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Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 12 seconds respectively and they cross each other in 24 seconds. The ratio of their speeds is:
ব্যাখ্যা
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 12 seconds respectively and they cross each other in 24 seconds. The ratio of their speeds is:
Solution:
Let,
the speeds of the two trains be x m/sec and y m/sec respectively.
Then,
length of the first train = 27x metres,
and length of the second train = 12y metres.
ATQ,
(27x + 12y)/(x + y) = 24
⇒ 27x + 12y = 24x + 24y
⇒ 27x - 24x = 24y - 12y
⇒ 3x = 12y
⇒ x/y = 12/3
∴ x : y = 4 : 1
Solution:
Let,
the speeds of the two trains be x m/sec and y m/sec respectively.
Then,
length of the first train = 27x metres,
and length of the second train = 12y metres.
ATQ,
(27x + 12y)/(x + y) = 24
⇒ 27x + 12y = 24x + 24y
⇒ 27x - 24x = 24y - 12y
⇒ 3x = 12y
⇒ x/y = 12/3
∴ x : y = 4 : 1