ব্যাখ্যা
x2 - 3x - 1 = 0
বা, (x2 - 3x - 1)/x = 0
বা, x2/x - 3x/x - 1/x = 0
বা, x - 1/x = 3
এখন, (x + 1/x)2 = (x - 1/x)2 + 4.x.1/x
বা, (x + 1/x)2 = 32 + 4 = 13
বা, x + 1/x = √13
∴ x2 - 1/x2 = (x + 1/x)(x - 1/x)
= √13.3
= 3√13
Math Master · তারিখ অনির্ধারিত · ২০ প্রশ্ন
x2 - 3x - 1 = 0
বা, (x2 - 3x - 1)/x = 0
বা, x2/x - 3x/x - 1/x = 0
বা, x - 1/x = 3
এখন, (x + 1/x)2 = (x - 1/x)2 + 4.x.1/x
বা, (x + 1/x)2 = 32 + 4 = 13
বা, x + 1/x = √13
∴ x2 - 1/x2 = (x + 1/x)(x - 1/x)
= √13.3
= 3√13
x2 = 100
∴ x = 10
এখন,
x-3 = 1/x3
= 1/103
= 1/1000
= 0.001
x + y = 2 এবং x3 + y3 = 8
x3 + y3 = 8
বা, (x + y)3 - 3xy(x + y) = 8
বা, 23 - 3xy.2 = 8
বা, - 6xy = 0
∴ xy = 0
x2 + y2
= (x + y)2 - 2xy
= 22 - 2.0
= 4
a + b = -c
∴ a + b + c = 0
এখন, a3 + b3 + c3
= a3 + b3 + c3 - 3abc + 3abc
= (a + b + c)(a2 + b2 + c2 - ab - bc - ca) + 3abc
= 0 × (a2 + b2 + c2 - ab - bc - ca) + 3abc
= 3abc
যেহেতু, x = 2 + √3
∴ 1/x = 2 - √3
∴ x + 1/x = 4
এখন, x3 + 1/x3
= (x + 1/x)3 - 3.x.1/x(x + 1/x)
= 43 - 3.4
= 64 - 12
= 52
x4 + y4
= (x2)2 + (y2)2
= 1/2 [2{(x2)2 + (y2)2}]
= 1/2 [{(x2 + y2)2 + (x2 - y2)2}]
= 1/2 [52 + 32]
= 1/2 × 34
= 17
a - [a - {a - (a + 1)}]
= a - [a - {a - a - 1}]
= a - [a - {-1}]
= a - [a + 1]
= a - a - 1
= -1
1/(x - 2) - {(3 - x)/(x - 2)}
= (1 - 3 + x)/(x - 2)
= (x - 2)/(x - 2)
= 1
0.01 × 0.1
= 0.001
(1 - 1/a2) ÷ (1/a + 1)
= (1 - 1/a2)/(1/a + 1)
= {(1 + 1/a)(1 - 1/a)}/(1 + 1/a)
= 1 - 1/a
= (a - 1)/a
(x + 7)(x - 6)
= x2 + 7x - 6x - 42
= x2 + x - 42
প্রথম রাশি, x3 + x2y
= x2(x + y)
দ্বিতীয় রাশি, x2y + xy2
= xy(x + y)
∴ গ.সা.গু = x(x + y)
প্রথম রাশি, a + b = (a + b),
দ্বিতীয় রাশি, a2 - b2 = (a + b)(a - b),
তৃতীয় রাশি, a3 + b3 = (a + b)(a2 - ab + b2)
∴ ল.সা.গু = (a + b)(a - b)(a2 - ab + b2)
= (a - b)(a3 + b3)
a(a - b)/(a + b) ÷ (a - b)/(a3 + b3)
= {a(a - b)/(a + b)} × {(a3 + b3)/(a - b)}
= {a(a - b)/(a + b)} × {(a + b)(a2 - ab + b2)/(a - b)}
= a(a2 - ab + b2)
যদি 1/(x + 1) = 0 হয়,
তবে 1 = 0 হয় যা অসম্ভব,
∴ 1/(x + 1) ≠ ০
1/x3 এর লব ও হরের সাথে -x যোগ করে পাই,
(1 - x)/(x3 - x)
= -(x - 1)/{x(x2 - 1)}
= - (x - 1)/{ x(x + 1)(x - 1)}
= - {1/(x2 + x)}
2/(√5 + √3)
= 2(√5 - √3)/{(√5 + √3)(√5 - √3)} [লব ও হরের সাথে (√5 - √3) গুণ করে]
= 2(√5 - √3)/{(√5)2 - (√3)2}
= 2(√5 - √3)/(5 - 3)
= 2(√5 - √3)/2
= √5 - √3
(a + 2)(a - 2)/(a + 3)(a - 3)
= (a2 - 4)/(a2 - 9)
a2 - 9)a2 - 4(1
a2 - 9
-------
5
∴ ভাগশেষ = 5
(x - y)/xy + (y - z)/yz + (z - x)/zx
= (zx - yz + xy - zx + yz - xy)/xyz
= 0/xyz
= 0
এখানে, x - y = m + n + 9
এবং x + y = m - n - 3
'+' করে, 2x = 2m + 6
বা, x = m + 3
∴ x - m = 3