ব্যাংক নিয়োগ প্রস্তুতি ⎯ লং কোর্স

Given,Principal,P = tk. 1000
Compound rate,R = 20%per annum
= 20/2
= 10% half-yearly
Time = 18 month
= 3 half - years

Amount,A = {P × [1 + (R/100)]ⁿ}
= {1000 × [1 + (10/100)]³}
= (1000 × 11 × 11 × 11) ÷ (10 × 10 × 10)
A = tk.1331
Hence, compound interest = tk.1331

Here, the sum becomes 4 times that means 100, becomes 400.
Rate of such question is given by
R = interest/time = 300/10 = 30%

Let,
Principal = Tk. 100
Amount = Tk. 200

Alternative Method:
Suppose 100 be the principal.
In 4 years it doubles and becomes 200.
In next 4 years 200 double to 400.
In next 4 years 400 doubles to 800.
Hence the period for 8 times is 12 years.

Compound interest for the 4th year = 3600 + (3600 × 8 × 1)/100.
= 3600 + 288.
= Tk. 3888.

Compound interest for the 5th year = 3888 + (3888 × 8 × 1)/100.
= 3888 + 311.04.
= Tk. 4199.04.

Difference between the compound interest in the 4th and 5th year = 4199.04 - 3888.
= Tk. 311.04.

Let P = 100,
A = 200,
It means I = 100

Now We want A = 300,
means I = 200
Years for I of Tk. 100 = 10
Years for I of Tk. 200 = (10/100) × 200 = 20 Years

Alternative Method:
Assuming simple interest, let the amount be P and rate of interest per annum be R%.

Given that P becomes 2P in 10 years.
=> P + PX10X R/100 = 2P
=> 1 + R/10 = 2
=> R = 10

Let P triple itself in N years:
=> P + PXNX 10/100 = 3P
=> 1 + N/10 = 3
=> N = 20 years

If the value of the machine at the beginning of year 1 is 10,000 and then it reduces by 10%, the value of the machine at the end of year 1 is:
10,000 × (100%-10%) = 9,000
And again, at the end of Year 2, we follow a similar route:
9000 × (100% - 10%)
= 8,100

Cost of machine 10000/-
Depreciation 10% each year.
1st year = 10000 - 1000 = 9000/-
2nd year = 9000 - 900 = 8100/-
3rs year = 8100 - 810 = 7290/-
4th year = 7290 - 729 = 6561/-
Depreciation will be deducted from the amount left after subtracting previous depreciation value.

Let the sum of money be P(which is the principal value) and rate of interest be R.
According to the question,
Amount (principal +simple interest) = 8P/5
Time (T) = 5 years
Simple interest (SI) = PRT/100
SI = 5PR/100
Amount = P + SI
8P/5 = P + (5PR/100)
8P/5 = P(100 + 5R)/100
160 = 100 + 5R
5R = 60
R = 12
Therefore, rate of interest = 12% p.a.

Alternative Method:
Given A = 8/5p (8/5 of the sum) .
Time = 5years .
Let the sum be P = 100.
Then, the amount = 8/5p = (value of p is 100)
= 8/5 × 100
= 160 .
S. I. = A-P
= 160 - 100
= 60 .
Hence,
Rate = S.I. × 100/P × T
= 60 × 100/100 × 5
= 12% p.a.

Dividend on Tk.20 = Tk. (9/100 × 20) = Tk. 9/5
Tk.12 is income of Tk.100.
∴Tk. 9/5 is an income of = Tk (100/12 × 9/5) = Tk.15

Let x be the market value,
we don't know face value so consider 100.
6% of 100 = 8% of x.
(6/100) × 100 = (8/100) × x.
6 = 8x/100.
x = 600/8.
x = 75.

Alternative Solution:
For an income of Tk. 8, investment = Tk. 100.
For an income of Tk. 6, investment = Tk.(100/8 × 6) = Tk. 75
Market value of Tk. 100 stock = Tk. 75.

Number of shares = (4455/8.25)
= 540
Face value = Tk(540 × 10)
= Tk. 5400
Tk (12/100 × 5400) = Tk. 648

To earn Tk. 135, investment = Tk. 1620.
To earn Tk. 8, investment = Tk.(1620/135 × 8)
= Tk 96
So, Market value of Tk. 100 stock = Tk. 96.

To earn Tk. 10, money invested = Tk. 100.
To earn Tk. 12, money invested = Tk (100/10 × 12)
= Tk. 120.
Market value of Tk.100 stock = Tk. 120.

Suppose he buys each share for Tk. x.
Then, Tk.(25 × 9/100) = (x × 10/100)
or x = Tk. 22.50.
Cost of each share = Tk. 22.50.

Face Value of the stock = Tk.2000
Dividend is 7(1/2)% = 15/2% of the face value
Dividend = (2000 × 15) ÷ (2 × 100)
= Tk. 150

By investing Tk. 1500, the man obtained an income of Tk. 130.
So, by investing Tk. 95, the income will be = (130/1500) × 96
= Tk 8.32
So, the divided = 8.32%

Number of shares = 25000
Face value of each share = Tk. 15
Let R be the rate of interest.

Dividend per share = 15 × R/100
Total dividend = 25000 × 15 × R/100
As per the question: 25000 × 15 × R/100
= 30000
R = 30000/3750 = 8

So, the dividend is 8%.

Investment = Tk. 333000
Since face value is not given, we can take it as Tk. 100
and dividend per share = Tk.11/2
Market Value = 110 + 1 = 111
Number of shares purchased = 333000/111 = 3000
Total income = 3000 × 11/2 = Tk.16500

Face Value = Tk.1200
Market Value = Tk.120
Dividend (income) = (1200 × 8)/100
= Tk.96

Investment = Tk.[20 × (50 − 5)] = Tk. 900.
FaceValue = Tk. (50 × 20) = Tk.1000.
Dividend = Tk. (27/2 × 1000/100) = Tk.135.
Interest Obtained = (135/900 × 100)% = 15%

C.I. when interest compound yearly = Tk. [5000 × (1 + 4/100) (1 + 1/2 × 4/100)]
= Tk. 5304.
C.I. when interest is compounded half-yearly = Tk. 5000 (1 + 2/100)³
= Tk. 5306.04
Difference = Tk. (5306.04 - 5304)
= Tk. 2.04

The population grew from 3600 to 4800 in 3 years.
That is a growth of 1200 on 3600 during a three year span.
Therefore, the rate of growth for three years has been constant.

The rate of growth during the next three years will also be the same.
Therefore, the population will grow from 4800 by 4800 × 1/3 = 1600
Hence, the population three years from now will be 4800 + 1600 = 6400