ব্যাখ্যা
Solution:
Let, the price of pen = 100
20% less, price of 2 pencils = 100 - 20 = Tk. 80
20% less, price of 1 pencil = 80/2 = Tk. 40
∴ pen : pencil = 100 : 40
= 5 : 2
PrepBank · বিষয়ভিত্তিক প্রশ্ন
PrepBank · পাতা ৪ / ১১ · ৩০১–৪০০ / ১,০৮৬
Question: The ratio of the number of boys and girls in a school is 7 : 4. If the percentage increase in the number of boys and girls be 25% and 15% respectively, what will be the new ratio?
Solution:
Let,
The number of boys and girls in a school be 7X and 4X respectively
their increased number number is (125% of 7X) and (115% of 4X)
⇒ (125/100) of 7X and (115/100) of 4X
⇒ 35X/4 and 23X/5
∴ required ratio = 35X/4 : 23X/5
= 175X : 92X [multiply by 20]
= 175 : 92
Let,
the cost of the table and chair be Tk. 5x and Tk. 7x respectively.
New cost of chair = 120% of Tk. 7x = Tk (6/5 × 7x)
= Tk. 42x/5.
New cost of table = 110% of Tk. 5x = Tk.(11/10 × 5x)
= Tk. 55x/10.
∴ New ratio = 55x/10 : 42x/5
= 55 : 84
এছাড়াও,
5 : 7
নতুন অনুপাতঃ
5 এর 110% : 7 এর 120%
= 5.5 : 8.4
Common factor helps in finding actual values easily
So, take 'A' as a common factor.
∴ 3 numbers will now be 42A, 32A and 23A
∴ 42A + 32A + 23 A = 3395
∴ 97A = 3395
∴ A = 35
3 parts of 3395 are
42A = 42 x 35 = 1470;
⇒ 32A = 32 x 35 = 1120
⇒ 23A = 23 x 35 = 805
These are the amounts to be paid.
Question: Copper is 9 times as heavy as water, and tin is 3 times as heavy as water. In what ratio should these be mixed to get an alloy 6 times as heavy as water?
Solution:
Let copper be 9x times as heavy and tin 3y times as heavy as water.
9x + 3y = 6(x + y)
⇒ 9x + 3y = 6x + 6y
⇒ 9x − 6x = 6y − 3y
⇒ 3x = 3y
⇒ x/y = 1/1
∴ Copper and tin should be mixed in the ratio 1 : 1.
Question: The ratio of milk and water in a solution is 7 : 4. After adding 8 liters of water, the ratio of milk and water becomes 3 : 2. Find the final amount of water in the solution.
Solution:
Let the initial amount of milk = 7x liters
Let the initial amount of water = 4x liters
According to the question,
7x/(4x + 8) = 3/2
⇒ 2 × 7x = 3 × (4x + 8)
⇒ 14x = 12x + 24
⇒ 14x - 12x = 24
⇒ 2x = 24
⇒ x = 12
∴ Final amount of water = 4x + 8
= 4 × 12 + 8
= 48 + 8
= 56 liters
Let,
Initial milk = 4x
Initial water = 3x
ATQ,
(3x + 13)/4x = 1/1
Or, 4x = 3x + 13
Or, x = 13
So, water at final = (3 × 13) + 13
= 52 L
Let, the rice of two verities be in amount x and y
ATQ,
(8x + 12y)120/100 = 12(x + y)
⇒ 8x + 12y = (12×100)/120(x + y) = 10x + 10y
⇒ 2x = 2y
∴ x : y = 1 : 1
Let, A = 3x/4
and, B = x/4
So, C = (3x/4) / 4 = 3x/16
∴ C:B = 3x/16 : x/4 = 3:4
Question: If the ratio of syrup and water in a mixture is 7 : 3, then the percentage of water in mixture is-
Solution:
The ratio of syrup and water in a mixture is 7 : 3
Total = 10
∴ percentage of water = (3 × 100)/10 %
= 30%
Question: The first number is 25% greater than a third number, and the second number is 40% greater than the same third number. What is the ratio of the first number to the second number?
Solution:
Let the third number be x
Then,
First number = 125% of x
= 125x/100
= 5x/4
Second number = 140% of x
= 140x/100
= 7x/5
∴ Ratio of first two numbers
= 5x/4 : 7x/5
= 25x : 28x
= 25 : 28
Let the annual salary of A, B, C respectively be 3x, 4x and 5x.
Then 5x - 3x = 80000
x = 40000
So, B's annual salary = 4x = Tk. 160000
Hence, B's monthly salary
= Tk (160000)/12
= Tk. 13333.33
Question: The milk and water in a mixture are in the ratio 5 : 4. When 15 litres of water are added to it, the ratio of milk and water in the new mixture becomes 5 : 7. The total quantity of water in the new mixture is:
Solution:
Let the initial quantity of milk = 5x litres
and initial quantity of water = 4x litres
According to the question,15 litres of water is added.
New amount of water = (4x + 15)
The amount of milk remains the same = 5x
As per the new ratio,
5x/(4x + 15) = 5/7
⇒ 7(5x) = 5(4x + 15)
⇒ 35x = 20x + 75
⇒ 35x − 20x = 75
⇒ 15x = 75
⇒ x = 5
The total quantity of water in the new mixture,
= (4x + 15)
= (4 × 5) + 15
= 20 + 15
= 35 litres
∴ Total quantity of water in new mixture 35 litres.
The percentage of boys = {4/(4+5)}×100 = (4/9)×100 = 400/9%
and The percentage = {5/(4 + 5)}×100 = (5/9)×100 = 500/9% .
So, The percentage of students passed in the exam = (400/9 - 10)% + (500/9 - 20)% = 310/9 + 320/9 = 630/9 = 70%.
Ratio of W : R : G = 2 : 3 : 5
If 6 Green marbel is added, Ratio becomes W : R : G = 2 : 3 : 7
Difference of ratio for 6 marbles = 7 – 5 = 2
So, 1 ratio = 3 marbles
∴ White marbles = 2×3 = 6
Let the present age of Jolly and lopa be 13X and 11X respectively.
Given, Jlly's age 4 years hence and lopa's age 4 years ago in the ratio 15:9.
That is,
(13X + 4)/(11X - 4) = 15/9
⇒ 9(13X + 4) = 15(11X - 4)
⇒ 117X + 36 = 165X - 60
⇒ 48X = 96
⇒ X = 2.
Now, required ratio is (13X-4)/(11X + 4)
= 13(2) - 4/11(2) + 4
= 22/26
= 11/13.
Hence the answer is 11:13.
Let PQ = Qr = x km
Let speed downstream = a km/hr.
and speed upstream = b km/hr.
Then,
x/a + x/b = 10
x = 10ab/(a + b) .........(i)
And,
2x/a = 4
x = 4a/2
x = 2a .............(ii)
From (i) and (ii) we have:
2a = 10ab/(a + b)
5b = a + b
a = 4b
Required ratio = Speed in the water/Speed of river
= {1/2(a + b)}/{(1/2) (a - b)}
= (a + b)/(a - b)
= (4b + b)/(4b - b)
= 5b/3b
= 5/3
Given mixture = 48 lit
Milk in it = 48 x 5/8 = 30 lit
=> Water in it = 48 - 30 = 18 lit
Let 'L' lit of water is added to make the ratio as 3:5
=> 30/(18+L) = 3/5
=> 150 = 54 + 3L
=> L = 32 lit.
Apply Allegation Method and first calculate the ratio in which they have to be mixed.
= 8 : 12 = 2 : 3
Thus, the two varieties of oil should be mixed in the ratio 2 : 3. So, if 240 liters of the second variety are taken, then 160 liters of the first variety should be taken.
Cyclist:Jogger
Ratio of distance→ 2:1
Ratio of time→ 1:2
Ratio of their speed (Jogger:Cyclist)
= (1/2):(2/1)
= 1:4
Question: A bag contains red, blue, and green balls in the ratio 2 : 3 : 5. If there are 15 blue balls, how many total balls are there in the bag?
Solution: Given ratio = Red : Blue : Green = 2 : 3 : 5
Let the numbers be:
Red = 2x, Blue = 3x, Green = 5x
Given,
Blue balls, 3x = 15
∴ x = 5
Now calculate total balls:
= 2x + 3x + 5x
= (2 + 3 + 5)x
= 10x
= 10 × 5
= 50
In 3 L solution sugar is 60%
So, Sugar Amount = 3 × 3/5 = 1.8 L
Now, 1 L water is added.
So, Total solution = (3 + 1)
= 4 L
% sugar = (1.8 × 100)/4
= 180/4
= 45% [Answer.]
Let B's capital be tk. x.
Then, (3500 x 12)/7x = 2/3
or, 14x = 126000
so, x = 9000 tk
Quantity of alcohol in vessel P = 62.5/100 × 2 = 5/4 litres
Quantity of alcohol in vessel Q = 87.5/100 × 4 = 7/2 litres
Quantity of alcohol in the mixture formed = 5/4 + 7/2 = 19/4 = 4.75 litres
As 6 litres of mixture is formed, ratio of alcohol and water in the mixture formed
= 4.75 : 1.25 = 19 : 5.
Given, y : z = 1.5
∴ y = 1.5 × 2 = 3
And, x : y = 1.5
∴ x = 1.5 × 3 = 4.5
Question: For a circle where the diameter is 4π, calculate the radius-to-circumference ratio.
Solution:
Here
The diameter of the circle is d = 4π
So the radius of the circle r = 2π
∴ Circumference of circle = 2. π. 2π
= 4π2
So the ratio between radius and Circumference of circle = 2π : 4π2
= 2π/4π2
= 1 : 2π
Let Mira paid x,
so, Akhi paid 2x/3, and
Lamia paid 2x,
So total bill paid is given by,
x + (2x/3) + 2x = 1;
we get,
x = 3/11
So, Mira paid 3/11 fraction of the total bill.
Question: What is the ratio of 5 inches to 9 feet?
Solution:
We know, 1 foot = 12 inches
So, 9 feet = 9 × 12 = 108 inches
Now,
5 inches : 9 feet = 5 : 108
∴ The ratio = 5 : 108
Angle traced by hour hand in 13/ 3 hrs
=( 360/12 × 13/3)∘ =130∘
Angle traced by min. hand in 20 min
=( 360/60 ×20)∘=120∘
∴Required angle
=(130−120)∘ =10∘
Question: The ratio of X : Y is 2 : 5, and the ratio of Y : Z is 3 : 4. If X = 12, what is the value of Z?
Solution:
Given:
X : Y = 2 : 5 -------(1)
Y : Z = 3 : 4 -------(2)
X = 12
From equation (1):
X/Y = 2/5
⇒ 2Y = 5X
⇒ Y = (5 × 12)/2 = 30
∴ Y = 30
From equation (2):
Y/Z = 3/4
⇒ 3Z = 4Y
⇒ Z = (4 × 30)/3 = 40
Therefore, the value of Z is 40.
Income = Expenditure + Saving
Asim : 12x = 15y + 3x (3x = 25% of 12x)
Shakil : 9x = 9y + (9x – 9y)
Riaz : 7x = 8y + (7x – 8y)
Therefore, 12x – 3x = 15y
x/y = 5/3
y = 3x/5
Therefore, savings = (income – expenditure)
Asim = 12x – 9x = 3x
Shakil = 9x - 9y = 9x - (27x/5)
= 18x/5
Riaz = 7x - 8y = 7x - (24x/5)
= 11x/5
i.e., the ratio of savings of Asim : Shakil : Riaz
= 3x : 18x/5 : 11x/5
= 15 : 18 : 11.
3 vessels of 30 litres each = 3 X 30 = 90 ml milk mixture
Amount of milk in mixture = 2/(2 + 1) × 90 = 60L
Amount of water = 90 - 60 = 30L
To make milk to water ratio 1 : 2, we simply need to make water double of milk.
By direct observation,
we can say that we should have 60L x 2 = 120L water to make the required ratio
We already have 30L,
we need (120 - 30) = 90L more water.
A : B : C
= 1000 : (1000 - 50) : (1000 - 69)
= 1000 : 950 : 931
In a 950 m race, B can give C a start of
(950 - 931) m
= 19 m
In a 1000 m race, B can give C a start of
(19/950) × 1000 = 20 m
Let C.P of 1 litre milk be Tk. 1.
Then, S.P of 1 litre of mixture = Tk. 1, Gain = 25%
C.P. of 1 litre mixture = Tk. (100/125) × 1
= Tk. 4/5
By the rule of alligation, we have:
∴ Ratio of the milk to water = 4/5 : 1/5
= 4 : 1.
Hence, percentage of water in the mixture
= {(1/5) × 100}%
= 20%
Let, A's profit = 42,360 = 5x
So, x = 42,360/5 = 8472
total profit = 5x + 7x + 8x = 20x = 20×8472
∴ The total profit is tk. 1,69,440
Question: A person who has a rice storage has two types of rice costing Tk. 50 per kg and Tk. 70 per kg. In what ratio should he mix them to make a mixture worth Tk. 58 per kg?
Solution:
Cheaper variety price, a = Taka 50 per kg
Expensive variety price, b = Taka 70 per kg
Mixture price, c = Taka 58 per kg
Ratio = (b - c)/(c - a)
= (70 - 58)/(58 - 50)
= 12/8
= 3 : 2
Question: In a mixture of milk and water, the ratio is 7 : 5. If 6 liters of water is added, the new ratio becomes 7 : 6. What was the original amount of milk in the mixture?
Solution:
ধরি, শুরুতে দুধ ছিল = 7x লিটার,
পানি ছিল = 5x লিটার।
এখন 6 লিটার পানি যোগ করলে,
নতুন পানি = 5x + 6 লিটার
ATQ,
7x/(5x + 6) = 7/6
⇒ 6 × 7x = 7 × (5x + 6)
⇒ 42x = 35x + 42
⇒ 7x = 42
⇒ x = 6
∴ দুধের পরিমাণ = 7x = 7 × 6 = 42 লিটার
Question: In a 60 liters mixture of milk and water, the ratio of milk to water is 7 : 3. To get a new mixture containing milk and water in the ratio 3 : 2, the amount of water to be added is-
Solution:
Quantity of milk in 60 liters mixture is = 60 × (7/10) = 42 liters
so, water is = 60 - 42 = 18 liters
Let, p liters of water to be added to become the ratio 3 : 2
so,
42 : (18 + p) = 3 : 2
or, 42/(18 + p) = 3/2
or, 3p + 54 = 84
or, 3p = 84 - 54
or, 3p = 30
or, p = 30/3
∴ p = 10
hence, 10 liters water to be added to become the ratio 3 : 2