১.
The area of an isosceles triangle is 25√3 cm2, and the measure of each of the equal sides is 10 cm, what is the angle between the equal sides?
ব্যাখ্যা
Question: The area of an isosceles triangle is 25√3 cm2, and the measure of each of the equal sides is 10 cm, what is the angle between the equal sides?
Solution:
Area of the traingle :
⇒ 1/2absinθ = 25√3
⇒ 10 × 10 sinθ = 50√3
⇒ sinθ = √3/2
∴ θ = 60°
Solution:
Area of the traingle :
⇒ 1/2absinθ = 25√3
⇒ 10 × 10 sinθ = 50√3
⇒ sinθ = √3/2
∴ θ = 60°