ব্যাংক নিয়োগ প্রস্তুতি ⎯ লং কোর্স

Quantity of water in given mixture
=10 / 100 x 50=5 litres.

Quantity of milk in given mix.
= 50 - 5= 45 litres.

Let x litres of water be added to it.
Milk : 45 litres, water (5 + x) litres
Total mix = (50 + x) litres
(5+x)/ (50+ x ) = 20/100
⇒ (5 + x)5 = 50 + x
⇒ 4x = 25
⇒ x= 6.25
6.25 litres of water must be added.

for, 3 to 2, 
600 × 3/(3 + 2) = 360; which is greater than 200. This maybe the correct answer.

for, 5 to 2, 
600 × 2/(5 + 2) = 171.43; which is less than 200. This is not the correct answer.

for, 7 to 3, 
600 × 3/(7 + 3) = 180; which is less than 200. This is not the correct answer.

for, 9 to 1, 
600 × 1/(9 + 1) = 60; which is less than 200. This is not the correct answer.

x : y = 5 : 3
⇒ x/y = 5/3
⇒ 11x/2y = (11 × 5)/(2 × 3)
⇒ 11x/2y = 55/6
⇒ (11x + 2y)/(11x - 2y) = (55 + 6)/(55 - 6)
⇒ (11x + 2y)/(11x - 2y) = 61/49
⇒ (11x + 2y) : (11x - 2y) = 61 : 49

x/y = 3
⇒ x = 3y

x + 3y - 10 = 0
⇒  3y + 3y = 10
⇒  6y = 10
⇒  y = 10/6
⇒  y = 5/3

x = 3 × 5/3 = 5

Since the ages of Mary and Maria are in the ratio 4 : 5,
the actual ages can be taken as 4x years and 5x years respectively.
After 12 years, their ages will be 4x + 12 years and 5x + 12 years.
Therefore, as per the problem (4x + 12)/(5x + 12) = 5/6 => x = 12
Mary's age now is 4x years = 48 years.
So after 2 years Mary will be 50 years.

x : y = 7 : 3
⇒ x/y = 7/3
⇒ x = 7y/3

x/(13 - 2y) = 1
⇒ (7y/3)/(13 - 2y) = 1
⇒ 7y/3 = 13 - 2y
⇒ 7y = 39 - 6y
⇒ 7y + 6y = 39
⇒ 13y = 39
⇒ y = 3

অপশনে সঠিক উত্তর নেই, তাই বাতিল করা হয়েছে।

Let, the present ages of Jamal and Kamal are 6x and 4x respectively.
(6x - 5)/(4x - 5) = 5/3
20x - 25 = 18x - 15
2x = 10
x = 5

Habib's age = 6 × 5 = 30 years 

Two numbers are 3y and 5y
(3y + 8)/(5y + 8) = 2/3
10y + 16 = 9y + 24
y = 8
The greater number is 5 × 8 = 40

In 20 litres mixture - 1; sum of ratio = 3 + 7 = 10
10 units = 20 litres
1 unit = 20/10 = 2

In 36 litres mixture - 1; sum of ratio = 5 + 7 = 12
12 units = 36 litres
1 unit = 36/12 = 3

In 20 litres mixture - 1; spirit : water = 3 × 2 : 7 × 2 = 6 : 14
In 36 litres mixture - 2; spirit : water = 7 × 3 : 5 × 3 = 21 : 15

spirit : water = (6 + 21) : (14 + 15) = 27 : 29

Let C subscribes Tk. x
x + x + 5000 + x + 9000 = 50,000
x = 12,000
A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12
C's share = 100000 of 12/50 = 24,000

Let total profit be Tk. 100
After paying 5% to charity, A's share = 95 × 3/5 = 57
Total profit = 100/57 × 1140 = 2000

In this question as time frame for both investors is same as then just get the ratio of their investments.

P : Q
= 57000 : 33000
= 57 : 33
= 19 : 11

A : B : C = 35000 : 45000 : 55000 = 7 : 9 : 11
sum of ratio = 7 + 9 + 11 = 27
A's share = 81,000 × 7/27 = 21,000

Sum of 4 and 5 is 9
Share of B = 72000 × 5/9 = Tk. 40,000

(a + b + c) : 5c = (3 + 4 + 7) : 5 × 7 = 14 : 35 = 2 : 5

2A/3 = 75B/100 = 6C/10
A/B = 9/8
B/C = 8/10
A : B : C = 9 : 8 : 10

Let bucket contains 5x and 3x of liquids A and B respectively.
Quantity of A in 16 liters = 16 × (5x / 8x) = 10
Quantity of B in 16 liters = 16 - 10 = 6
(5x - 10)/(3x - 6 + 16) = 3/5
Upon solving, x = 5
So initial quantity of B = 15 liters

Let present age of A and B be 4x and 5x
18 years ago their ages
(4x - 18)/(5x - 18) = 11/16
x = 10
Sum of the present ages = 40 + 50 = 90 years