ব্যাংক নিয়োগ প্রস্তুতি ⎯ লং কোর্স

A's share : B's share = Ratio of their 1 day's work
= 1/8 : 1/12
= 3 : 2.
∴ B's share = Tk. 200 × (2/5)
= Tk. 80.

(X + y)'s 1 day's work = (1/16) + (1/16)
= 2/16
= 1/8
Z's 1 day's work = (X + Y + Z)'s 1 day's work - (X + Y)'s 1 day's work
= 1/6 - 1/8
= 1/24.
∴ Z alone can finish the work in 24 days.

Let, there be x men originally.
So, x men had provisions for 40 days whereas (x + 500) men consumed it in 35 days.
more men, Less days [Indirect proportion]
∴ (x + 500) : x = 40 : 35
⇒ 35(x+ 500) = 40x
⇒ 5x = 35 × 500
⇒ x = (35 × 500)/5
= 3500.

Ratio of rates of working of A and B = 2:1
So, ratio of times taken = 1 : 2
∴ A's 1 day's work = (1/6);
B's 1 day's work = 1/12
(A + B)'s 1 day's work = (1/6) + (1/12)
= 3/12
= 1/4
So, A and B together can finish the work in 4 days.

Let,
The required number of days be x.
Less Cows, More days[Indirect proportion]
Less Bags, Less days [Direct proportion]
Cows(1 : 40), bags(40 : 1)}::40 : x
∴ 1 × 40 × x = 40 × 1 × 40
= 40.

Time taken by A alone to do the work = (10 × 8)
= 80 hrs.
Since B is two -thirds as efficient as A,
So the time taken by B to do the work
= 80 × (3/2)hrs
= 120 hrs.
∴ Required time = (120/5)
= 24 days.

Lopa's wages : Rasel's wages
= Lopa's 1 day's work : Rasel's 1 day's work
= 1/3 : 1/2
= 2 : 3
∴ Lopa's share = Tk.(2/5) × 150
= Tk 60.

B's 3 day's work = (1/21) × 3
= 1/7.
Remaining work = 1 - (1/7)
= 6/7.
(A + B)'s 1 day's work
= (1/14) + (1/21)
= 5/42.
Now, 5/42 work is done by A and B in 1 day.
∴ 6/7 work is done by A and B in (42/5) × (6/7)
= 36/5 days.
Hence, total time taken = 3 + (36/5) days
= 10(1/5) days.

A's 2 day's work = (1/20) × 2
= 1/10
(A + B + C)'s 1 day's work = (1/20) + (1/30) + (1/60)
= 6/60
= 1/10
(A + B + C) work in 3 days = (1/10) + (1/10)
= 1/5.
Now, 1/5 work is done in 3 days.
∴ Whole work is done in (3 × 5)
= 15 days.

3 men's 1 day's work = 1/20;
5 boy's 1 day's work = 1/30.
(3 men + 5 boys)'s 1 day's work = (1/20) + (1/30)
= 5/60
= 1/12.
∴ 3 men and 5 boys will complete the work in 12 days.

(7 × 12) men can complete the work in 1 day.
∴ 1 man's 1 day's work = 1/84.
7 men's 5 day's work = (1/12) × 5
= 5/12.
Remaining work = 1 - (5/12)
= 7/12
5 men's 1 day's work = (1/84) × 5
= 5/84.
5/84 work is done by them in 1 days.
7/12 work is done by them in (84/5) × (7/12)
= 49/5 days.
= 9(4/5) days.

প্রতি লাইনে 11 words, প্রতি page এ 36 লাইন বিশিষ্ট 125 pages এ
word আছে 11× 36 × 125
5 দিনে 11 × 36 × 125 words হয়
1 দিনে (11 × 36 × 125)/5 words হয়
∴ 6 দিনে (11 × 36 × 125 × 6)/5 words হয়
= (11 × 36 × 125 × 6)/(5 × 12) lines
= (11 × 36 × 125 × 6)/(5 × 12 ×30) pages
= 165 pages.

Let, 1 man's 1 day's work = x and
1 boy's 1 day's work = y

Then, 12x + 16y = 1/5
and 13x + 24y = 1/4.

Solving these two equations, we get,
x = 1/100 and
y = 1/200
∴ Required ratio = x : y
= 1/100 : 1/200
= 2 : 1.

12 men can do a piece of work in 24 days
⇒ M₁ = 12 and D₂ = 24
8 men can do this work in D₂ days
⇒ M₂ = 8
M₁D₁ = M₂D₂
⇒ 12 × 24 = 8 × D₂
⇒ D₂ = (12 × 24)/8
= 36 days.

Let,
The required number of days be x.
Less Man, More Days [Indirect proportion]
∴ 42 : 56 :: 24 : x
⇒ 42x = 56 × 24
⇒ x = (56 × 24)/42
⇒ x = 32.

Let,
The required number of days be x.
Less pumps, More days[Indirect proportion]
Less weight, Less days [Direct proportion]
More hours/days, Less days [Indirect proportion]
{Pumps(16 : 18) , Weight (2170 : 1736), Hours/Day(9 :7)} :: 10 : x
∴ (16 × 2170 × 9 × x) = (18 × 1736 × 7 × 10)
⇒ x = (18 × 1736 × 7 × 10)/(16 × 2170 × 9)
= 7.

Let,
The required number of binders is x.
Less books, Less binders [Direct proportion]
More days, Less binders [Indirect proportion]
Books {(1400 : 800) , Days (20 : 15)} :: 21 : x
∴ 1400 × 20 × x = 800 × 15 × 21
⇒ x = (800 × 15 × 21)/(1400 × 20)
= 9.

Let,
The original number of artisans be x.
More artisans, Less days [Indirect proportion]
∴ (x + 8) : x :: 16 : 12
⇒ 12 (x + 8) = 16x
⇒ 12x + 96 = 16x
⇒ 16x - 12x = 96
⇒ 4x = 96
⇒ x = 96/4
⇒ x = 24.

Let,
the required number of rounds be x.
More radius, Less rounds [Indirect proportion]
∴ 20 : 14 :: 70 : x
⇒ (20 × x) = (14 × 70)
⇒ x = (14 × 70)/20
= 49.

After 25 days, 35 men complete the work in 12 days.
Thus, 35 men can finish the remaining work in 12 days.
∴ 30 men can do it in (12 × 35)/30
= 14 days.
which is 1 day behind.

প্রথম 5 টি copy এর প্রত্যেকটি দেখতে সময় লাগে = 30/5
= 6 মিনিট
পরের 30 টি copy এর প্রত্যেকটি দেখতে সময় পাবে = 150/30
= 5 মিনিট

বর্তমান রেট - 1/6
কাঙ্ক্ষিত রেট - 1/5
বাড়াতে হবে - 1/30

অতএব, {(1/30) / (1/6)} × 100
= 20% faster হতে হবে ।

x adults = 2x children
to complete in d days 2x children is required.
∴ to complete in (d + 2) days (2x × d)/(d + 2) children is required.

42 days এ কাজটি complete করতে লাগে 55 men
1 day এ কাজটি complete করতে লাগে 55 × 42 men
33 day এ কাজটি complete করতে লাগে (55 × 42)/33 men
= 70 men.
Additional men লাগবে 70 - 55 = 15 men.

1 child's 1 day's work = 1/192;
1 adults 1 day's work = 1/96.
Work done in 3 days = (1/96) × 16 × 3
= 1/2
Remaining work = {1 - (1/2)}
= 1/2.
(6 adults + 4 Children)'s 1 day's work = (6/96) + (4/192)
= 1/12
1/12 work is done by them in 1 days
1/2 work is done by them in (12 × (1/2)}
= 6 days.