ব্যাখ্যা
Solution:
These numbers are 11, 13, 31, 17, 71, 37, 73, 79, 97.
∴ There are 9 such number.
PrepBank · বিষয়ভিত্তিক প্রশ্ন
PrepBank · পাতা ১৩ / ১৮ · ১,২০১–১,৩০০ / ১,৭৩৬
ধরি,
ক্ষুদ্রতর সংখ্যাটি 3x এবং বৃহত্তর সংখ্যাটি 5x
প্রশ্নমতে, (3x - 9)/(5x - 9) = 12/23
⇒ 69x - 207 = 60x - 108
⇒ 69x - 60x = 207 - 108
⇒ 9x = 99
⇒ x = 11
অতএব, ক্ষুদ্রতর সংখ্যাটি = 3 × 11 = 33
Question: Let N be the smallest positive integer that is divisible by both 18 and 24. How many distinct prime factors does N have?
Solution:
এখানে, N হলো 18 এবং 24 দ্বারা বিভাজ্য ক্ষুদ্রতম সংখ্যা।
সুতরাং, N হবে 18 এবং 24 এর ল.সা.গু।
এখন, 18 = 2 × 3 × 3 = 21 × 32
এবং 24 = 2 × 2 × 2 × 3 = 23 × 31
LCM(18, 24) = 23 × 32 = 8 × 9 = 72
অতএব, N = 72
72 এর মৌলিক উৎপাদক = 23 × 32
স্বতন্ত্র মৌলিক উৎপাদকগুলি হলো 2 এবং 3।
∴ N এর স্বতন্ত্র মৌলিক উৎপাদকের সংখ্যা হলো 2টি।
Question: Two positive numbers are in the ratio 3 : 2. The product of their HCF and LCM is 3456. Find the sum of both the numbers.
Solution:
Let two numbers are 3a and 2a.
HCF × LCM = 1st no. × 2nd no.
⇒ 3456 = 3a × 2a
⇒ 3456 = 6a2
⇒ a2 = 576
∴ a = 24
∴ Sum of both the numbers = 3a + 2a = 5a = 5 × 24 = 120
Consider the consecutive even numbers as : x, (x + 2), (x + 4) and (x+ 6)
Average = Sum of Quantities/Number of Quantities
{x + (x + 2) + (x + 4) + (x + 6)}/4 = 27
⇒ (4x + 12)/4 = 27
⇒ x + 3 = 27
⇒ x = 27 - 3
⇒ x = 24.
Therefore,
Largest number = (x + 6) = (24 + 6) = 30
Smallest number = 24.
Hence, the answer is 24.
Question: If p is a positive integer, what is the smallest possible value of p such that 1470 × p is a perfect square?
Solution:
আমরা জানি, একটি সংখ্যা পূর্ণবর্গ হতে হলে তার মৌলিক গুণনীয়কের ঘাতসমূহ সবই জোড় সংখ্যা হতে হবে।
1470 = 2 × 3 × 5 × 7 × 7
= 21 × 31 × 51 × 72
এখন, 1470 × p = 21 × 31 × 51 × 72 × p
এখানে, 2-এর ঘাত = 1 (বিজোড়), 3-এর ঘাত = 1 (বিজোড়), 5-এর ঘাত = 1 (বিজোড়), 7-এর ঘাত = 2 (জোড়)
পূর্ণবর্গ করতে হলে সব ঘাত জোড় হতে হবে। তাই p = 2 × 3 × 5 = 30 হলে,
1470 × 30 = 21 × 31 × 51 × 72 × (2 × 3 × 5)
= 22 × 32 × 52 × 72
যেহেতু সব মৌলিক উৎপাদকের ঘাত জোড়, তাই এটি একটি পূর্ণবর্গ সংখ্যা।
সুতরাং, p = 30 হলে, 1470p পূর্ণবর্গ সংখ্যা হয়।
Question: When the positive integers x and y are divided by the positive integer z, they yield remainders 12 and 22, respectively. If (x + y) is divided by z, the remainder is 6. What is the value of z?
Solution:
ধরি, x কে z দিয়ে ভাগ করলে ভাগশেষ 12
অর্থাৎ, x হলো z এর কোনো গুণিতক থেকে 12 বেশি।
একইভাবে,
y কে z দিয়ে ভাগ করলে ভাগশেষ 22
অর্থাৎ, y হলো z এর কোনো গুণিতক থেকে 22 বেশি।
তাই (x + y) এর ভাগশেষ আগে হবে = 12 + 22 = 34
কিন্তু দেওয়া আছে, (x + y) কে z দিয়ে ভাগ করলে ভাগশে 6।
অর্থাৎ,
⇒ 34 - z = 6
⇒ z = 34 - 6
∴ z = 28
1056 ÷ 23, quotient = 45, remainder = 21
Since the remainder is not zero.
So, 1056 is not exactly divisible by 23
So, we take the next multiple of 23. Next multiple = 46
So, 23 X 46 = 1058
So, 1058 is exactly divisible by 23.
1958 - 1056 = 2
Hence, 2 is the least number to be added to 1056.
Let the ten's digit be x and unit's digit be y.
Then, (10x + y) - (10y + x) = 63
⇔ 9 (x - y) = 63
x - y = 7.
There are several numbers like this, e.g. 70-07, 81-18 and 92-29.
Thus, the correct answer is - ঘ) Can not be determined
Question: The smallest number added to 680621 to make the sum a perfect square is:
Solution:
এখানে
(825)2 = 825 × 825
= 680625
প্রদত্ত সংখ্যা = 680621
নির্ণেয় ক্ষুদ্রতম সংখ্যা = (680625 - 680621) = 4
The solution of this question is based on the rule,
The HCF of (am - 1) and (an - 1) is given by (aHCF of m, n - 1)
Thus for this question the answer is (35 - 1)
Since, 5 is the HCF of 35 and 125
As per statement (a - b) is 6 more than (c + d).
a - b = (c + d) + 6 ............ (1)
As per statement (a + b) is 3 less than (c - d)
a + b = (c - d) - 3 ........... (2)
Adding both equations Eq(1) and Eq(2)
(a - b) + (a + b) = (c + d) + 6 + (c - d) - 3
⇒ a - b + a + b = c + d + 6 + c - d - 3
⇒ 2a = 2c + 3
⇒ 2a - 2c = 3
⇒ 2 (a - c) = 3
⇒ a - c = 3/2
∴ a - c = 1.5
Question: The difference between the average of all prime numbers between 30 and 60 and the average of all prime numbers between 15 and 30 is-
Solution:
The prime numbers between 30 and 60 are 31, 37, 41, 43, 47, 53 and 59.
∴ The average of all prime numbers between 30 and 60 is,
= (31 + 37 + 41 + 43 + 47 + 53 + 59)/7
= 311/7
= 44.43
And,
The prime numbers between 15 and 30 are 17, 19, 23 and 29.
∴ The average of all prime numbers between 15 and 30 is,
= (17 + 19 + 23 + 29)/4
= 88/4
= 22
∴ Required difference = (44.43) - 22 = 22.4
Let,
The number is x,
therefore, (1/2) x + 4 = 14,
so, x = 20
Angle traced by the minute hand in 5 minutes. =(360/60×5)∘ = 30∘
13p + 11 and x = 17q + 9
∵ 13p + 11 = 17q + 9
17q - 13p = 2
q = (2 + 13p)/17
∵ The least value of p for which q = (2 + 13p)/17 is a whole number p = 26
x = (13 x 26 + 11)
= (338 + 11)
= 349
Let the number be = x
According to question,
x2=(75.15)2−(60.12)2
⇒x2=(75.15+60.12)(75.15−60.12)
⇒x2=135.27×15.03
⇒x2=2033.1081
⇒x=45.09
According to question,
√(0.25/0.0009) × √(0.09/0.36)
⇒ √((25/9)×100) × √(9/36)
⇒ ((5×10)/3) × (3/6)
⇒ 25/3
⇒ 8(1/3)
6(-3)(1/3)(-0.25)
= 6×0.25
= 1.5
Question: The difference between two integers is 4. If their product is 221, then the sum of the two numbers is?
Solution:
Let the two integers be x and y
The difference between the two integers is 4,
∴ x - y = 4 and their product is, xy = 221
We know,
⇒ (x + y)2 = (x - y)2 + 4xy
⇒ (x + y)2 = 42 + (4 × 221)
⇒ (x + y)2 = 16 + 884
⇒ (x + y)2 = 900
⇒ x + y = √900
∴ x + y = 30
∴ The sum of the two numbers is 30
HCF of the given numbers will be the greatest number which can divide 48, 84 and 144
18 = 2 × 3 × 3
84 = 2 × 2 × 3 × 7
144 = 2 × 2 × 2 × 2 × 3 × 3
∴ HCF = 2 × 3 = 6
Hence 6 is the greatest number which divides 18, 84 and 144 without leaving any remainder
Question: A shopkeeper has sufficient money to buy 50 books. On reduction in the price of each book by Tk. 4, he could buy 10 books more. How much money does he has?
Solution:
১টি বইয়ে দাম কমে ৪ টাকা
∴ ৫০টি বইয়ে দাম কমে (৫০ × ৪) টাকা
= ২০০ টাকা
সে মোট বই কিনে (৫০ + ১০) টি
= ৬০টি
১০টি বইয়ের দাম ২০০ টাকা
∴ ৬০টি বইয়ের দাম (২০০ × ৬০)/১০ টাকা
= ১২০০ টাকা
∴ তার কাছে ১২০০ টাকা আছে।
Question: If p is an even integer, which of the following must be an even integer?
Solution:
ধরি,
p = 2
ক) p2 - p = 22 - 2 = 4 - 2 = 2 [যা জোড়]
খ) 3n3 = 3 × 23 = 24 [যা জোড়]
গ) p + 2 = 2 + 2 = 4 [যা জোড়]
∴ সঠিক উত্তর হচ্ছে ঘ) All of the above
Let the numbers be 2x, 3x, 5x and 7x respectively.
Then, their L.C.M = (2 × 3 × 5 × 7)x = 210x
[∵ 2, 3, 5, 7 are prime numbers ]
So, 20x = 630
or x = 3
∵ The numbers are 6, 9, 15 and 21.
Required difference = 21 - 6 = 15.
Answer : 15
Question: The average of A and B is 45 and the sum of B & C is 78. What is the value of A - C?
Solution:
Given that,
Average of A and B = 45
Sum of B and C = 78
Now,
Average of A and B = 40, so-
⇒ (A + B)/2 = 45
∴ A + B = 90 ........(1)
And, B + C = 78 .........(2)
Subtract (2) from (1) than we get,
⇒ A + B - (B + C) = 90 - 78
⇒ A + B - B - C = 12
⇒ A - C = 12
So the value of A - C is 12.
Question: Find the remainder when 711 + 7111 + 71111 is divided by 8.
Solution:
When, 7 is divided by 8 then remainder = 7
When, 72 is divided by 8 then remainder = 1
When, 73 is divided by 8 then remainder = 7
When, 74 is divided by 8 then remainder = 1
Odd exponents give remainder = 7
Even exponents give remainder = 1
In 1st term, exponent is 11, which is odd so remainder = 7
In 2nd term, exponent is 111, which is also odd so remainder = 7
In 3rd term, exponent is 1111, which is odd so remainder = 7
So, (711 + 7111 + 71111) mod 8 = (7 + 7 + 7) mod 8 = 21 mod 8 = 5
Question: What will be the least number which when tripled will be exactly divisible by 8, 12, 15?
Solution:
Prime factorization of,
8 = 2 × 2 × 2
12 = 2 × 2 × 3
15 = 3 × 5
LCM = 2 × 2 × 2 × 3 × 5 = 120
So the smallest, 3n = 120
⇒ n = 120/3
∴ n = 40
So the least number which when tripled will be exactly divisible by 8, 12, and 15 is 40.