Question: Three partners, X, Y, and Z, invest Tk. 90000 in a business. X invests Tk. 12000 more than Y, and Y invests Tk. 6000 more than Z. If the total profit is Tk. 45000, how much does X receive?
Solution:
Let Z's investment be Tk. x.
∴ Y's investment = Tk. (x + 6000)
∴ X's investment = Tk. (x + 6000 + 12000) = Tk. (x + 18000)
Since the total investment is Tk. 90000,
∴ X + Y + Z = 90000
⇒ (x + 18000) + (x + 6000) + x = 90000
⇒ 3x + 24000 = 90000
⇒ 3x = 90000 - 24000
⇒ 3x = 66000
⇒ x = 22000
So, Z's investment = Tk. 22000
Y's investment = Tk. (22000 + 6000) = Tk. 28000
X's investment = Tk. (28000 + 12000) = Tk. 40000
Total profit = Tk. 45000
∴ X's share of profit = (X's investment/Total investment) × Total profit
= (40000/90000) × 45000
= Tk. 20000
∴ X receives Tk. 20000