ব্যাংক নিয়োগ প্রস্তুতি ⎯ লং কোর্স

Let the number be,
x, x + 1, x + 2, x + 3, x + 4, x + 5 and x + 6,
Then (x + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) + (x + 6)) / 7 = 20.
or 7x + 21 = 140
or 7x = 119
or x =17.
Latest number = x + 6 = 23.

Total annual income
= TK (10000 X 4 + 12000 X 8 + 26000)
= TK. 162000
Average monthly income = TK 16200012 = TK. 13500

Let N be the no. of persons in the group.
Required number of person is given by;
Member in group × aged increased = difference of replacement
N × 5 = 38 - 18
Or, 5N = 20
Or, N = 4

Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 .... (i)
A + B = (40 x 2) = 80 .... (ii)
B + C = (43 x 2) = 86 ....(iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)
Subtracting (i) from (iv), we get : B = 31.
B's weight = 31 kg.

Let there be x pupils in the class.
Total increase in marks = x . 1/2
= x/2
∴ x/2 = 83 - 63
=> x/2 = 20
=> x = 40

Let P, Q and R represent their respective monthly incomes. Then, we have:

P + Q = (5050 x 2) = 10100 .... (i)
Q + R = (6250 x 2) = 12500 .... (ii)
P + R = (5200 x 2) = 10400 .... (iii)

Adding (i), (ii) and (iii), we get:
2(P + Q + R) = 33000 or P + Q + R = 16500 .... (iv)

Subtracting (ii) from (iv), we get,
P = 4000.
∴ P's monthly income = TK. 4000.

Then, daily wage of a woman = TK. (x - 5).
Now,
600x + 400 (x - 5) = 25.50 × (600 + 400)
=> 1000x = 27500
=> x = 27.50.
Man's daily wages = TK. 27.50;
Woman's daily wages = (x - 5)
= TK. 22.50.

Sum of their ages = 40 × 5 = 200 years
Sum of A & B’s ages = 35 × 2 = 70 years
Sum of C & D’s ages = 42 × 2 = 84
So, Age of E = 200 - (70 + 84) = 46

Average = (13 + 27 + 35 + X)/4 = 25
Or, X + 75 = 100
So, X = 25

Bambi’s present age = 6x,
Samba’s present age = 4x
Therefore,
(6x - 5)/(4x - 5) = 5/3
Or, 20x - 25 = 18x - 15
So, x = 5
And samba’s age = 6 × 5 = 30

Sum of 12 children ages = 12 × 15 = 180
Sum of the 13 children ages = 14 × 13 = 182
So age of new children = 182-180 = 2

লাইভ পরীক্ষার প্রশ্নে new average 14 এর পরিবর্তে 13 ছিলো। তাই উত্তর তুলে দেওয়া হয়েছে।

According to the question,
(x + y)/2 = 6.5,
or, x + y = 13 and
xy = 36,
Now substitute the value of x and y from the option and find the answer.

Let, 8 years ago,
the age of A and B was 4x and 5x respectively. Age of C = y
so, the present age of A and B is 4x + 8 and 5x + 8 respectively 

A/Q,
5x + 8 : y = 4 : 5 ------------ (1)
y - (4x + 8) = 20 ----------- (2)
Solving this equation we will get x = 8 and y = 60

So, present age of Age of A = 4×8 + 8
= 40
and present age of B = 5×8 + 8 
= 48
From equation (1),
C = {(5x + 8) × 5} ÷ 4 = 60

So, the total age of A, B & C= 40 + 48 + 60
= 148

The number of boys = B
The number of Girls = G
According to question, 5G + 5.7B = 5.5(B + G)
Or, 0.2B = 0.5G
Or, B:G = 5:2
Now, sum of the ratio= 7.
Sum of one option is divisible by 7 that is = 50 + 20
= 70

Let,
7 years ago son’s age was x years old and father’s age was 5x year.
Now,
(x+7)/(5x+7) = 1/3,
so x = 7
Son’s age = 7 + 7 = 14
Father’s age= 5 × 7 + 7 = 42
After 7 years,
Son’s age : Father’s age = 21:49 = 3:7

Let Roni's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
there4 (4x + 8) = (5/2)(x + 8)
=> 8x + 16 = 5x + 40
=> 3x = 24
=> x = 8.

Hence, required ratio = (4x + 16)/(x + 16)
= 48/24
= 2

Let the son's present age be x years.
Then, (38 - x) = x
2x = 38.
x = 19.
Son's age 5 years back = (19 - 5)
= 14 years.

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
⇒ 5x = 20
⇒ x = 4.
∴ Age of the youngest child = x = 4 years.

Total age of 10 students = 150 years
Total age of 15 students = 240 years
Total age of 5 new students = 240 - 150 = 90 years
Therefore,
Average age of 5 new students = 90/5 = 18 years

Let the present age be x years.
20 years ago my age was x - 20.

According to given data,
x - 20 = x/3
=> 2x = 60
=> x = 30

Let the Father be x years when he died.
Average Age 10 years ago be A.
Total Age 10 years ago = 6 × A
Total Age after 10 years(Just before father's Death) = 6A + 6 × 10 = 6A + 60
Father Died and Baby was born => the Total number of people in the family is Same (6)
Baby born today so age of baby = 0
(6A + 60 - x)/6 = 6A/6
=> A + 10 -(x/6) = A
=> x/6 = 10
=> x = 60
Therefore we can conclude that the father was 60 years old when he died.

Let,
Maala’s age = 4A and
Kala’s age = 3A
Then,
4A + 3A = 28
A = 4
Maala’s age = 16 years
and Kala’s age = 12 years
Proportion of their ages after 8 is = (16 + 8) : (12 + 8)
= 24 : 20
= 6 : 5

Let Benu’s age now be B.
Anika’s age now is A.
(A - 6) = P(B - 6)
But A is 17 and therefore 11 = P(B - 6)
11/P = B - 6
(11/P) + 6 = B

If Ratul age is x,
then Sahin age is x - 7,
so, (x - 7)/x = 7/9
9x - 63 = 7x
2x = 63
x = 31.5
So, Sahin age is = 31.5 - 7
= 24.5

Let the son's present age be x years.
Then, man's present age = (x + 24) years
=> (x + 24) + 2 = 2(x + 2)
=> x + 26 = 2x + 4
So, x = 22

Age of Raju when he got the job = 17 + 3 + 2 + 1 = 23 yr

Age of Raju at the time of marriage = 23 + 3 = 26 yr