ব্যাখ্যা
Solution:
A এর 1 দিনের কাজ = 1/8
B এর 1 দিনের কাজ = 1/12
(A + B) একত্রে 1 দিনের কাজ = (1/8) + (1/12)
=(3 + 2)/24
= 5/24
(A + B) এর 1 দিনের কাজ অনুপাত = (1/8) : (1/12) = 3 : 2
A এর শেয়ার = {(3/5) × 800} = 480 টাকা
PrepBank · বিষয়ভিত্তিক প্রশ্ন
PrepBank · পাতা ১১ / ১১ · ১,০০১–১,০৬৬ / ১,০৭৬
P's 1 day 1 hrs work = 1/96 part.
Q's 1 day 1 hr's work = 1/80 part.
P & Q together work in 1 hr per day = 1/96 + 1/80 = 11/480 part.
P & Q together completes in 8 hr per day = 11×8/480 = 11/60 part.
So, days required = 60/11 = 5(5/11)
Question: If a half kg of tomato costs 80 taka, how many taka will 300 gm cost?
Solution:
Let the required cost be P TK
Less weight : Less cost (Direct proportion)
500 : 300 : : 80 : P
⇒ 500/300 = 80/P
⇒5/3 = 80/P
⇒ P = (3 × 80)/5
∴ P = 48
1 child's 1 day's work = 1/192;
1 adults 1 day's work = 1/96.
Work done in 3 days = (1/96) × 16 × 3
= 1/2
Remaining work = {1 - (1/2)}
= 1/2.
(6 adults + 4 Children)'s 1 day's work = (6/96) + (4/192)
= 1/12
1/12 work is done by them in 1 days
1/2 work is done by them in (12 × (1/2)}
= 6 days.
Combined work done by Mamun and Tonmoy in 4 + 6 days (4 initial days and last 6 days)= 10/24 + 10/40
= (50 + 30)/120
= 80/120
= 2/3
∴ Remaining work = 1 - 2/3 = 1/3
Robin works for = (1/3) × 30 = 10.
Question: A can complete a work in 24 days and B in 16 days. They work together for 6 days. How many more days will A take alone to finish the remaining work?
Solution:
A একা কাজটি করতে পারে = 24 দিনে
∴ A এর একদিনের কাজ = 1/24 অংশ
এবং,
B একা কাজটি করতে পারে = 16 দিনে
∴ B এর একদিনের কাজ = 1/16 অংশ
∴ A ও B একসাথে একদিনের কাজ = (1/24) + (1/16) = (2 + 3)/48 = 5/48 অংশ
তারা 6 দিনে একসাথে কাজ করে = 6 × (5/48) = 5/8 অংশ
বাকি কাজ = 1 - (5/8) = 3/8 অংশ
অতএব,
A, 1/24 অংশ কাজ করে 1 দিনে
∴ 3/8 অংশ কাজ করে = (24 × 3)/8 = 9 দিনে
অতএব, A একা বাকি কাজ শেষ করতে ৯ দিন লাগবে।
A can complete work in 9 days.
So, percentage of work A completed in one day = 100/9 = 11.11%.
B can complete work in 12 days.
B's one day work = 100/12 = 8.33%.
A and B together can complete = 11.11 +8.33 = 19.44% of work in one day.
Now,
Take 2 days = 1 unit of time (one day of A and one of B).
In one unit of time A and B can complete work = 19.44% work.
Total time unit they need to complete whole work = 100/(19.44) = 5.14 time unit
Thus, Total time = 5.14 time unit = 5.14 × 2 = 10.28 days.
Question: In a party, there is enough cake for 120 adults or 200 teenagers. If 150 teenagers have already eaten the cake, how many adults can be served with the remaining cake?
Solution:
মোট কেকের পরিমাণ = 200 জন কিশোর (Teenagers)
ইতিমধ্যে কেক খেয়েছে = 150 জন কিশোর
অবশিষ্ট কিশোরদের জন্য কেক আছে = 200 - 150 = 50 জনের
প্রশ্নমতে,
200 জন কিশোরের কেক = 120 জন প্রাপ্তবয়স্কের সমান
∴ 1 জন কিশোরের কেক = 120/200 জন প্রাপ্তবয়স্কের সমান
∴ 50 জন কিশোরের কেক = (120 × 50)/200 জন প্রাপ্তবয়স্কের সমান
= 30 জন
∴ অবশিষ্ট কেক দিয়ে আরও 30 জন প্রাপ্তবয়স্ককে পরিবেশন করা যাবে।
Work done by X in 8 days = 1/40×8 = 1/5
Remaining work = 1−1/5 = 4/5
Now, 4/5 work is done by Y in 16 days
Whole work will be done by Y in = 16×5/4 = 20 days
∴ X's 1 day's work = 1/40
∴ Y's 1 day's work = 1/20
(X + Y)'s 1 day's work
=1/40 + 1/20
=3/40
Hence, X and Y will together complete the work in
= 40/3
= 13(1/3) days
Question: A ferry can carry 30 trucks or 50 motorcycles at a time. If there are 18 trucks on the ferry, how many motorcycles can be loaded onto it?
Explanation:
Given,
30 trucks = 50 motorcycles
∴ 1 truck = 50/30 = 5/3 motorcycles
∴ 18 trucks = 18 × 5/3 = 30 motorcycles
Maximum motorcycles on ferry = 50
∴ Remaining motorcycles that can be loaded = 50 - 30 = 20
So, the ferry can carry 20 more motorcycles along with the 18 trucks.
Question: 25 men can complete a job in 36 days. After 12 days, 5 men left. How many days will the remaining men take to finish the job?
Solution:
25 men can complete a job in 36 days
∴ Total work = 25 × 36 = 900 man-days
∴ Work done in first 12 days = 25 × 12 = 300 man-days
And,
Remaining work = 900 - 300 = 600 man-days
Remaining days = 25 - 5 = 20 men
So,
Remaining days = 600/20 = 30 days
∴ The remaining men will take 30 days to finish the job.
Question: A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done is 23 days?
Solution:
Ratio of times taken by A and B = 100 : 130 = 10 : 13
Suppose B takes x days to do the work.
Then,
10 : 13 :: 23 : x
⇒ x = (23 × 13)/10
⇒ x = 299/10
A's 1 day's work = 1/23
B's 1 day's work = 10/299
(A + B)'s 1day's work = 1/23 + 10/299
= 23/299
= 1/13
∴ A and B together can complete the work in 13 days.
Question: 30 workers can manufacture 30 machines working 5 hours a day. How many workers need to be appointed extra to triple the production if they work 10 hours a day?
Solution:
5 hours to manufacture 30 machines by 30 workers
∴ 1 hour to manufacture 1 machine by = (30 × 5)/30 workers
∴ 10 hours to manufacture 90 machines by = (5 × 90)/10 workers
= 45 workers
∴ Extra workers required
= (45 - 30)
= 15 workers
Let 'B' alone can do the work in 'x' days
6/30 + 18/x = 1
=> x = 22.5
1/30 + 1/22.5 = 7/90
=> 90/7 = 12 (6/7) days
We know,
M1D1T1W2 = M2D2T2W1 [Men = M; Days = D; Time/Hours = T; Work = W]
Let the former type be E times efficient.
So, 1 former type pump = E x latter type pumps
So 1F = E x L
∴ 12F x 18 hours x 400 = 16L x 24 hours x 300
∴ (12 x E x L) x 18 x 400 = 16 L x 24 x 300 ------------------> Put value of F i.e. 1F
E = 4/3 = these are many times more efficient.
If A completes a work in 1 day, B completes the same work in 3 days.
This means, difference is 2 days, if B completes the work in 3 days
Therefore, difference is 60 days, if B completes the work in 90 days
⇒ Amount of work B can do in 1 day = 1/90
Amount of work A can do in 1 day = 3 × 1/90 = 1/30
Amount of work A and B can together do in 1 day = 1/90 + 1 /30 = 4/90 = 2/45
Therefore, A and B together can do the work in 45/2 days = 22 (1/2) days
Ratio of rates of working of P and Q = 2:1
So, ratio of times taken = 1 : 2
∴ P's 1 day's work = (1/6);
Q's 1 day's work = 1/12
(P + Q)'s 1 day's work = (1/6) + (1/12)
= 3/12
= 1/4
So, P and Q together can finish the work in 4 days.
Question: 5 pumps working 6 hours a day can empty a tank in 3 days. How many hours a day must 3 pumps work to empty the tank in 2 days?
Solution:
5 pumps এর প্রয়োজনীয় সময় 3 × 6 = 18 ঘণ্টা
1 pump এর প্রয়োজনীয় সময় = 18 × 5 = 90 ঘণ্টা
3 pumps এর প্রয়োজনীয় সময় = 90/3 = 30 ঘণ্টা
∴ 3টি পাম্পকে 2 দিনে কাজটি শেষ করতে প্রতিদিন কাজ করতে হবে,
= (30/2) = 15 ঘণ্টা।
Suppose,
A, B and C take x, x/2 and x/3 days respectively to finish the work.
Then,
(1/x) + (2/x) + (3/x) = 1/2
⇒ 6/x = 1/2
⇒ x = 12.
So, B takes 6 days to finish the work.
Question: A and B can finish a job together in x days. If A alone can complete the job in x + 3 days, and B alone can complete it in x + 12 days, what is the value of x?
Solution:
A's 1 day's work = 1/(x + 3) part
B's 1 day's work = 1/(x + 12) part
(A + B)'s 1 day's work = 1/x
ATQ,
1/(x + 3) + 1/(x + 12) = 1/x
⇒ (x + 12 + x + 3)/[(x + 3)(x + 12)] = 1/x
⇒ (2x + 15)/(x2 + 15x + 36) = 1/x
⇒ 2x2 + 15x = x2 + 15x + 36
⇒ x2 = 36
∴ x = 6
Question: If the cost of gas on burning 5 burners for 5 hours a day for 7 days is Tk. 525, then how many burners can be used for 10 days at 5 hours a day for Tk. 750?
Solution:
Given that,
5 burners 5 hours a day for 7 days is Tk. 525
Total burner-hours = (5 × 5 × 7) burner-hours
= 175 burner-hours
Cost per burner-hour =(525 ÷ 175)
= 3 Tk
∴ 750 Tk. total burner-hour = (750 ÷ 3) burner-hours
= 250 burner-hours
Let, the number of burners = x
ATQ,
x × 5 × 10 = 250
⇒ x × 50 = 250
⇒ x = 250 ÷ 50
∴ x = 5
24 men complete work in 10 days.
In 1 day work done by 24 men = 1/10
In 1 day work done by 30 men = ?
∴ ? × 24 = (1/10) × 30
∴ ? = 1/8 = Amount of work done by 30 men in one day.
Thus in this case,
30 men complete the entire work in 8 days.
[If A completes a work in ''n'' days, in 1 days he completes 1/n amount of work; Conversely, if A completes 1/n amount of work in 1 day, he completes the entire work in 'n' days.]
Question: A worker earns Tk. 300 on the first day and spends Tk. 150 on the second day, earns Tk. 300 on the third day and again spends Tk. 150 on the fourth day, and so on. On which day would he have had Tk. 1500?
Solution:
1ম দিনে আয় = 300 টাকা
2য় দিনে ব্যয় = 150 টাকা
∴ প্রতি 2 দিনে জমা হয় = 300 - 150 = 150 টাকা
শুধু 1ম দিনে আয় করায় হাতে থাকে = 300 টাকা
অতএব, 1500 - 300 = 1200 টাকা আরও জমা করতে হবে।
150 টাকা জমা হয় 2 দিনে,
∴ 1200 টাকা জমা হয় = (2 × 1200)/150 = 16 দিনে
অর্থাৎ, 16 দিনের শেষে জমা থাকবে = 1200 টাকা
17-তম দিনে আবার আয় হবে = 300 টাকা
∴ মোট সঞ্চয় হবে = 1200 + 300 = 1500 টাকা
∴ 17-তম দিনে তার কাছে মোট 1500 টাকা জমা থাকবে।
Let work is done by Rizvi in 1 day = 1/R & Shafi in 1/S day
Both complete work in 24 days. So in 1 day, together they complete = 1/24 = 1/R + 1/S
For 20 days both work together, so work done by them = 20(1/R + 1/S) = 5/6
Remaining work = {1 - (5/6)= 1/6} is done by Rizvi alone in 6 days
Work done by Rizvi in 6 days = 1/6 = 6(1/R)
∴ R = 36 = days needed by Rizvi to complete the work alone
According to the question,
∴ (1/36) + 1/S = 1/24
1/S = (1/24) - (1/36)
1/S = (3 - 2)/72
1/S = 1/72
S = 72 days needed by Shafi to complete the work alone.