ব্যাংক নিয়োগ প্রস্তুতি ⎯ লং কোর্স

Given that T = R
S.I = (P × R × T)/100
⇒ 686 = (1400 × R × R)/100
⇒ 686 = 14R²
⇒ R² = 49
⇒ R = 7.

S.I. for 1 year = 854 - 815
= 39
S.I. for 3 years = 39 × 3
= 117
∴ Required Sum = 815 - 117
= Tk. 698.

The difference in interest rate = 6(1/4)% - 4%
= (25/4)% - 4%
= (9/4)%
Gain per year
= simple interest on Tk. 5000 at = (9/4)% for 1 year.
= {5000 × (9/4) × 1}/100
= 225/2
= Tk. 112.5

P = (100 × S.I)/RT
= (100 × 6200)/(8 × 4)
= 620000/32
= 775 × 25
= Tk. 19375.

Let the sum lent to C be x
Simple interest on Tk. 1500 at 8% for 4 years + simple interest on x at 8%for 4 years.
= Tk. 1400
(1500 × 8 × 4)/100 + (x × 8 × 4)/100 = 1400
⇒ {8 × 4(1500 + x)}/100 = 1400
⇒ 1500 + x = 4375
⇒ x = 4375 - 1500
⇒ x = 2875.

Let the rate of interest be R%
Amount due in 6 months
= 10 + simple interest on Tk. 10 for six months.
= {10 + 10 × R × (1/2)}/100
= 10 + (R/20)
With the formula mentioned,
3 = 100(10 + 9R/20)/{(100 × 6) + R × 6(6 - 1)}/(2 × 12)
⇒ 3 = (1000 + 5R)/{600 + (5R/4)}
⇒ 1800 + 15R/4 = 1000 + 5R
⇒ 5R/4 = 800
⇒ R = 640.
Hence interest rate is 640%

Let the sum be x
Then,
Simple interest = x/4
T = 3(1/8)
= 25/8 years
R = {100 × (x/4)}/{x × (25/8)}
= 8
Hence Required interest rate = 8%

Let the rate of interest be R%
Amount due in 10 months
= 9 + simple interest on Tk. 9 for ten months
= 9 + {9 × R × (10/12)}/100
= 9 + (3R/40)
With the formula mentioned,
1 = 100{9 + 3R/40)}/[(100 × 10) + {R × 10(10 - 1)/(2 × 21)}]
900 + (15R/2) = 1000 + (15R/4)
15R/4 = 100
R = 26.67.
Hence the interest rate is 26.67%.

Let the sum be x Assume that it will treble in n years.
Note that when the money doubles, simple interest is (2x - x), and when the money trebles, simple interest is (3x - x)
simple interest ∝ T (because here P and R are constants)
Therefore,
(2x - x) : (3x - x) = 12 : n
⇒ x : 2x = 12 : n
⇒ n = 24.

Face value of each share = Tk. 20
Dividend per share = 9% of 20 = (9 × 20)/100
= 9/5.
He needs to have an interest of 12% on his money
Money Paid for a share = (9/5) × (12/100)
Money Paid for a share = (9/5) × (100/12)
= 15.
ie, Market Value of the share = Tk. 15.

By investing Tk. 1552, income = Tk. 128
By investing Tk. 97, income = (128 × 97)/1552
= 8
Hence, the dividend is 8%.

Assuming that face value of the first stock = Tk. 100 as it is not given in the question.
Since it is a 5% stock, we can take the dividend per stock = Tk. 5
Market Value of the first stock = Tk. 104
Investment on the first stock = Tk. 26000
Number of stocks purchases = 26000/104 = 250
His total income from all these stocks = Tk. 250 × 5 = Tk. 1250
He sells each of these stocks at Tk. 120
ie, amount he earns = Tk. 120 × 250 = Tk. 30000
He invests this Tk. 30000 in 6% stock (here also face value is not given and hence take it as Tk. 100)
His new income = Tk. (1250 + 2500) = Tk. 3750
ie, By Tk. 30000 of investment, he earns an income of Tk. 3750
To get an income of Tk. 6, the investment needed = (30000 × 6)/3750
= Tk. 48.

Face value of each share = Tk. 5
Total dividend received by Jobayed = {100 × 5 × (12/100)}
= Tk. 60
Let market value of 100 shares = Tk. x
x × (10/100) = 60
x = 600
ie, Market value of 100 shares = Tk. 600
Hence, Market value of each share = Tk. 6

Since face value is not given, take it as Tk. 100.
As it is an 8% stock, income (dividend) per stock = Tk. 8
ie, For an income of Tk. 8, amount of stock needed = Tk. 100
For an income of Tk. 800, the amount of stock needed = (100 × 800)/8
= 10000

Just too much information is given in the question to confuse. This is a straight and simple question
Market Value of Company X (his selling price) = Tk. 30
Total shares sold = 4000
The amount he gets = Tk. (4000 × 30)
He invests this amount in ordinary shares of Company Y
Market Value of Company Y(His purchasing price) = 15
Number of shares of company Y which he purchases = (4000 × 30)/15
= Tk. 8000.

Number of shares = 20000
Face value of each share = Tk. 10
dividend per share = (10 × R/100) where R is the Rate of interest.
Total dividend = 20000 ×10 ×R/100
20000 ×10 ×R/100 = 24000
R = 24000/2000
= 12
Hence the dividend is 12%.

Investment = Tk. 333000
Since face value is not given, we can take it as Tk.100
and dividend per share = Tk. 11/2
Market Value = 110 + 1 = 111
Number of shares purchased = 333000/111 = 3000
Total income = 3000 × (11/2)
= Tk. 16500.

Market Value = Tk. 96.
Required Income = Tk. 650.
Here face value is not given. Take face value as Tk. 100 if it is not given in the question
To obtain Tk. 10 (ie,10% of the face value 100), investment = Tk. 96
To obtain Tk. 650, investment = {(96/10) × 650}
= Tk. 6240.

P(4/100)² =1
⇒ P(1/25)² = 1
⇒ P/25² = 1
⇒ P = 625
Hence The sum is Tk. 625.

Compound interest for 1 year.
2{3%(P)} + 3%{3%(P)}
= 6%(P) + 0.09%(P)
= 6.09%(P)
That is an effective interest rate for 1 year = 6.09%.

Let the sum be Tk. x
Amount after 3 years on Tk. x at 20% per annum when interest is compounded annually
P(1 + R/100)^T
= x{1 + (20/100)}³
= x(120/100)³
= x(6/5)³
Compound interest = {x(6/5)³ - x}
= x{(6/5)³ - 1}
= x{(216/125) - 1}
= 91x/125
Simple interest PRT/100 = (x × 20 × 3)/100
= 3x/5
Given that difference between compound interest and simple interest is Tk. 48
(91x/125) - (3x/5) = 48
⇒ (91x - 75x)/125 = 48
⇒ 16x/125 = 48
⇒ x = (48 × 125)/16
= 3 × 125
= Tk. 375.

R = {(20 × 100)/1000)}
= 2% [percentage is calculated for twenty per thousand]
Population after 2 years
= P(1 - R/100)^T
= 40000{1 - (2/100)}²
= 40000{1 - (1/50}²
= 40000(49/50)²
= (40000 × 49 × 49)/(50 × 50)
= 16 × 49 × 49
= 38416.

Simple interest for 2 years is Tk. 320
⇒ Simple interest for first year = 320/2 = 160
⇒ Similarly, simple interest for the second year is also 160
Compound Interest for first year = 160
Compound Interest for second year = 340-160 = 180
we can see that compound Interest for the second year is more than
simple interest for the second year by 180-160 = 20
i.e., Tk. 20 is the simple interest on Tk. 160 for 1 year
R = 100 × S.I./PT
= (100 × 20)/(160 × 1)
= 12.5%

Tk. 20000 after 4 years = 20000{1 + (10/100)}⁴ =Tk. 29282
Tk. 20000 after 3 years = 20000{1 + 10/100)}³ =Tk. 26620
Tk. 20000 after 2 years = 20000{1 + 10/100)}² =Tk. 24200
Tk. 20000 after 1 years = 20000{1 + 10/100)}¹ =Tk. 22000
Total amount after 4 years = 29282 + 26620 + 24200 + 22000 = Tk. 102102

Let the sum be P
The sum P becomes 3P in 4 years on compound interest
3P = P{(1 + R/100)}⁴
3 = {1 + R/100)}⁴
Let the sum P becomes 81P in n years
81P = P{1 + (R/100)}ⁿ
81 = {1 + (R/100)}ⁿ
3⁴ = {1 + (R/100)}ⁿ
[{1 + (R/100)}⁴]⁴ = {1 + (R/100)}ⁿ
{1 + (R/100)}¹⁶ = {1 + (R/100)}ⁿ
n = 16.