ব্যাখ্যা
Solution:
8 hours to build 50 engines by 50 workers
1 hour to build 1 engine by = (50 × 8)/50 workers
10 hours to build 100 engine by = (8 × 100)/10 workers
= 80 workers
∴ extra workers = 80 - 50 = 30
PrepBank · বিষয়ভিত্তিক প্রশ্ন
PrepBank · পাতা ৪ / ১১ · ৩০১–৪০০ / ১,০৭৬
Question: A lift can carry 12 adults or 20 children at a time. If there are 9 adults in the lift, how many children can be loaded onto it?
Solution:
এখানে,
12 জন প্রাপ্তবয়স্ক (Adults) = 20 জন শিশু (Children)
∴ 1 জন প্রাপ্তবয়স্ক = 20 / 12 = 5/3 জন শিশু
∴ 9 জন প্রাপ্তবয়স্ক = 9 × 5/3 = 15 জন শিশু
লিফটের সর্বোচ্চ ধারণক্ষমতা = 20 জন শিশু
∴ আরও শিশু বহন করা যাবে = 20 - 15 = 5 জন শিশু
সুতরাং, 9 জন প্রাপ্তবয়স্কের সাথে আরও 5 জন শিশুকে লিফটে নেওয়া যাবে।
Work done by 20 women in 1 day = 1/16
Work done by 1 woman in 1 day = 1/(16 × 20)
Work done by 16 men in 1 day = 1/15
Work done by 1 man in 1 day = 1/(15 × 16)
Efficiency of a man : efficiency of a woman
= 1/(15 × 16) : 1/(16 × 20)
= 1/15 : 1/20
= 1/3 : 1/4
= 4 : 3
Question: Adnan can do 1/5 of a work in 8 days. In how many days will he complete the work?
Solution:
Adnan can do 1/5 of a work in 8 days.
∴ He will complete the work in = 8 × 5 = 40 days
∴ Adnan will complete the work in 40 days.
Question: A truck can carry 24 motorcycles or 36 bicycles at a time. If there are 10 motorcycles on the truck, how many bicycles can be loaded along with them?
Solution:
Here,
24 motorcycles = 36 bicycles
∴ 1 motorcycle = 36/24 bicycles = 3/2 bicycles
∴ 10 motorcycles = 10 × 3/2 = 15 bicycles
Total bicycle capacity = 36
∴ Remaining bicycles that can be loaded = 36 - 15 = 21 bicycles
∴ Required number of bicycles = 21
Question: Hasan can dig 18 holes in 12 minutes. Faruk can dig the same number of holes in only 6 minutes. Hasan digs the first 9 holes, then Faruk digs for 2 minutes, and finally Hasan finishes the remaining holes. How long will it take them to dig 27 holes in total?
Solution:
Faruk can dig 18 holes in 6 minutes.
∴ In 2 minutes, he can dig = (18 × 2)/6 holes
= 6 holes
Hasan first digs 9 holes.
∴ Total completed = 9 (Hasan) + 6 (Faruk) = 15 holes
Remaining = 27 - 15 = 12 holes
Hasan can dig 18 holes in 12 minutes.
∴ To dig 12 holes, Hasan will take = (12 × 12) / 18 = 8 minutes
Time Hasan spent digging first 9 holes = (12 × 9)/18 = 6 minutes
∴ Total time = 6 (Hasan) + 2 (Faruk) + 8 (Hasan) = 16 minutes
Question: A 100 m long 3 m high and 30 cm wide wall is built by 30 men, 20 women and 50 children working 9 hours a day in 20 days. How long a wall 1.5 m high 30 cm wide can be built by 15 men, 25 women and 35 children working 2 hour a day in 15 days (given men, women and children are equally efficient)?
Solution:
Earlier dimensions of the wall = 100 × 3 × 0.30.
Volume of the wall = 90
New dimensions = L × 1.5 × 0.3.
Volume of the wall = 0.45L
∴ As men, women and children are given to be equally efficient, so in the first case, the total number of persons is (30 + 20 + 50) = 100 and the same in the second case is (15 + 25 + 35) = 75
working 9 hours a day in 20 days 100 persons make 90 m3 wall
∴ working 1 hours a day in 1 days 1 persons make 90/(100 × 20 × 9) m3 wall
∴ working 2 hours a day in 15 days 75 persons make (90 × 75 × 15 × 2)/(100 × 20 × 9) m3 wall
= 11.25
∴ Length of the wall = L = 11.25/0.45 = 25 m
প্রথম 5 টি copy এর প্রত্যেকটি দেখতে সময় লাগে = 30/5
= 6 মিনিট
পরের 30 টি copy এর প্রত্যেকটি দেখতে সময় পাবে = 150/30
= 5 মিনিট
বর্তমান রেট - 1/6
কাঙ্ক্ষিত রেট - 1/5
বাড়াতে হবে - 1/30
অতএব, {(1/30) / (1/6)} × 100
= 20% faster হতে হবে ।
A and B complete a work in = 15 days
One day's work of (A + B) = 1/15
B complete the work in = 20 days;
One day's work of B = 1/20
Then, A's one day's work = 1/15 - 1/20
= (4 - 3)/60
= 1/60
Thus, A can complete the work in = 60 days.
Question: P, Q and R can do a job in 20, 30 and 60 days respectively. In how many days can P do the job if he is assisted by Q and R every third day?
Solution:
P's 2 days' work = 2/20
= 1/10
∴ (P + Q + R)'s 1 day's work
= (1/20 + 1/30 + 1/60)
= 6/60
= 1/10
∴ Job done in 3 days [P alone 2 days + (P+Q+R) 1 day] = (1/10 + 1/10) = 1/5
Now, 1/5 jobs is done in 3 days
∴ The whole job will be done in (3 x 5) = 15 days.
A can do the work in 3 days. So, in 1 day a does 1/3 amount of work.
B takes double the time as A. So, B can do the work in 6 days. So, in 1 day B does 1/6 amount of work
C takes one more day in addition to the time taken by B. So, C can do the work in 7 days. So, in 1 day C does 1/7 amount of work
When they work together, in 1 day they complete how much work?
In 1 day A, B and C together complete = 1/3 + 1/6 + 1/7 = 9/14 amount of work
A, B and C together complete the entire work in 14/9 days.
We Know
Total work = rate × Time
Therefore, Rate = 30/6 = 5 task/hr
Now we need to find the number of computers
Given, total work = 80 task and total time = 3 hrs
So, No. of computers = 80 / (5×3) = 5.33, but no. of computers cannot be fraction, so we have to consider it as 1.
∴ Total no. of computers = 5+1 = 6.
Let the required number of days be x.
Less spiders, More days (Indirect Proportion)
Less webs, Less days (Direct Proportion)
Spiders 1:7 and Webs 7:1 } :: 7:x
=> 1 × 7 × x = 7 × 1 × 7
=> x = 7
Question: A is twice as good a workman as B and therefore can finish a job 30 days earlier than B. Working together, in how many days can they finish the job?
Solution:
Given,
A is twice as good workman as B. Means,
A = 2B
Let B can finish work in X days, then A will finish same work in (X - 30) days alone
Now,
BX = 2B × (X - 30)
⇒ BX = 2BX - 60B
∴ X = 60 days
B can finish work in 60 days, then A can finish the work in 30 days.
One day work of B = 1/60
One day work of A = 1/30
One day work of (A+B) = (1/60) + (1/30) ⇒ (1+2)/60 ⇒ 3/60 ⇒ 1/20
So, they can finish work together in 20 days.
Question: A group of women decided to do a job in 5 days. But since 15 women dropped out every day, the job completed at the end of the 8th day. How many women were there at the beginning?
Solution:
Let X be the initial number of women then,
According to the question,
5X = X + (X - 15) + (X - 30) + (X - 45) + (X - 60) + (X - 75) + (X - 90) + (X - 105)
⇒ 5X = 8X - 420
⇒ 8X - 5X = 420
⇒ 3X = 420
⇒ X = 420/3
∴ X = 140 women
Question: A team of workers can finish a project in 20 days. However, when 5 of them were absent, it took 25 days to complete the same work. How many workers were originally assigned to the project?
Solution:
Let,
the total number of people working originally = x
When 5 people were absent,
Total present workers = x - 5
x workers can complete the work in 20 days
∴ 1 worker can complete it in 20x days
∴ (x - 5) workers can complete it in 20x/(x - 5) days
ATQ,
20x/(x - 5) = 25
⇒ 4x/(x - 5) = 5
⇒ 5x - 25 = 4x
∴ x = 25
∴ The total number of people working originally = 25
Question: Apu was assigned to do 2 similar tasks. He completes the second task in two-thirds the time it takes him to complete the first task. If it took him an hour to complete both the tasks, in how many minutes did he complete the second task?
Solution:
Let the time taken for the first task be t minutes.
Then, time for the second task = 2t/3 minutes.
Total time for both tasks = 1 hour = 60 minutes.
ATQ,
t + (2t/3) = 60
⇒ (3t + 2t)/3 = 60
⇒ 5t = 60 × 3
⇒ t = (60 × 3)/5
∴ t = 36
∴ Second task = 2t/3 = (2 × 36)/3 = 24 minutes
So Apu completed the second task in 24 minutes.
Number of pages typed by Robi in 1 hour = 32/6 = 16/3 .
Number of pages typed by Kamal in 1 hour = 40/5 = 8
Number of pages typed by both in 1 hour = (16/3 + 8) = 40/3
Therefore, Time taken by both to type 110 pages = 110/(40/3) hours
= 110 × 3/40 hours (or) 8 hours 15 minutes.
Question: A does a work in 12 days, B in 15 days, and C can do half the work in 10 days. How long will it take them to complete the whole work if they work together?
Solution:
A,
12 দিনে করে কাজটির = 1 অংশ
∴ 1 দিনে করে কাজটির = 1/12 অংশ
B,
15 দিনে করে কাজটির = 1 অংশ
∴ 1 দিনে করে কাজটির = 1/15 অংশ
C,
10 দিনে করে কাজটির = 1/2 অংশ
∴ 1 দিনে করে কাজটির = 1/20 অংশ
A, B ও C একত্রে করে = (1/12) + (1/15) + (1/20)
= (5 + 4 + 3)/60
= 12/60
= 1/5 অংশ
A, B ও C একত্রে 1/5 অংশ করে = 1 দিনে
∴ 1 বা সম্পূর্ণ অংশ করে = (1 × 5) দিনে
= 5 দিনে
April has 30 days. So Protik takes 30 days to build the pavement.
Mahmud is 25% faster than Protik
25% = 25/100 = .25
This means, if Protik is 1, then Mahmud is (1 + 0.25) = 1.25
Protik takes 30 days to do the work.
Mahmud will take = 30/1.24 = 24 days to get the work done.
Quarter of Kg means 250 gm
Less weight, less price (Direct Proportion)
So, 250 : 200 :: 60 : x
=> x = 48
So 200 gm will cost 48 poysa.
(7 × 12) men can complete the work in 1 day.
∴ 1 man's 1 day's work = 1/84.
7 men's 5 day's work = (1/12) × 5
= 5/12.
Remaining work = 1 - (5/12)
= 7/12
5 men's 1 day's work = (1/84) × 5
= 5/84.
5/84 work is done by them in 1 days.
7/12 work is done by them in (84/5) × (7/12)
= 49/5 days.
= 9(4/5) days.
Question: What is the solution of the inequality: - 6 ≤ 3x + 3 < 27?
Solution:
- 6 ≤ 3x + 3 < 27
⇒ - 6 - 3 ≤ 3x + 3 - 3 < 27 - 3
⇒ - 9 ≤ 3x < 24
⇒ - 9/3 ≤ 3x/3 < 24/3
⇒ - 3 ≤ x < 8
∴ solution of the inequality: [-3, 8)
Question: If 8 men or 12 women can build a 240-meter road in 10 days, how many days will 6 men and 6 women take to build a 360-meter road?
Solution:
দেওয়া আছে, ৮ জন পুরুষের কাজের ক্ষমতা = ১২ জন মহিলার কাজের ক্ষমতা
অর্থাৎ, ২ জন পুরুষ = ৩ জন মহিলা
এখন,
৩ জন মহিলা = ২ জন পুরুষ
∴ ১ জন মহিলা = (২/৩) জন পুরুষ
∴ ৬ জন মহিলা = ৬ × (২/৩) = ৪ জন পুরুষ
সুতরাং, মোট শ্রমিক সংখ্যা = ৬ জন পুরুষ + ৪ জন পুরুষ = ১০ জন পুরুষ।
৮ জন পুরুষ ২৪০ মিটার রাস্তা তৈরি করে ১০ দিনে।
∴ ১ জন পুরুষ ২৪০ মিটার রাস্তা তৈরি করে = (১০ × ৮) = ৮০ দিনে
∴ ১ জন পুরুষ ১ মিটার রাস্তা তৈরি করে = (৮০ ÷ ২৪০) = ১/৩ দিনে
∴ ১০ জন পুরুষ ১ মিটার রাস্তা তৈরি করে = (১/৩ ÷ ১০) = ১/৩০ দিনে
∴ ১০ জন পুরুষ ৩৬০ মিটার রাস্তা তৈরি করে = (১/৩০) × ৩৬০ = ১২ দিনে।
∴ ৬ জন পুরুষ এবং ৬ জন মহিলা ৩৬০ মিটার রাস্তা তৈরি করতে ১২ দিন সময় নেবে।
Question: In a camp of soldiers there was a stock of food for 90 days for 6000 soldiers. After 30 days, 2400 soldiers left the barracks. For how many days shall the leftover food last for the remaining soldiers?
Let,
the remaining food last for P days
6000 soldiers had provision for 90 days
3600 soldiers had provision for P days
ATQ,
3600/6000 = 60/P
⇒ 3/5 = 60/P
⇒ 3P = 300
⇒ P = 300/3
∴ P = 100
The remaining food last for 100 days for the remaining soldiers.
Question: 3 pumps working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day?
Solution:
3 pumps need 2 × 8 hours = 16 hours
1 pump needs 16 × 3 hours
4 pumps need (16 × 3)/4 hours
= 12 hours
Question: If the workforce is doubled, how much longer will it take to finish the task?
Solution:
ধরি,
শ্রমিক সংখ্যা = x, এর দিগুণ = 2x,
সময় = n
x জন কাজটি করে n সময়ে
১ জন কাজটি করে = xn সময়ে
২x জন কাজটি করে = xn/২x
= n/২ সময়ে বা ১/২ সময়ে।
Question: If 3 jackets and 5 sweaters cost Tk. 12,000, and 5 jackets and 3 sweaters cost Tk. 13,600, what is the cost of one jacket?
Solution:
ধরি, একটি জ্যাকেটের মূল্য x টাকা এবং একটি সোয়েটারের মূল্য y টাকা।
প্রশ্নমতে,
3x + 5y = 12000 ............... (i)
5x + 3y = 13600 .............. (ii)
(ii) × 5 - (i) × 3 ⇒
(25x + 15y) - (9x + 15y) = 68000 - 36000
⇒ 25x - 9x = 32000
⇒ 16x = 32000
⇒ x = 32000/16
⇒ x = 2000
সুতরাং, একটি জ্যাকেটের মূল্য 2000 টাকা।
Question: A contractor employs 45 persons to do a job in 40 days. After 10 days, it was found that only one-sixth of the work was finished. How many more persons are to be employed to finish the job as per schedule?
Solution:
দেওয়া আছে:
মোট লোক = 45 জন
নির্ধারিত সময় = 40 দিন
10 দিনে সম্পন্ন কাজ = 1/6 অংশ
ধরি, সম্পূর্ণ কাজ = 1 একক
45 জন লোক 10 দিনে করে = 1/6 অংশ কাজ
∴ 45 জন লোক 1 দিনে করে = (1/6) ÷ 10 = 1/60 অংশ
∴ 1 জন লোক 1 দিনে করে = (1/60) ÷ 45 = 1/2700 অংশ
অবশিষ্ট কাজ = 1 - 1/6 = 5/6 অংশ
অবশিষ্ট সময় = 40 - 10 = 30 দিন
∴ অবশিষ্ট 5/6 অংশ কাজ 30 দিনে করতে হবে
∴ প্রতিদিনের প্রয়োজনীয় কাজের হার = (5/6) ÷ 30 অংশ
= 5/180 = 1/36 অংশ
এখন,
প্রতিদিন 1/2700 অংশ কাজ করে 1 জন
∴ 1 অংশ কাজ করে = 1 ÷ (1/2700) জন
∴ 1/36 অংশ কাজ করে = (2700/36) জন
= 75 জন
∴ অতিরিক্ত লোকের প্রয়োজন = 75 - 45 = 30 জন
Ratio of rates of working of A and B = 2:1.
So, ratio of times taken = 1:2
Therefore, A's 1 day's work = 1/9
B's 1 day's work = 1/18
(A + B)'s 1 day's work = 1/9 + 1/18 = 1/6
So, A and B together can finish the work in 6 days.
Question: A can finish a job in 18 days, B in 12 days, and C in 6 days. B and C begin the work together but have to stop after working for 2 days. How many days will A alone take to complete the remaining work?
Solution:
Work done by B and C in 1 day:
B's 1-day work = 1/12,
C's 1-day work = 1/6
B + C in 1 day = 1/12 + 1/6
= (1 + 2)/12
= 3/12
= 1/4
Work done by B and C in 2 days = 2 × 1/4 = 1/2
Remaining work = 1 - 1/2 = 1/2
A's 1-day work = 1/18
∴ Time for A to finish remaining work = (1/2) ÷ (1/18)
= 1/2 × 18
= 9 days
Question: Working 5 hours a day, Samiya can complete a work in 8 days and working 6 hours a day, Fahima can complete the same work in 10 days. Working 6 hours a day, they can jointly complete the work in:
Solution:
Working 5 hours a day, Samiya can complete a work in 8 days = 8 × 5 = 40 hours
Working 6 hours a day, Fahima can complete a work in 10 days = 6 × 10 = 60 hours
(Samiya and Fahima)'s 1 hour's work = (1/40) + (1/60)
= (3 + 2)/120
= 5/120
= 1/24
They can jointly complete the work in 24 hours
Working 6 hours a day, they can jointly complete the work in = 24/6 = 4 days
Question: A contractor undertook to finish a piece of work in 100 days and employed 75 men. After 50 days, 2/5 of the work was completed. How many additional men should be employed to complete the work on schedule?
Solution:
We know that 75 men completed 2/5 of the work in 50 days. Therefore, the amount of work done by 1 man in 50 days is:
Work done by 1 man in 50 days = 2/(5×75) = 2/375
Remaining work = 1 - 2/5 = 3/5
Number of men required = Remaining work / Work done by 1 man in 50 days
= (3/5)/(2/375)
= 112.5
Since the number of workers must be an integer, round up to 113 workers.
Additional workers = 113 − 75 = 38
Question: P takes twice as much time as Q or three times as much time as R to finish a piece of work. Working together, they can finish the work in 2 days. Q can do the work alone in how many days?
Solution:
ধরা যাক,
P, Q ও R এর যথাক্রমে কাজটি শেষ করতে সময় লাগে x, x/2, এবং x/3 দিন।
তারা একসাথে 2 দিনে কাজ শেষ করে।
অর্থাৎ তাদের একদিনের কাজ হলো 1/2 অংশ।
∴ P + Q + R এর একদিনের কাজ = (1/x) + (2/x) + (3/x)
= (1 + 2 + 3)/x
= 6/x
শর্তমতে,
6/x = 1/2
∴ x = 12
∴ Q একা কাজ শেষ করতে সময় নেবে = 12/2 = 6 দিন।
Suppose,
A, B and C take x, x/2 and x/3 days respectively to finish the work.
Then,
(1/x) + (2/x) + (3/x) = 1/2
⇒ 6/x = 1/2
⇒ x = 12.
So, B takes 6 days to finish the work.
Question: A plumber charges Tk. 60 as a service fee plus Tk. 25 per hour for labor. If a customer's total cost is Tk. 185, what is the maximum number of full hours the plumber can work?
Solution:
Given that,
Fixed service fee = Tk. 60
Charge per hour = Tk. 25
Total bill = Tk. 185
Let h = number of full hours the plumber works.
Now, total cost equation,
60 + 25h ≤ 185
⇒ 25h ≤ 185 - 60
⇒ 25h ≤ 125
⇒ h ≤ 125/25
∴ h ≤ 5
So, the plumber can work a maximum of 5 full hours.
Question: If the cost of q metres of wire is Tk. k, then what is the cost of p metres of wire at the same rate (in Tk)?
Solution:
Cost of q metres = Tk. k
Cost of 1 metre = Tk. k/q
Cost of p metres = Tk. (k × p/q) = Tk. kp/q
Question: X can do a work in 15 days, and Y in 10 days. They work together for 3 days. How much of the work is left?
Solution:
X, 15 দিনে করতে পারে কাজটির 1 অংশ
∴ X ,1 দিনে করতে পারে কাজটির 1/15 অংশ
Y, 10 দিনে করতে পারে কাজটির 1 অংশ
∴ Y, 1 দিনে করতে পারে কাজটির 1/10 অংশ
X ও Y 1 দিনে একত্রে করতে পারে কাজটির = {(1/15) + (1/10)} অংশ
= (2 + 3)/30 অংশ
= 5/30 অংশ
= 1/6 অংশ
X ও Y 3 দিনে করতে পারে কাজটির (3 × 1/6) অংশ
= 1/2 অংশ
কাজ বাকি থাকে = 1 - (1/2) অংশ
= (2 - 1)/2 অংশ
= 1/2 অংশ
∴ কাজটির 1/2 অংশ বাকি থাকে।
Question: A factory has two machines, X and Y. Machine X can produce 6,000 items in 10 days, working 6 hours per day. Machine Y can produce 8,000 items in 8 days, working 10 hours per day. If both machines work together for 8 hours per day, how many days will they take to produce 24,000 items?
Solution:
Total hours worked by Machine X = 10 days × 6 hours/day = 60 hours.
Rate of X = (6000/60) = 100 items/hour
Total hours worked by Machine Y = 8 days × 10 hours/day = 80 hours.
Rate of Y = (8000/80) = 100 items/hour
Combined rate = Rate of X + Rate of Y = 100 + 100 = 200 items/hour.
So, time required = {24000/(200 × 8)} = 15 days.
Let, 1 man's 1 day's work = x and
1 boy's 1 day's work = y
Then, 12x + 16y = 1/5
and 13x + 24y = 1/4.
Solving these two equations, we get,
x = 1/100 and
y = 1/200
∴ Required ratio = x : y
= 1/100 : 1/200
= 2 : 1.
Question: A and B can complete a piece of work in 18 days and 12 days respectively. They got a contract to complete the work for TK. 60000. The share of A in the contracted money will be-
Solution:
Ratio of number of days taken by A and B to complete the work = 18 : 12 = 3 : 2
∴ Ratio of efficiency of A and B = 2 : 3
Let their shares is in the ratio of 2x and 3x
Now,
2x + 3x = 60000
or, 5x = 60000
∴ x = 60000/5 = 12000
∴ share of A = 2x = 2 × 12000 = 24000 Taka
Question: 'A' can do a work in 10 days, and 'B' in 15 days. They work together for 4 days. How much of the work is left?
Solution:
মনে করি,
সম্পূর্ণ কাজ = 1 অংশ
∴ A একা একদিনে করে = 1/10 অংশ।
B একা একদিনে করে = 1/15 অংশ।
∴ A ও B একসাথে একদিনে করে = (1/10) + (1/15) অংশ
= (3 + 2)/30
= 5/30
= 1/6 অংশ
∴ A ও B একসাথে 4 দিনে করে = 4 × (1/6) অংশ
= 2/3 অংশ
∴ কাজ বাকি থাকে = 1 - (2/3) অংশ
= (3 - 2)/3
= 1/3 অংশ
Question: If 8 people make 48 chairs in 12 days by working 6 hours a day, then how long will it take 12 people working 8 hours a day to make 192 chairs?
Solution:
48 টি চেয়ার তৈরি করতে 8 জন লোক প্রতিদিন 6 ঘণ্টা কাজ করে = 12 দিনে
∴ 1 টি চেয়ার তৈরি করতে 1 জন লোক প্রতিদিন 1 ঘণ্টা কাজ করে = (8 × 6 × 12)/48 দিনে
∴ 192 টি চেয়ার তৈরি করতে 12 জন লোক প্রতিদিন 8 ঘণ্টা কাজ করে = (576 × 192)/(48 × 8 × 12)
= 24 দিনে
Question: If 8 workers can assemble a car in 9 hours, how long would it take 12 workers to assemble the same car?
Solution:
Here, M1 = 8, M2 = 12, W1 = W2 = 1, T1 = 9, T2 = ?
(M1 × T1)/(M2 × T2) = W1/W2
⇒ (8 × 9)/ (12 × T2) = 1
⇒ 12 × T2 = 72
⇒ T2 = 72/12
∴ T2 = 6
Question: A can complete a work in 20 days, B in 30 days, and C in 60 days. A stops working 4 days before the completion of the work, and B stops 6 days before completion. C continues working alone till the end. What was the total number of days taken to complete the entire work?
Solution:
Let the total work be completed in y days.
∴ A worked for (y - 4) days
So his contribution = (y - 4)/20
B worked for (y - 6) days
So his contribution = (y - 6)/30
C worked full y days, so his contribution = y/60
Therefore,
(y - 4)/20 + (y - 6)/30 + y/60 = 1
⇒ 3(y - 4) + 2(y - 6) + y = 60
⇒ 3y - 12 + 2y - 12 + y = 60
⇒ 6y - 24 = 60
⇒ 6y = 84
⇒ y = 14
∴ The total work was completed in 14 days.
Suppose,
A, B and C take x, x/2 and x/3 days respectively to finish the work.
Then,
(1/x) + (2/x) + (3/x) = 1/2
⇒ 6/x = 1/2
⇒ x = 12.
So, B takes 6 days to finish the work.