ব্যাখ্যা
Solution:
Let the lengths of the line segments be x and (x + 2) cm.
ATQ,
(x + 2)2 - x2 = 32
⇒ x2 + 4x + 4 - x2 = 32
⇒ 4x = 28
∴ x = 7 cm
Hence, the greater line should be, x + 2 = 7 + 2 = 9 cm
PrepBank · বিষয়ভিত্তিক প্রশ্ন
PrepBank · পাতা ১৩৮ / ১৬১ · ১৩,৭০১–১৩,৮০০ / ১৬,১২৪
Question: A boat takes 6 hours to travel 30 km upstream and 3 hours to travel the same distance downstream. Find the distance travelled by the boat in 7 hours in still water.
Solution:
Let the speed of the boat in still water be b km/h
and the speed of the current (stream) be c km/h.
Then we get,
Upstream speed = b - c
Downstream speed = b + c
Now, upstream speed = 30/6 = 5 km/h
∴ b - c = 5 ……… (1)
And downstream speed = 30/3 = 10 km/h
∴ b + c = 10 ……… (2)
Add equations (1) and (2) then we get,
(b - c) + (b + c) = 5 + 10
⇒ 2b = 15
⇒ b = 15/2
∴ b = 7.5 km/h
So, the speed of the boat in still water is 7.5 km/h.
∴ Distance travel in still water in 7 hours = speed × time
= 7.5 × 7
= 52.5 km
So the boat will travel 52.5 km in 7 hours in still water.
Question: If both 52 and 32 are factors of m where m = z × 25 × 62 × 73 , what is the smallest positive value of z?
Solution:
Given, m = z × 25 × 62 × 73
We simplify this by expressing all terms in their prime factorizations except z,
∴ 62 = (2 × 3)2 = 22 × 32
∴ m = z × 25 × 22 × 32 × 73
= z × 27 × 32 × 73
If both 52 and 32 are factors, then they must be present in the number.
From the simplified expression of m, we can see that the factor 32 is already present but the required factor 52 is missing.
To make 52 a factor of m, it must come from z.
∴ The smallest positive value of z = 52 = 25.
Question: The average temperature for Wednesday, Thursday, and Friday was 38°C. The average for Thursday, Friday, and Saturday was 40° C. If the temperature on Saturday was 41° C, what was the temperature on Wednesday?
Solution:
Average temperature for Wednesday, Thursday, and Friday = 38° C
∴ Total temperature = 3 × 38 = 114° C
Average temperature for Thursday, Friday, and Saturday = 40° C
∴ Total temperature = 40 × 3 = 120° C
Temperature on Saturday = 41° C
Now,
(Thursday + Friday + Saturday) - (Wednesday + Thursday + Friday) = 120 - 114
= 106° C
Hence, Saturday - Wednesday = 6
∴ Wednesday = 41 - 6 = 35° C
Given,
52416/312=168
⇔ 52416/ 168 =312
Now, 52.416/ 0.0168
= 524160/ 168
= (52416/ 168 )×10
=312×10
=3120
এখানে, |x - 1| = 2x
যদি x এর মান ধনাত্মক হয়, x - 1 = 2x
বা, 2x - x = -1
বা, x = -1 [গ্রহণযোগ্য নয়, কারণ এতে করে পরম মান ঋণাত্মক হয়, যা অসম্ভব]
যদি x এর মান ঋণাত্মক হয়, -(x - 1) = 2x
বা, - x + 1 = 2x
বা, 3x = 1
বা, x = 1/3
Investment = Tk. 333000
Since face value is not given, we can take it as Tk.100
and dividend per share = Tk. 11/2
Market Value = 110 + 1 = 111
Number of shares purchased = 333000/111 = 3000
Total income = 3000 × (11/2)
= Tk. 16500.
Question: A pipe can fill a tank in x hours and another pipe can empty it in y (y > x) hours. If both pipes are open, in how many hours will the tank is filled?
Solution:
Net part filled in 1 hour
= (1/x) - (1/y)
= (y - x)/xy hours
∴ The tank will be filled in = xy/(y - x) hours.
Question: Which of the following is the smallest given that x > y > 1 ?
Solution:
Given that, x > y > 1,
Consider the expressions,
∴ (x/y) >1 (since x > y)
Adding the same positive number to numerator and denominator reduces the fraction when numerator > denominator.
Thus,
(x/y) > (x+1)/(y+1) > (x + 2)/(y + 2)
Also, (x + 1)/y > (x+1)/(y+1) (larger denominator)
and xy > x > y > 1
∴ The smallest is (x + 2)/(y + 2)
Question: A train 120 meters long takes 30 seconds to cross a 480-meter-long bridge. How much time will the train take to cross a 400-meter-long platform?
Solution:
Length of train = 120 m
Length of bridge = 480 m
∴ Total distance to cross bridge = 120 + 480 = 600 m
Time taken = 30 seconds
∴ Speed of train = Total distance/Time
= 600/30 = 20 m/s
Length of platform = 400 m
∴ Total distance to cross platform = 120 + 400 = 520 m
∴ Time taken = Total distance/Speed
= 520/20 seconds
= 26 seconds
(24)2 − 1
= 28 - 1
= 256 - 1
= 255
= 3 × 5 × 17
So, the smallest prime factor is 3
Question: A boat running downstream covers a distance of 30 km in 3 hours, while it takes 5 hours to cover the same distance upstream. What is the speed of the boat in still water?
Solution:
Rate while running downstream = (30/3) km/h
= 10 km/h
Rate while running upstream = (30/5) km/h
= 6 km/h
∴ Speed of the boat in still water
= (10 + 6)/2 km/h
= 8 km/h
So, the speed of the boat in still water is 8 km/h.
Question: If |x - 2| < 5, what are the values of a and b for which a < 2x + 9 < b?
Solution:
|x - 2| < 5
⇒ - 5 < x - 2 < 5
⇒ - 5 + 2 < x - 2 + 2 < 5 + 2
⇒ - 3 < x < 7
⇒ - 6 < 2x < 14
⇒ - 6 + 9 < 2x + 9 < 14 + 9
∴ 3 < 2x + 9 < 23
Compare with a < 2x + 9 < b.
We get, a = 3 and b = 23
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
Question: What number should come next in the series:
5, 7, 13, 31, 85,.......?
Solution:
দেওয়া আছে,
সিরিজটি হলো: 5, 7, 13, 31, 85,.......
পার্থক্যগুলোর মধ্যে একটি প্যাটার্ন রয়েছে। প্রতিটি পার্থক্য আগের পার্থক্যের 3 গুণ।
5 থেকে 7 পর্যন্ত পার্থক্য: 2
7 থেকে 13 পর্যন্ত পার্থক্য: 6 (2 × 3)
13 থেকে 31 পর্যন্ত পার্থক্য: 18 (6 × 3)
31 থেকে 85 পর্যন্ত পার্থক্য: 54 (18 × 3)
সুতরাং, পরবর্তী পার্থক্যটি হবে:
54 × 3 = 162
পরবর্তী সংখ্যাটি হবে শেষ সংখ্যা এবং এই পার্থক্যের যোগফল:
85 + 162 = 247
∴ পরবর্তী সংখ্যাটি হলো 247
Question: A train covers a distance of 600 meters in 25 seconds, whereas a car covers a distance of 43.2 km in 36 minutes. What is the ratio of the speed of the train to the speed of the car?
Solution:
ট্রেনের গতিবেগ নির্ণয়:
দূরত্ব = 600 মিটার, সময় = 25 সেকেন্ড।
∴ ট্রেনের গতিবেগ = 600/25 মিটার/সেকেন্ড
= 24 মিটার/সেকেন্ড।
গাড়ির গতিবেগ নির্ণয়:
দূরত্ব = 43.2 কিমি = 43.2 × 1000 = 43200 মিটার।
সময় = 36 মিনিট = 36 × 60 = 2160 সেকেন্ড।
∴ গাড়ির গতিবেগ = 43200/2160 মিটার/সেকেন্ড
= 20 মিটার/সেকেন্ড।
গতিবেগের অনুপাত = ট্রেনের গতিবেগ : গাড়ির গতিবেগ
= 24 : 20
= 6 : 5
∴ তাদের গতিবেগের অনুপাত হলো 6 : 5
Question: After paying a 10 percent tax on all income over Tk. 3,000, a person had a net income of Tk. 12,000. What was the income before taxes?
Solution:
প্রশ্নে ৩০০০ টাকা পর্যন্ত আয়ের উপর কোন কর দেয়া লাগে না এবং ৩০০০ টাকার উপর আয় করলে বাকি টাকার উপর কর দিতে হয়।
ধরি,
আয়ের করযুক্ত অংশ ক টাকা
∴ ক - ক এর ১০% + ৩০০০ = ১২০০০
বা, ক - (১০ক)/১০০ + ৩০০০ = ১২০০০
বা, ক - ক/১০ = ৯০০০
বা, ১০ক - ক = ৯০০০০
বা, ৯ক = ৯০০০০
∴ ক = ১০০০০
∴ করযুক্ত টাকা ১০০০০ এবং করমুক্ত টাকা ৩০০০
∴ মোট টাকা (১০০০০ + ৩০০০) = ১৩০০০ টাকা
∴ যদি কর না দিত তাহলে তাঁর আয় ১৩০০০ টাকা হত। কিন্তু ১০০০ টাকা কর দিয়ে দেয়ায় তার আয় থাকে ১২০০০ টাকা
Question: In traveling from a dormitory to a certain city, a student went 1/5 of the way by foot, 2/3 of the way by bus, and the remaining 8 kilometers by car. What is the distance, in kilometers, from the dormitory to the city?
Solution:
Let,
total distance x kilometers
ATQ,
x/5 + 2x/3 + 8 = x
⇒ x - x/5 - 2x/3 = 8
⇒ (15x - 3x - 10x)/15 = 8
⇒ 2x = 120
∴ x = 60
Question: In a class, 25 students play football, 15 students play cricket, and 5 students play both. 10 students play neither football nor cricket. What is the total number of students in the class?
Solution:
Number of students who play football, n(F) = 25
Number of students who play cricket, n(C) = 15
Number of students who play both football and cricket, n(F ∩ C) = 5
Number of students who play neither = 10
n(F ∪ C) = n(F) + n(C) - n(F ∩ C)
= 25 + 15 - 5
= 35
Total students in the class = students who play football or cricket + students who play neither
= 35 + 10
= 45
∴ There are 45 students in the class.
A dice has 6 faces.
So there are 6 possible outcomes
Dice are rolled once AND then again.
So total possibilities = 6 x 6 = 36
The sum should be 8 of the 2 throws.
So which combination of numbers from 1 to 6 will yield us a sum of 8?
They are - (2,6); (6,2); (3,5); (5,3); (4,4)
So there are a total of 5 possibilities where the addition is 8.
But only 1 possibility where the first throw of dice is 4.
So, the Probability for the first throw to be 4 and sum to be 8 = 1/36.
Question: Ratul is four times as old as Tarek. 12 years ago, Ratul was 10 times as old as Tarek. What will be the sum of their ages after 5 years?
Solution:
ধরি, বর্তমানে Tarek-এর বয়স = x বছর।
তাহলে Ratul-এর বয়স = 4x বছর।
12 বছর আগে তাদের বয়স ছিল:
Tarek = x - 12 বছর
Ratul = 4x - 12 বছর
প্রশ্নমতে,
4x - 12 = 10(x - 12)
⇒ 4x - 12 = 10x - 120
⇒ 120 - 12 = 10x - 4x
⇒ 108 = 6x
⇒ x = 108/6
∴ x = 18
∴ বর্তমানে Tarek এর বয়স = 18 বছর,
Ratul এর বয়স = 4 × 18 = 72 বছর
5 বছর পর তাদের বয়স হবে:
Tarek = 18 + 5 = 23 বছর
Ratul = 72 + 5 = 77 বছর
∴ 5 বছর পর তাদের বয়সের যোগফল = 23 + 77 = 100 বছর
Question: What will replace the '?' mark?
Solution:
এখানে, উপরের সংখ্যাটি নিচের দুটি সংখ্যার যোগফলের দ্বিগুণ।
১ম চিত্রে,
(15 + 10) × 2 = 25 × 2 = 50
২য় চিত্রে,
(30 + 15) × 2 = 45 × 2 = 90
একইভাবে, ৩য় চিত্রে,
(25 + 10) × 2 = 35 × 2 = 70
সুতরাং, সঠিক উত্তরটি হবে 70।
Area of the carpet :
= [(5 - 0.20) × (8 - 0.20)] m2
= (4.8 × 7.8) m2
= 37.44 m2
∴ Cost of carpeting :
= Tk. (37.44 × 18)
= Tk. 673.92
Question:
Solution:
A:B = 3:2 = 6:4
A:C = 2:1 = 6:3
A:B:C = 6:4:3
∴ B's share = 4/13 × 157300 = 48400
We are given selling price = Tk. 580 and expected profit of 15%
Therefore, we can easily solve this numerical, considering basic formulae of profit and loss.
Let cost price = x
Selling price = C.P. + Profit
S.P. = C.P. + (15% of C.P.) [We know that profit is gained on cost price]
580 = x + (0.15 x)
580 = 1.15 x
Therefore,
x = 504.347
Cost Price = Tk. 504.35
Now,
we have the cost price and hence,
Profit = S.P. – C.P. = 580 – 504.35
= Tk. 75.65
The trader gets a profit of Tk. 75.65
Question: If m is the average of the first 7 positive multiples of 4 and if M is the median of the first 7 positive multiples of 4, what is the value of M - m?
Solution:
4-এর প্রথম 7টি ধনাত্মক গুণিতক হলো= {4, 8, 12, 16, 20, 24, 28}
(এখানে পদের সংখ্যা, n = 7)
ধাপ 1: গড় (m) নির্ণয়:
যেহেতু এটি একটি সমান্তর ধারা (Arithmetic Progression), গড় হলো প্রথম ও শেষ পদের গড়।
m = (প্রথম পদ + শেষ পদ)/2
∴ m = (4 + 28)/2 = 32/2 = 16
ধাপ 2: মধ্যমা (M) নির্ণয়:
যেহেতু পদসংখ্যা বিজোড় (n = 7),
∴ মধ্যমা হবে (7 + 1)/2 বা 4র্থ পদ।
4র্থ পদ = 16
∴ M = 16
ধাপ 3: M - m এর মান নির্ণয়:
M - m = 16 - 16
∴ M - m = 0
অতএব, M - m এর মান হলো 0।
Shortcut:
যেহেতু 4-এর গুণিতকগুলো একটি সমান্তর ধারা (Arithmetic Progression) তৈরি করে, তাই যেকোনো সমান্তর ধারার ক্ষেত্রে গড় (m) এবং মধ্যমা (M) সর্বদা সমান হয়। অতএব, M - m = 0 হবে।
Question: A person 1.8 meters tall sees the top of a tree in a small mirror placed on the ground. The mirror is 1 meter away from the person's feet and 150 meters away from the base of the tree. What is the height of the tree?
Solution:
ধরি, মানুষের উচ্চতা, AB = 1.8 m
মানুষ এবং আয়নার দূরত্ব, BC = 1 m
গাছের উচ্চতা, ED = h
গাছ এবং আয়নার দূরত্ব, CD = 150 m
আলোর প্রতিফলনের সূত্র অনুসারে, ∠ACB = ∠ECD (আপতন কোণ = প্রতিফলন কোণ)।
∴ ΔABC এবং ΔEDC সদৃশ।
সদৃশ ত্রিভুজের ধর্ম অনুসারে:
AB/ED = BC/CD
⇒ 1.8/h = 1/150
⇒ h × 1 = 1.8 × 150
⇒ h = 270 m
অতএব, গাছটির উচ্চতা = 270 meters।
Question: If P = 5 + √3, then find the value of P2 ?
Solution:
Given that,
P = 5 + √3
∴ P2= (5 + √3)2
= 52 + 2 × 5 × √3 + (√3)2
= 25 + 10√3 + 3
= 28 + 10√3
Question: A mixture contains two liquids A and B are in the ratio 2 : 1. If 6 litres of mixture is withdrawn and replaced with 6 litres of B, then the ratio becomes 3 : 2. What was the initial quantity of A?
Solution:
মনে করি,
মিশ্রণের প্রাথমিক পরিমাণ = 3X লিটার
A এর পরিমাণ = 2X লিটার
B এর পরিমাণ = X লিটার
∴ 6 লিটার মিশ্রণ তুলে নেওয়ার পর,
A এর পরিমাণ = 2X - (2/3) × 6 = (2X - 4) লিটার
B এর পরিমাণ = X - (1/3) × 6 = (X - 2) লিটার
আবার,
B তে 6 লিটার যোগ করার পর,
B এর পরিমাণ = X - 2 + 6 = (X + 4) লিটার
প্রদত্ত অনুপাত,
(2X - 4) /(X + 4) = 3/2
বা, 4X - 8 = 3X + 12
বা, X = 12 + 8
∴ X = 20
তাহলে, A এর পরিমাণ = 2 × 20 = 40 লিটার
Question: A square and a circle have the same perimeter. The side of the length of square is 44 cm, what is the area of the circle?
Solution:
Perimeter of the square = 4 × side length
= 4 × 44 cm
= 176 cm
As per the question, the square and circle have the same perimeter.
∴ Circumference of the circle = 176 cm
We know that, Circumference of the circle = 2πr
∴ 2πr = 176
⇒ r = 176/(2π)
⇒ r = 88/π
⇒ r = 88/(22/7)
⇒ r = 88 × 7/22
⇒ r = 4 × 7
⇒ r = 28 cm
Area of the circle = πr2
= (22/7) × 282
= (22/7) × (28 × 28)
= 22 × 4 × 28
= 2464 sq. cm
∴ The area of the circle is 2464 sq. cm.
Question: A right triangle has sides 6 cm, 8 cm, and 10 cm. What is its area?
Solution:
Given that,
A right triangle with sides are 6 cm, 8 cm, and 10 cm.
We know,
Area = (1/2) × base × height
= (1/2) × 6 × 8
= 24 cm2
So the area of the right triangle is 24cm2.
Question: A solid metal sphere of radius 10 cm is melted and recast into solid cones of radius 5 cm and height 12 cm. How many cones can be made?
Solution:
The volume of a sphere = (4/3)πr3
= (4/3)π(10)3
= (4000π/3) cm3
The volume of a cone = (1/3)πr2h
= (1/3)π(5)2(12)
= 100π cm3
Number of cones = (4000π/3)/100π
= 40/3
= 13. 33
= 13 (approx)
Question: State the equation of the vertical line that goes through the point (-3, 5).
Solution:
একটি উল্লম্ব রেখা (vertical line) হলো এমন একটি সরলরেখা যা Y-অক্ষের সমান্তরাল। এই ধরনের রেখার একটি বিশেষ বৈশিষ্ট্য হলো, রেখার উপর অবস্থিত প্রতিটি বিন্দুর x-স্থানাঙ্ক (x-coordinate) একই থাকে, কিন্তু y-স্থানাঙ্ক (y-coordinate) পরিবর্তিত হতে পারে।
উল্লম্ব রেখার সাধারণ সমীকরণ হলো: x = a, যেখানে a একটি ধ্রুবক সংখ্যা এবং রেখার প্রতিটি বিন্দুর x এর মান একই থাকে।
প্রশ্নে বলা হয়েছে রেখাটি (- 3, 5) বিন্দুর মধ্য দিয়ে যায়।
যেহেতু এই বিন্দুর x-স্থানাঙ্ক হলো - 3,
সুতরাং রেখাটির সমীকরণ হবে: x = - 3
Question: Last year, Company X made p dollars in profit. Half of the profit went to the company's founder. The rest was split evenly among his four other partners. In terms of p, how much did each of the other partners receive?
Solution:
Here,
Company X's profit is p dollars.
Half of the profit went to the founder, so the founder received,
1/2 of p = p/2
Remaining Profit = p - p/2 = p/2
The remaining profit was split among 4 partners.
∴ Each partner gets = (p/2) ÷ 4
= (p/2) × (1/4)
= p/8
Question: Two numbers are in the ratio 2 : 3. If 4 is subtracted from the first number, the ratio becomes 1 : 2. What are the numbers?
Solution:
Let the two numbers be: 2x and 3x
According to the question,
(2x - 4)/3x = 1/2
⇒ 2(2x - 4) = 3x
⇒ 4x - 8 = 3x
⇒ x = 8
∴ First number = 2 × 8 = 16
∴ Second number = 3 × 8 = 24
Let,
the number be x.
Then, (100 + 37.5)% of x
⇒ 137.5% of x = 33
⇒ 137.5 × (1/100) × x = 33
⇒ x = (33 × 100)/137.5
⇒ x = 24.
Question: In how many ways can 4 people from a group of 7 people be seated around a circular table?
Solution:
4 people out of 7 = 7C4
= 7!/4!(7 - 4)!
= 7!/(4! × 3!)
= 35
And 4 people around a circular table = (4 - 1)! = 3! = 6
∴ Total ways = 6 × 35 = 210
Question: A committee of 3 men and 2 women is to be formed from 5 men and 4 women. In how many ways can the committee be formed?
Solution:
We have 5 men and 4 women.
We need to choose 3 men from 5 and 2 women from 4.
∴ Number of ways = 5C3 × 4C2
= {5!/3!(5 - 3)!} × {4!/2!(4 - 2)!}
= {(5 × 4)/2} × {(4 × 3)/2}
= 10 × 6
= 60 ways
Let, the number be z,
Then, 7z – 15 = 2z + 10
⇒ 5z = 25
⇒ z = 5.
Hence, the required number is 5.
Given that,
The area of the field = 680 sq. feet
⇒ lb = 680 sq. feet
Length(l) = 20 feet
⇒ 20 × b = 680
⇒ b = 680/20
= 34 feet
∴ Required length of the fencing = l + 2b
= 20 + (2 × 34)
= 88 feet