ব্যাখ্যা
Question: A watch becomes fast by 5 minutes everyday. By what percent does it become fast ?
Solution:
Number of minutes in a day = (24 × 60) = 1440
∴ Required percentage =(5/1440) × 100%
= (50/144)%
= (25/72)%
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Question: A watch becomes fast by 5 minutes everyday. By what percent does it become fast ?
Solution:
Number of minutes in a day = (24 × 60) = 1440
∴ Required percentage =(5/1440) × 100%
= (50/144)%
= (25/72)%
A's 2 day's work = (1/20) × 2
= 1/10
(A + B + C)'s 1 day's work = (1/20) + (1/30) + (1/60)
= 6/60
= 1/10
(A + B + C) work in 3 days = (1/10) + (1/10)
= 1/5.
Now, 1/5 work is done in 3 days.
∴ The whole work is done in (3 × 5)
= 15 days.
The series is = 2 + 5 + 8 + .......
Here, a = 2
d = 3
n = 100
So, nth number in the series is = a + (n - 2)d
= 2 + (100 - 1)3
= 2 + 99×3
= 299
The number of bacteria on 100th day will be 299
Question: A swimmer swims from a point P against the current for 6 min and then swims back along the current for next 6 min and reaches at a point Q. If the distance between P and Q is 120 m then the speed of the current (in km/h) is:
Solution:
Given that,
Swimmer swims 6 min against current and 6 min along current
Distance between P and Q = 120 m
Let,
Speed of swimmer in still water = u m/min
Speed of current = v m/min
Now,
Distance travelled upstream (against current), d1 = (u - v) × 6
And distance travelled downstream (along current), d2 = (u + v) × 6
Net displacement from starting point = 120 m
d2 - d1 = 120
⇒ 6(u + v) - 6(u - v) = 120
⇒ 6u + 6v - 6u + 6v = 120
⇒ 12v = 120
⇒ v = 120/12
⇒ v = 10 m/min
⇒ v = (10 × 60)/1000
⇒ v = 600/1000
∴ v = 0.6 km/h
So the speed of the current is 0.6 km/h.
Number of bricks =Volume of the wall/ Volume of 1 brick
=800 x 600 x 22.5/25 x 11.25 x 6
= 6400.
The ratio of the length of an arc of a circle to its circumference is always the same as the ratio of a sector to its area.
(r × θ) / (2π × r) = θ / 2π
ATQ,
sector area : total area = (θ/2π)×πr2 : πr2 = 3 : 5
(θ/2π)×πr2 / πr2 = 3 / 5
θ/2π = 3 / 5
(θ/2π) × 2π = 3/5 × 2π
∴ θ = 6π / 5
Arc length = 6π/5 × r
Circumference = 2πr
∴ Arc length/Circumference = (6π/5 × r) / 2πr = 3/5
By definition x ≠ 1, =1
Given equation can be written as
log(x+1)2 / x2−1=log2
=>x+1 / x−1=2
=>x=3
Let, Book costs x
and Bag costs x + 1000
ATQ,
x + 1000 + x = 1100
Or, x = 50
Question: 8, 6, 9, 23, 87, … what number should come next?
Solution:
(8 x 1) - 2 = 6
(6 x 2) - 3 = 9
(9 x 3) - 4 = 23
(23 x 4) - 5 = 87
(87 x 5) - 6 = 429
When 4 fair coins are tossed simultaneously, the total number of outcomes is 24 = 16
At least 3 heads imply that one can get either 3 heads or 4 heads.
One can get 3 heads in 4C3 = 4 ways and can get 4 heads in 4C4
∴ Total number of favorable outcomes = 4 + 1 = 5
∴ The required probability = 1/4.
দেয়া আছে,
y/x = 3/7 .........(i)
এবং x + 2y = 13 ............(ii)
(ii) নং সমীকরণ হতে পাই
x + 2y = 13
⇒ x = 13 - 2y .........(iii)
x এর মান (i) নং এ বসাই
y/x = 3/7
⇒ 7y = 3x
⇒ 7y = 3(13 - 2y)
⇒ 7y = 39 - 6y
⇒ 13 y = 39
⇒ y = 3
Answer: 3.
Let the speed one train be x and the speed of the second train be y
Length of the first train = Speed × Time = 28x
Length of second train = Speed × Time = 18y
So, {(28x + 18y)/(x + y)} = 26
⇒ 28x + 18y = 26x + 26y
⇒ 2x = 8y
Therefore,
x : y = 4 : 1.
let the number is x
according to the given question-
it is doubled = 2x
then added 9 = 2x+9
resultant is tripled. so, = 3(2x+9)
given, 75
3(2x+9) = 75
6x + 27 = 75
6x = 75 - 27
6x = 48
x = 48/6
x = 8
hence, the number is 8.
Question: If 2x - 1 + 2x + 1 = 320, then 2x - 6 is equal to
Solution:
1852.20 = 1600(1 + r/100)3
Or, 1852.2/1600 = (1 + r/100)3
Or, 18522/16000 = (1 + r/100)3
Or, (21/20)3 = (1 + r/100)3
Or, (1 + r/100) = 21/20
Or, r/100 = 1/20
So, r = 5
Question: A shopkeeper marks up his goods by 40% above the cost price. He then offers a discount of 15% on the marked price. What is the overall percentage profit?
Solution:
Let,
the cost price (CP) be Tk. 100
Marked Price = 40% more than cost price
= 100 + 40
= Tk. 140
Discount = 15% of 140
= (15/100) × 140
= Tk. 21
Selling Price (SP)= 140 - 21 = Tk. 119
∴ Profit = SP - CP = 119 - 100 = Tk. 19
∴ overall percentage profit = (profit/cost price) × 100%
= (19/100) × 100%
= 19%
Let the number of hens be x and the number of cows be y.
Then, x + y = 48 .... (i)
and 2x + 4y = 140
x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
The required answer = 26.
Suppose pipe A alone takes x hours to fill the tank.
Then, pipes B and C will take x/2 and x/4 hours respectively to fill the tank.
∴ 1/x + 2/x + 4/x = 1/5
⇒ 7/x = 1/5
⇒ x = 35 hours
Question: In how many ways can 8 examination papers be arranged so that the best and the worst papers never come together?
Solution:
No. of ways in which 8 papers can be arranged = 8! ways.
When the best and the worst papers come together, regarding the two as one paper, we have only 7 papers.
These 7 papers can be arranged in 7! ways.
And two papers can be arranged themselves in 2! ways.
No. of arrangements when best and worst papers do not come together
= 8! - 7! × 2!
= 7!(8 - 2)
= 6 × 7!
= 30,240
Question: What is the length of a train that takes 15 seconds to pass a pole when it runs at a speed of 54 km/h?
Solution:
আমরা জানি, ট্রেন যখন কোনো খুঁটি বা ব্যক্তিকে অতিক্রম করে, তখন ট্রেনটি তার নিজের দৈর্ঘ্য অতিক্রম করে।
ট্রেনের দৈর্ঘ্য = গতিবেগ × সময়
এখানে, ট্রেনের গতিবেগ = 54 km/h
= 54 × (1000/3600) m/s
= 15 m/s
সময় = 15 সেকেন্ড
∴ ট্রেনের দৈর্ঘ্য = গতিবেগ × সময়
= 15 × 15 মিটার
= 225 মিটার
অতএব, ট্রেনটির দৈর্ঘ্য হলো 225 মিটার।
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 12 seconds respectively and they cross each other in 24 seconds. The ratio of their speeds is:
Solution:
Let,
the speeds of the two trains be x m/sec and y m/sec respectively.
Then,
length of the first train = 27x metres,
and length of the second train = 12y metres.
ATQ,
(27x + 12y)/(x + y) = 24
⇒ 27x + 12y = 24x + 24y
⇒ 27x - 24x = 24y - 12y
⇒ 3x = 12y
⇒ x/y = 12/3
∴ x : y = 4 : 1
Question: If x is a whole number greater than 1. Then x2(x2 - 1) is always divisible by?
Solution:
Here, x = 2, 3, 4...
When x = 2,
then = x2(x2 - 1)
= 22(22 - 1)
= 4 (4 - 1)
= 4 × 3
= 12
When, x = 3,
then = x2(x2 - 1)
= 32 (32 - 1)
= 9 × 8
= 72
............
Now, the given options are 10, 6, 8 and 5.
∴ 12 and 72 is not divisible by 10, 8 and 5.
But, 12 and 72 is divisible by 6.
So, x2(x2 - 1) is always divisible by 6.
Question: What will come at the place of question mark?
3, 7, 23, 95, ?
Solution:
1st number = 3
2nd number = 3 × 2 + 1 = 7
3rd number = 7 × 3 + 2 = 23
4th number = 23 × 4 + 3 = 95
5th number = 95 × 5 + 4 = 479
So the next number is 479.
Question: Two pipes, A and B can fill a tank in 30 and 20 minutes respectively. If both pipes are used together, then how long will it take to fill the tank?
Solution:
Pipe A fill a tank in 30 minutes
So, it fills in one minute (1/30)
Pipe B fills a tank in 20 minutes
So, it fills in one minute (1/20)
both pipes fill in one minute = (1/30) + (1/20)
= 1/12
so, it will take 1/(1/12) or 12 minutes to fill the tank.
Question: A man buys an article for 25% more than its value and sells it for 20% less than its value. His gain or loss percentage is –
Solution:
Let the original value of the article = 100
∴ Cost Price (CP) = 100 + 25% of 100
= 100 + 25 = 125
∴ Selling Price (SP) = 100 - 20% of 100
= 100 - 20 = 80
Since SP 80 is less than CP 125, there is a Loss.
∴ Loss = CP - SP = 125 - 80 = 45 টাকা
∴ Loss percentage = (Loss/CP) × 100%
= (45/125) × 100%
= 36% loss
Given that,
The difference between numbers = 56
first digit is = 2/9 of second number
let second number = x
then first number = (2/9) x
the ratio of number = (2/9)x : x
∴ ratio is = 2: 9
ABCD is a rhombus in which AB = BC = CD = DA = 17 cm
Diagonal AC = 16 cm (with O being the diagonal intersection point)
Therefore, AO = 8 cm
In ∆ AOD,
AD2 = AO2 + OD2
⇒ 172 = 82 + OD2
⇒ 289 = 64 + OD2
⇒ 225 = OD2
⇒ OD = 15
Therefore, BD = 2 × OD
= 2 × 15
= 30 cm
Now, area of rhombus
= 1/2 × d1 × d2
= 1/2 × 16 × 30
= 240 cm2
Question: Which of the following is the lowest positive integer that is divisible by 8, 9, 10, 11 and 12?
Solution:
ক্ষুদ্রতম সংখ্যাটি হবে 8, 9, 10, 11 এবং 12 এর ল.সা.গু
8 = 2 × 2 × 2
9 = 3 × 3
10 = 2 × 5
11 = 1 × 11
12 = 2 × 2 × 3
8, 9, 10, 11 এবং 12 এর ল.সা.গু = 2 × 2 × 2 × 3 × 3 × 5 × 11 = 3960
Product of 1st and 4th terms (extremes) = product of 2nd and 3rd terms (means)
⇒ 2.5x = 40
⇒ x = 40/2.5 = 16
Question: he difference between a two-digit number and the number obtained by reversing its digits is 54. If the ratio of the tens digit to the units digit of the number is 3 : 1, what is the difference between the sum and the difference of its digits?
Solution:
Let the digits of the number be:
Tens digit = x
Units digit = y
So, the number = 10x + y
The reversed number = 10y + x
Given condition: The difference between the number and its reverse number is 54:
(10x + y) - (10y + x) = 54
9x - 9y = 54
⇒ x - y = 6 ............... (1)
Given ratio of digits: Tens : Units = 3 : 1
x/y = 3/1
⇒ x = 3y.................(2)
Solve the two equations:
Substitute x = 3y into x - y = 6:
3y - y = 6
⇒ 2y = 6
⇒ y = 3
Then x = 3y = 9
Digits found: Tens = 9, Units = 3
Sum and difference of digits:
Sum = x + y = 9 + 3 = 12
Difference = x - y = 9 - 3 = 6
Difference between sum and difference of digits = 12 - 6 = 6
According to the question,
Loss 20%
Selling price
=100%−20=80%
80%=480
1=480/80
∴(Profit 20%) = 480/ 80 ×120
=Tk. 720
Question: The fourth proportional to 5, 8, and 15 is-
Solution:
Let, The fourth proportional is x.
So, 5/8 = 15/x
⇒ 5x = 120
∴ x = 24
Question: If an investment of m dollars is made today and the value of the investment doubles every 6 years, what will be the value of the investment, in dollars 24 years from today?
Solution:
Present investment = m
The investment doubles every 6 years.
∴ After 6 years, it will be 2m
∴ After (6 + 6) = 12 years, it will be (22)m = 4m
∴ After (6 + 6 + 6 + 6) = 24 years, it will be (24)m = 16m
Let the smaller number be x and greater number be y
ATQ,
4x = 3y – 5
Or, 3y – 4x = 5 ......(1)
Again,
x + y = 6(y – x) + 6
Or, x + y = 6y – 6x + 6
Or, 7x – 5y = 6 ..... (2)
Multiply equation (1) by 5 and equation (2) by 3 and add them,
15y – 20x = 25
21x – 15y = 18
_____________
∴ x = 43
From equation (1),
3y – 4 × 43 = 5
Or, 3y – 172 = 5
Or, 3y = 177
Or, y = 177/3
∴ y = 59
Question: A tank is 1/3 parts full with water. If 9 liters of water is added, the tank becomes 5/6 parts full. What is the capacity of the tank?
Solution:
Let the capacity of the tank = x liters
According to the question,
(x/3) + 9 = 5x/6
⇒ (5x/6) - (x/3) = 9
⇒ (5x - 2x)/6 = 9
⇒ 3x = 54
⇒ x = 54/3
⇒ x = 18
Therefore, the capacity of the tank = 18 liters.
Question: Find the compound interest on TK. 30000 at 7% interest compounded annually for two years.
Solution:
Principal, P = Rs 30000
Rate, R = 7%
Time, T = 2 year
By formula:
A = P(1 + R/100)T
= 30000 (1 + 7/100)2
= 30000 (107/100)2
= 30000 × (11449/10000)
= 34347
Compound Interest = A - P = 34347 - 30000
= 4347
Question:
Solution:
কোনো বর্গ ম্যাট্রিক্সের ট্রেস (Trace) হলো তার প্রধান কর্ণ বরাবর উপাদানগুলির যোগফল।
এখানে ম্যাট্রিক্স A এর প্রধান কর্ণ বরাবর উপাদানগুলি হলো 2, 5, এবং 8.
∴ Trace(A) = 2 + 5 + 8 = 15
Question: Today is Monday. After 45 days, it will be:
Solution:
Each day of the week is repeated after 7 days.
So, after 42 days, it will be Monday.
After 43 days, it will be Tuesday.
After 44 days, it will be Wednesday.
∴ After 45 days, it will be Thursday.