ব্যাংক নিয়োগ প্রস্তুতি ⎯ লং কোর্স

We are given that,
1) Total population of city = 6500
2) Increase in male and female population = 5% & 10% respectively.
3) Final population of city = 7000

Hence,
Let’s assume that number of males = x
Number of female = 6500 – x

Therefore, after an increase in 5% male and 10% female, the population becomes 7000
5% male +10% female = Difference between new and original population
⇒ (5/100)x + (10/100) (6500 - x) = 7000 - 6500
⇒ 5x + 65000 - 10x = 50000
⇒ 5x = 15000
⇒ x = 3000

Number of males = 3000
Number of females = 3500.

If the price of goods decreases by R%, then the increase in consumption so as not to decrease the expenditure can be calculated using the formula:
[{R/(100 - R)} × 100]%
Using this trick,
The price of rice falls by 15%, therefore substituting this value
we get,
[{15/(100 - 15)} × 100]%
= 17.64%
Therefore, the person can increase his consumption by 17.64%.

1) Student attempts x questions.
2) Out of 20 questions he answered 15 correctly and of (x – 20) questions he answered 1/3 correctly.
3) The student gets 50% marks.
Therefore,
15 + 1/3(x – 20)= 50% of x
⇒ 15 + 1/3(x – 20) = (50/100) × x
⇒ 15 + 1/3(x – 20) = x/2
⇒ 90 + 2(x - 20) = 3x
⇒ x = 50
Hence, the number of questions attempted by the students = 50.

Now, in this numerical, there is no common loss and gain %.
Hence, solve it by making equations.

Let the cost price of the camel be x.
As the cost of camel and carriage = Tk 5000
Cost of carriage = Tk (5000 – x)
After selling the camel he gains 20% and on carriage a loss of 10%. But on the whole, he gains 3%.

Therefore,
20% of x – 10% of (5000 – x) = 3% of 5000
⇒ (20/100) × x - (10/100) × (5000 – x) = (3/100) × 5000
⇒ x/5 - (5000 – x)/10 = 150
⇒ 10x/5 - {(5000 – x) × 10}/10 = 150 × 10
⇒ 10x/5 - (5000 – x) = 1500
⇒ 2x - 5000 + x = 1500
⇒ 3x=1500 + 5000
⇒ x = 2166.67.
The cost of camel = Tk. 2166.67

Let the weight of the grocery bag be 1000 gm.
Now, the shopkeeper sells his grocery using weights 10% less than true weights.
Hence, actual weight of bag = 90% of 1000 gm = 900 gm
If each gram = Tk.1, C.P. of each bag containing 900 gm = Tk. 900
The shopkeeper sells with a gain of 30% on true C.P.

Calculate the S.P.
Selling price = 100 + gain% × C.P.
Therefore,
Selling price = (130/100) × Tk. 1000
= Tk. 1300
Gain = S.P. - C.P. = 1300 - 900 = Tk. 400
Gain% = (400/900) × 100
= 44.44%

1) Find the cost price

Let C.P. of book = x and S.P. = Tk. 450
S.P. of book = C.P. – (10% of C.P.)
S.P. = x – (0.10x)
450 = 0.9 x
x i.e cost price = Tk. 500

2) Find Selling Price to gain 10%.

Now, we are asked to find a selling price to gain 10% profit.
Selling price = (100 + Gain%)/100 × C.P.
Selling price = (100 + 10)/100 × 500
Selling price = (110/100) × 500
= Tk. 550

Let first discount = x
91% discount of (100 – x) % of 120 = 90
⇒ (91/100) × {(100 – x)/100} × 120 = 90
⇒ (100 - x) = (90 × 100 × 100)/(120 × 91) = 82.42
⇒ x = (100 – 82.42) = 17.58
Therefore, first discount = 17.58%

Let cost-price goods be Tk. 100
Marked price (Selling Price) marked by the shopkeeper on goods = Tk. 130
He sells the goods at a discount of 15%

Therefore,
Selling price = 85% of Tk. 130
= Tk. 110.50
Gain = S.P. – C.P.
= 110.5 – 100
= 10.50%

Profit earned by manufacturer = 20%
Profit earned by wholesaler = 25%
Profit earned by retailer = 30%
S.P. of shoes = Tk. 50

Therefore, 130% of 125% of 120% of x = 50.50
⇒ 120/100 × 125/100 × 130/100 × x = 5050/100
⇒ (195/100) x = 5050/100
⇒ x = (5050 × 100)/(195 × 100)
⇒ x = 25.89
Cost price of shoes = Tk. 25.89

We are given selling price = Tk. 580 and expected profit of 15%
Therefore, we can easily solve this numerical, considering basic formulae of profit and loss.
Let cost price = x
Selling price = C.P. + Profit
S.P. = C.P. + (15% of C.P.) [We know that profit is gained on cost price]
580 = x + (0.15 x)
580 = 1.15 x

Therefore,
x = 504.347
Cost Price = Tk. 504.35
Now,
we have the cost price and hence,
Profit = S.P. – C.P. = 580 – 504.35
= Tk. 75.65
The trader gets a profit of Tk. 75.65

Here,
The selling price of 10 m cloth is obtained as profit.
Profit of 10 m cloth = (S.P. of 30 m cloth) – (C.P. of 30 m cloth)
The selling price of 20 m cloth = Selling Price of 30 m of cloth

Let the cost of each metre be Tk. 100.

Therefore,
the cost price of 20 m cloth = 20 × 100 = Tk. 2000 and
S.P. of 20 m cloth = Tk. 3000

Profit% = (10/20) × 100
= 50%

Here,
we just know the selling price and the gain and loss incurred, on two cameras.
Therefore,
first calculate the cost price of both the cameras, because gain or loss is calculated on the cost price of the material.
When a shopkeeper earns profit, Cost Price = 100/(100 + Gain%) × S.P.
When shopkeeper incurs a loss, Cost Price = 100/(100 – Loss%) × S.P.

C.P. of camera A = 100/(100 +20) × 7500
= 100/120 × 7500
= Tk. 6250
C.P of camera B = 100/(100 – 5) × 8550
= 100/95 × 8550
= Tk. 9000

Total C.P. = Cost of camera A + Cost of camera B
Total C.P. = 6250 + 9000 = Tk. 15250
Total S.P. = 7500 + 8550 = Tk. 16050
Selling Price > Cost Price, hence man gains during this transaction.

Gain = S.P. – C.P.
= 16050 – 15250
= Tk. 800
Gain% = Gain/C.P. × 100
Gain% = 800/15250 × 100
= 5.24%

Gain% = [ Error/(True weight - Error)]%

Error = True weight - False weight
Error = 1000 - 970
= 30
Gain% = [{30/(1000 - 30)} × 100]%
Gain% = 3.09%

Let the marked price of the item be Tk. 100x
Discount % = 20%
Changes for delivery and packaging
= 10% on discounted price

Then
20% discount of 100x = 80x
Charges 10% on the discount price 80x = 88x
⇒ 88x + 88x × (25/100) - 88x = 2046
⇒ 110x - 88x = 2046
⇒ 22x = 2046
⇒ x = 93
Hence, 100x = 93 × 100
= 9300
Marked price = Tk. 9300

Let
Marked price = X
Cost Price(C.P.) = 1440
Sale price(S.P.) = 1440 + 25% of 1440
= Tk. 1800

S.P. = M.P. - 25% of M.P.
S.P. = X - 25% of X
S.P. = X - 0.25X
1800 = 0.75X
X = 1800/.25
= 2400
M.P. = Tk. 2400

According to the question
The cost price of 12 oranges = The sale price of 9 oranges
So profit% = (12 C.P. - 9 C.P.)/9 C.P × 100 = 33.33%

Then it is said that,
5 S.P. - 5 C.P. = 10 M.P. -10 S.P.
From that
we get the relation between M.P. and S.P., that is,
27 S.P. = 24 M.P.(With help of 12 C.P. = 9 S.P.)
Then Discount%
= M.P. - S.P./M.P
= (27 M.P. - 24 M.P.)/27 M.P × 100
= 11.11%
So, % point discount
= 33.33% - 11.11%
= 22.22%

Let,
The number is X
According to the question,
(60/100) × X + 120 = X
⇒ 3X/5 + 120 = X
⇒ X - 3X/5 = 120
⇒ (5X - 3X)/5 = 120
⇒ 2X = 600
⇒ X = 300.

Let the labeled price of TV = Tk. R
∴ SP of the TV = [R x (100 - 20)] / 100
= Tk. 4R/5
But 16,800 - 800 = 4R/5
∴ x = (16,000 x 5)/4
= Tk. 20,000

Let C.P. = Tk. 100.
Marked Price = 20% more than C.P.
∴ M.P. = Tk. 120
Discount = 30% on marked price
∴ S.P. = (100-30)% of M.P.
∴ S.P. = (70/100) × 120 = Tk. 84

Loss% = (100 - 84)/100 × 100
= 16%

Price after 1^stdiscount of 20% = (100-20)%
= 80% of Marked Price
∴ Price = (80/100) × 12800
= Tk. 10240

SP = (100 - Discount) % of Price

∴ 9216 = (100 - Discount) % x 10240
⇒ (100 - Discount)/100 = 9216/10240
⇒ 100 - Discount = (9216 × 100)/10240
⇒ 100 - Discount = 90
⇒ Discount = 100 - 90 = 10%

10% is the percent of 2^nddiscount offered.

According to the question,
15% of 1st no. =21% of 2nd no.
1% of 1st no.= (21/15) % of 2nd no.
18% of 1st no.= {(21/15) × 18} % of 2nd no.
=25.2%

Suppose, 1 Kg Wheat = Tk. 100
So, 1 Kg Rice will be Tk. 100 - (30% of 100)
= 100 - 30
= Tk. 70

According to the question,
(100/70) × 100 = 142.85%
So, Wheat is 142.85% of Rice
⇒ It is (142.85 - 100)
= 42.85% more than that of Rice.

Let the original price be 100
Increase of 10% means the price now = 100 + (10% of 100) = Tk. 110
Now decrease of 10% means price now = Tk. 110 - (10% of 110)
= 110 - 11
= Tk. 99
So change in price = 100 - 99 = Tk. 1
1 is 1 percent of 100.
It is 1%
So change in price is 1%.

30% discount = 30% of 2000 = Tk. 600
Now, if you offer two successive discounts of 15% each, it works out to
First discount of 15% = 15% of 2000
= Tk. 300
After discount value = Tk. 2000 - Tk.300
= Tk. 1700
Second discount of 15% = 15% of Tk. 1700
= {(15/100) × 1700}
= Tk. 255

Difference = 600 - (300+255)
= 600 - 555
= Tk. 45

Since profit of 10% is there,
∴ S.P. = (100+10)% of C.P. = (110/100) × 900
= Tk. 990
Discount = 12%
So,
SP = (100-12)% of List Price
∴ 990 = (88/100) × L.P.
∴ L.P. = Tk. 1125 [List price = Advertised Price = Marked Price]

Difference in discount = 8% - 5% = 3%
Due to this 3% man makes Tk. 60 less in profit
That means 3% of Marked Price = 60
(3/100) × M.P. = 60
∴ M.P. = Tk. 2000

The seller manages to make a 10% profit.
Value of this 10% profit = Tk. 77
% Profit = Profit/Cost price × 100
∴ 10 = 77/C.P. × 100
∴ CP = Tk. 770
And S.P. = 770+77 = Tk. 847

Price after Commission = Selling Price
= (100-23)% of L.P.
= 77% of L.P.
∴ 847 = 77/100 × L.P.
∴ L.P. = List Price = Tk. 1100