. 9.24 per Kg?
  1. 36 Kg
  2. 42 Kg
  3. 54 Kg
  4. 63 Kg
সঠিক উত্তর:
63 Kg
উত্তর
সঠিক উত্তর:
63 Kg
ব্যাখ্যা
Question: How many kilograms of sugar costing Tk. 9 per kg must be mixed with 27 kg of sugar costing Tk. 7 per Kg so that there may be a gain of 10% by selling the mixture at Tk. 9.24 per Kg?

Solution:
ধরি,
৯ টাকা টাকা দরের চিনি আছে ক কেজি
৭ টাকা দরের চিনি আছে  ২৭ কেজি

মোট ক্রয়মূল্য = ৯ক + ২৭ × ৭ টাকা = ৯ক + ১৮৯ টাকা 
মোট বিক্রয়মূল্য = (ক + ২৭) × ৯.২৪ টাকা = ৯.২৪ক + ২৪৯.৪৮ টাকা 

∴ লাভ = ৯.২৪ক + ২৪৯.৪৮ - ৯ক - ১৮৯ = ০.২৪ক + ৬০.৪৮ টাকা 

প্রশ্নমতে,
(৯ক + ১৮৯) এর ১০% = ০.২৪ক + ৬০.৪৮
বা, (৯ক + ১৮৯) × (১/১০) = ০.২৪ক + ৬০.৪৮
বা, ৯ক + ১৮৯ = ২.৪ক + ৬০৪.৮
বা, ৯ক - ২.৪ ক = ৬০৪.৮ - ১৮৯
বা, ৬.৬ক = ৪১৫.৮
বা, ক = ৪১৫.৮/৬.৬
∴ ক = ৬৩
১১.
A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is-
  1. 6 hours
  2. 10 hours
  3. 15 hours
  4. 30 hours
সঠিক উত্তর:
15 hours
উত্তর
সঠিক উত্তর:
15 hours
ব্যাখ্যা
Question: A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is-

Solution:
Suppose, first pipe alone takes x hours to fill the tank .
Then, second and third pipes will take (x - 5) and (x - 9) hours respectively to fill the tank.

ATQ,
1/x + 1/(x - 5) = 1/(x - 9)
⇒ (x - 5 + x)/x(x - 5) = 1/(x - 9)
⇒ (2x - 5)(x - 9) = x(x - 5)
⇒ x2 - 18x + 45 = 0
⇒ x2 - 15x - 3x + 45 = 0
⇒ x(x - 15) - 3(x - 15) = 0
⇒ (x - 15)(x - 3) = 0
∴ x = 15 [neglecting x = 3]
১২.
Salaries of Rakib and Sumon are in the ratio 2 : 3. If the salary of each is increased by Tk. 4000, the new ratio becomes 40 : 57. What is Sumon's new salary?
  1. Tk. 17,000
  2. Tk. 20,000
  3. Tk. 25,500
  4. Tk. 38,000
সঠিক উত্তর:
Tk. 38,000
উত্তর
সঠিক উত্তর:
Tk. 38,000
ব্যাখ্যা
Question: Salaries of Rakib and Sumon are in the ratio 2 : 3. If the salary of each is increased by Tk. 4000, the new ratio becomes 40 : 57. What is Sumon's new salary?

Solution:
Let the original salaries of Rakib and Sumon be Tk. 2x and Tk. 3x respectively.
Then,
(2x + 4000)/(3x + 4000) = 40/57
⇒ 57(2x + 4000) = 40(3x + 4000)
⇒ 6x = 68,000
⇒ 3x = 34,000

Sumon's present salary = (3x + 4000) = (34000 + 4000) = 38,000.
১৩.
At a certain diner, a hamburger and coleslaw cost $3.95, and a hamburger and french fries cost $4.40. If french fries cost twice as much as coleslaw, how much do french fries cost?
  1. $0.45
  2. $0.60
  3. $0.75
  4. $0.90
সঠিক উত্তর:
$0.90
উত্তর
সঠিক উত্তর:
$0.90
ব্যাখ্যা
Question: At a certain diner, a hamburger and coleslaw cost $3.95, and a hamburger and french fries cost $4.40. If french fries cost twice as much as coleslaw, how much do french fries cost?

Solution:
Let,
Cost of hamburger = $h
Cost of coleslaw = $c
Cost of fries = $f

h + c = $3.95 ...............(1)
h + f = $4.40 ................(2)
 
french fries cost twice as much as coleslaw
∴ f = 2c
 
Putting the Value of f in equation (2)
h + 2c = $4.40 ..............(3)

From (3) - (1) we get,
c = $0.45
 
∴ f = $0.45 × 2 = $0.90
১৪.

If ∠XYZ in the figure above is a right angle, what is the value of x?
  1. 155°
  2. 145°
  3. 125°
  4. 110°
সঠিক উত্তর:
145°
উত্তর
সঠিক উত্তর:
145°
ব্যাখ্যা
Question:

If ∠XYZ in the figure above is a right angle, what is the value of x?

Solution:

∠XYZ = 90°
∠XYA = 90° - 55° = 35°
 
∠x + ∠XYA = 180°
⇒ ∠x = 180° - 35°
∴ ∠x = 145°
 
১৫.
The least perfect square, which is divisible by each of 21, 36 and 66 is-
  1. 213444
  2. 214344
  3. 214434
  4. 231444
সঠিক উত্তর:
213444
উত্তর
সঠিক উত্তর:
213444
ব্যাখ্যা
Question: The least perfect square, which is divisible by each of 21, 36 and 66 is-

Solution:
L.C.M. of 21, 36, 66 = 2772.
Now,
2772 = 2 × 2 × 3 × 3 × 7 × 11

To make it a perfect square, it must be multiplied by 7 × 11.
So, required number = 22 × 32 × 72 × 112 = 213444
 
১৬.
  1. 0.97
  2. 0.95
  3. 0.86
  4. 1.06
সঠিক উত্তর:
0.86
উত্তর
সঠিক উত্তর:
0.86
ব্যাখ্যা
Question:

Solution:
১৭.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is-
  1. 9
  2. 11
  3. 13
  4. 15
সঠিক উত্তর:
15
উত্তর
সঠিক উত্তর:
15
ব্যাখ্যা
Question: Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is-

Solution:
Let the three odd integers be x, x + 2 and x + 4.
Then,
3x = 2(x + 4) + 3
⇒ 3x = 2x + 8 + 3
∴ x = 11.

∴ Third integer = x + 4 = 11 + 4 = 15.
১৮.
From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done?
  1. 564
  2. 645
  3. 735
  4. 756
সঠিক উত্তর:
756
উত্তর
সঠিক উত্তর:
756
ব্যাখ্যা
Question: From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done?

Solution:
Ways in which at least 3 men are selected;
⇒ 3 men + 2 women
⇒ 4 men + 1 woman
⇒ 5 men + 0 woman

Number of ways = 7C3 × 6C2 + 7C4 × 6C1 + 7C5 × 6C0
= 35 ×15 + 35 × 6 + 21
= 735 + 21
= 756
∴ The required No. of ways = 756
১৯.
The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is-
  1. 15360
  2. 153600
  3. 30720
  4. 307200
সঠিক উত্তর:
153600
উত্তর
সঠিক উত্তর:
153600
ব্যাখ্যা
Question: The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is-

Solution:
Perimeter = Distance covered in 8 min. = (12000/60) × 8 m = 1600 m.
Let
length = 3x metres and breadth = 2x metres.
Then,
2(3x + 2x) = 1600
⇒ 5x = 800
∴ x = 160.

∴ Length = 480 m and Breadth = 320 m.
∴ Area = (480 × 320) m2 = 153600 m2.
 
২০.
A certain culture of bacteria quadruples every hour. If a container with these bacteria was half full at 10:00 a.m., at what time was it one-eighth full?
  1. 9:00 a.m.
  2. 7:00 a.m.
  3. 6:00 a.m.
  4. 4:00 a.m.
সঠিক উত্তর:
9:00 a.m.
উত্তর
সঠিক উত্তর:
9:00 a.m.
ব্যাখ্যা
Question: A certain culture of bacteria quadruples every hour. If a container with these bacteria was half full at 10:00 a.m., at what time was it one-eighth full?

Solution:
To go from one-eighth (1/8) full to half (1/2) full culture of bacteria should quadruple: (1/2) ÷ (1/8) = (1/2) × 8 = 4
As it quadruples every hour then container was one-eighth full at 10:00 a.m - 1 hour = 9:00 a.m.
২১.
An accurate clock shows 8 o'clock in the morning. Through how may degrees will the hour hand rotate when the clock shows 2 o'clock in the afternoon?
  1. 144°
  2. 150°
  3. 168°
  4. 180°
সঠিক উত্তর:
180°
উত্তর
সঠিক উত্তর:
180°
ব্যাখ্যা
Question: An accurate clock shows 8 o'clock in the morning. Through how may degrees will the hour hand rotate when the clock shows 2 o'clock in the afternoon?

Solution:
Time between 8 o'clock in the morning to 2 o'clock in the afternoon = 6 hours

Angle traced by the hour hand in 6 hours = {(360/12) × 6}° = 180°
২২.
Nisha is 15 years elder to Romi. If 5 years ago, Nisha was 3 times as old as Romi, then find Nisha’s present age.
  1. 32.5 years
  2. 27.5 years
  3. 25 years
  4. 24.9 years
সঠিক উত্তর:
27.5 years
উত্তর
সঠিক উত্তর:
27.5 years
ব্যাখ্যা
Question: Nisha is 15 years elder to Romi. If 5 years ago, Nisha was 3 times as old as Romi, then find Nisha’s present age.

Solution:
Let,
Age of Romi be y
Nisha is 15 years elder than Romi = (y + 15).
So Nisha's age 5 years ago = (y + 15 - 5).
Romi's age before 5 years = (y - 5)

5 years ago, Nisha is 3 times as old as Romi
(y + 15 - 5) = 3 (y - 5)
⇒ (y + 10) = (3y - 15)
⇒ 2y = 25
⇒ y = 12.5

Romi's age = 12.5 years
Nisha's age = (y + 15) = (12.5 + 15) = 27.5 years.
২৩.
A and B are partners in a business. A contributes 1/4 of the capital for 15 months and B received 2/3 of the profit. For how long B's money was used?
  1. 3 months
  2. 6 months
  3. 10 months
  4. 12 months
সঠিক উত্তর:
10 months
উত্তর
সঠিক উত্তর:
10 months
ব্যাখ্যা
Question: A and B are partners in a business. A contributes 1/4 of the capital for 15 months and B received 2/3 of the profit. For how long B's money was used?

Solution:
Let the total profit be Tk. z
Then,
B's share of profit = Tk. 2z/3, 
A's share of profit = Tk. ( z - 2z/3 ) = Tk. z/3
 
∴ A : B = z/3 : 2z/3 = 1 : 2

Let the total capital be Tk. X and suppose B's money was used for n months.
Then,
{(X/ 4) × 15}/{(3X/4) × n) = 1/2 
⇒ 15/3n = 1/2
⇒ 3n = 30
⇒ n = 10

∴ B's money was used for 10 months.
২৪.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Tk. 1. The sum (in Tk.) is-
  1. 625
  2. 630
  3. 640
  4. 650
সঠিক উত্তর:
625
উত্তর
সঠিক উত্তর:
625
ব্যাখ্যা
Question: The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Tk. 1. The sum (in Tk.) is-

Solution:
Let the sum be Rs. x. Then,

Compound Interest = x(1 + 4/100) 2 - x
= (676/625)x - x
= (51/625)x

Simple Interest = x × 2 × 4/100 
= (2/25)x

ATQ,
(51/625)x - (2/25)x = 1
⇒ {(51 - 50)/625}x = 1
⇒ x/625 = 1
∴ x = 625
 
২৫.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
  1. 12 days
  2. 15 days
  3. 16 days
  4. 18 days
সঠিক উত্তর:
15 days
উত্তর
সঠিক উত্তর:
15 days
ব্যাখ্যা
Question: A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?

Solution:
A's 2 day's work = (1/20) × 2 = 1/10
(A + B + C)'s 1 day's work = 1/20 + 1/30 + 1/60 = 6/60 = 1/10

Work done in 3 days = 1/10  + 1/10 = 2/10 = 1/5

Now,
1/5 work is done in 3 days.
∴ Whole work will be done in (3 × 5) = 15 days.
২৬.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is-
  1. 1 hour
  2. 2 hours
  3. 3 hours
  4. 4 hours
সঠিক উত্তর:
1 hour
উত্তর
সঠিক উত্তর:
1 hour
ব্যাখ্যা
Question: In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is-

Solution:
Let the duration of the flight be x hours.
Then,
600/x - 600/(x + 1/2) = 200
⇒ 600/x - 1200/(2x + 1) = 200
⇒ 3/x - 6/(2x + 1) = 1
⇒ (6x + 3 - 6x){x(2x + 1)} = 1
⇒ x(2x + 1) = 3
⇒ 2x2 + x - 3 = 0
⇒ 2x2 + 3x - 2x - 3 = 0
⇒ x(2x + 3) - 1(2x + 3) = 0
⇒ (2x + 3)(x - 1) = 0
∴ x = 1 hr. [neglecting the (- ve) value of x]
২৭.
Find the odd man out.
396, 462, 572, 427, 671, 264
  1. 396
  2. 427
  3. 671
  4. 264
সঠিক উত্তর:
427
উত্তর
সঠিক উত্তর:
427
ব্যাখ্যা
Question: Find the odd man out.
396, 462, 572, 427, 671, 264

Solution:
In each number except 427, the middle digit is the sum of other two.
২৮.
The value of log32⋅log43⋅log54⋅log65⋅log76⋅log87 is-
  1. 1/4
  2. 1/2
  3. 1/3
  4. None of these
সঠিক উত্তর:
1/3
উত্তর
সঠিক উত্তর:
1/3
ব্যাখ্যা
Question: The value of log32⋅log43⋅log54⋅log65⋅log76⋅log87 is-

Solution:
log32⋅log43⋅log54⋅log65⋅log76⋅log87
⇒ (log32 ⋅ log43) (log54 ⋅ log65) (log76 ⋅ log87)
⇒ log42 .log64. log86 [logbM × logab = logaM]
⇒ (log42 .log64) log86
⇒ log62 ⋅ log86
⇒ log82
⇒ 1/log2
⇒ 1/log223
= 1/(3log22)
= 1/(3​ × 1) [∵ log22 = 1]
= 1/3

∴ log32⋅log43⋅log54⋅log65⋅log76⋅log87 = 1/3
২৯.
There were 36,000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold 9 times as many paperback copies as hardback copies were sold. If a total of 441,000 copies of the novel were sold in all, how many paperback copies were sold?
  1. 364,500
  2. 396,900
  3. 45,000
  4. 360,000
সঠিক উত্তর:
364,500
উত্তর
সঠিক উত্তর:
364,500
ব্যাখ্যা
Question: There were 36,000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold 9 times as many paperback copies as hardback copies were sold. If a total of 441,000 copies of the novel were sold in all, how many paperback copies were sold?

Solution:
From the time the first paperback copy was sold until the last copy of the novel was sold 9 times as many paperback copies as hardback copies were sold
Let,
x = number of hardback copies sold during this time
∴ 9x = number of paperback copies sold during this time
∴ x + 9x = total number of copies sold DURING THIS TIME PERIOD
 
A total of 441,000 copies of the novel were sold in all
36,000 hardback copies sold BEFORE the paperback version was issued.
So, we get:
36,000 + x + 9x = 441,000
⇒ 36,000 + 10x = 441,000
⇒ 10x = 405,000
∴ x = 40,500

∴ 9x = 9(40,500) = 364,500
∴ 364,500 paperback copies were sold
৩০.
Dan and Karen, who live 10 miles apart meet at a cafe that is directly north of Dan’s house and directly east of Karen’s house. If the cafe is 2 miles closer to Dan’s house than to Karen’s house, how many miles is the cafe from Karen’s house?
  1. 9
  2. 6
  3. 7
  4. 8
সঠিক উত্তর:
8
উত্তর
সঠিক উত্তর:
8
ব্যাখ্যা
Question: Dan and Karen, who live 10 miles apart meet at a cafe that is directly north of Dan’s house and directly east of Karen’s house. If the cafe is 2 miles closer to Dan’s house than to Karen’s house, how many miles is the cafe from Karen’s house?

Solution:

From the figure it is evident that
102 = x2 + (x - 2)2
⇒ 2x2 - 4x + 4 = 100
⇒ 2x2 - 4x - 96 = 0
⇒ x2 - 2x - 48=0
⇒ x2 - 8x + 6x - 48 = 0
⇒ x(x - 8) + 6(x - 8) = 0
⇒ (x - 8)(x + 6) = 0
∴ x = 8  [neglecting the (- ve) value of x]
 
Hence x = 8
৩১.
In one hour, a boat goes 11 km/hr along the stream and 5 km/hr against the stream. The speed of the boat in still water (in km/hr) is-
  1. 3 km/hr
  2. 5 km/hr
  3. 8 km/hr
  4. 9 km/hr
সঠিক উত্তর:
8 km/hr
উত্তর
সঠিক উত্তর:
8 km/hr
ব্যাখ্যা
Question: In one hour, a boat goes 11 km/hr along the stream and 5 km/hr against the stream. The speed of the boat in still water (in km/hr) is-

Solution:
Speed in still water = (11 + 5)/2 kmph
= 16/2 kmph
= 8 kmph.
৩২.
The market value of a certain machine decreased by 30 percent of its purchase price each year. If the machine was purchased in 1982 for its market value of Tk. 8000, what was its market value two years later?
  1. Tk. 8000
  2. Tk. 3200
  3. Tk. 5600
  4. Tk. 2400
সঠিক উত্তর:
Tk. 3200
উত্তর
সঠিক উত্তর:
Tk. 3200
ব্যাখ্যা
Question: The market value of a certain machine decreased by 30 percent of its purchase price each year. If the machine was purchased in 1982 for its market value of Tk. 8000, what was its market value two years later?

Solution:
Total price reduce after 2 years = 60% of purchase price = 60% of 8000
= 4800 
 
Market value after 2 years = 8000 - 4800
= 3200
 
৩৩.
For 9 innings, Roman has an average of 65 runs. In the tenth inning, he scores 200 runs, thus increasing his average. His average increased by-
  1. 78.5
  2. 72
  3. 13.5
  4. 77.5
সঠিক উত্তর:
13.5
উত্তর
সঠিক উত্তর:
13.5
ব্যাখ্যা
Question: For 9 innings, Roman has an average of 65 runs. In the tenth inning, he scores 200 runs, thus increasing his average. His average increased by-

Solution:
Total score for 9 innings = 65 × 9 = 585
Total score after 10th innings = 585 + 200 = 785
So, the new average is 785/10 = 78.5

So, the increment is 78.5 - 65 = 13.5
৩৪.
If 2x = 3y = 10, then 12xy =?
  1. 1200
  2. 200
  3. 120
  4. 40
সঠিক উত্তর:
200
উত্তর
সঠিক উত্তর:
200
ব্যাখ্যা
Question: If 2x = 3y = 10, then 12xy =?

Solution:
2x = 3y = 10

12xy 
= 2x × 6y
= 10 × 2 × 3y
= 20 × 10
= 200
৩৫.
An article is sold for Tk. 2400 at a profit of 25%. What would have been the actual profit or loss if it had been sold at Tk. 1800?
  1. Loss Tk. 120
  2. Profit Tk. 120
  3. Loss Tk. 80
  4. Profit Tk. 80
সঠিক উত্তর:
Loss Tk. 120
উত্তর
সঠিক উত্তর:
Loss Tk. 120
ব্যাখ্যা
Question: An article is sold for Tk. 2400 at a profit of 25%. What would have been the actual profit or loss if it had been sold at Tk. 1800?

Solution:
Firstly let us find the cost price of the article. C.P. = 2400 × (100/125) = 1920.
New selling price = Tk. 1800 
∴ Loss = 1920 - 1800 = 120