ব্যাখ্যা
Suppose B joined after x months
then,
21000 × 12 = 36000 × (12 - x)
⇒ 36x = 180
⇒ x = 5
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Suppose B joined after x months
then,
21000 × 12 = 36000 × (12 - x)
⇒ 36x = 180
⇒ x = 5
Since profit of 10% is there,
∴ S.P. = (100+10)% of C.P. = (110/100) × 900
= Tk. 990
Discount = 12%
So,
SP = (100-12)% of List Price
∴ 990 = (88/100) × L.P.
∴ L.P. = Tk. 1125 [List price = Advertised Price = Marked Price]
Question: Every 2 minutes, 5 litres of water are poured into a 1,500 litre tank. After 3 hours, what percent of the tank will be full?
Solution:
In 2 minutes, 5 liters is poured
In 180 minutes = (180 × 5)/2 = 450 liters
So, percentage filled = (450 × 100)/1500
= 30%
B's income is less than A's by
[10/(100 + 10) × 100]%
= (100/11)%
= 9(1/11)%
Question: By selling a book for Tk. 675, a seller loses 2/9 of his outlay, by selling it for Tk. 810, his gain or loss percentage is -
Solution:
Let the cost price of the book be Tk. x
The loss of outlay is Tk. 2x/9
Given that,
Selling price of the book is Tk. 675
or, x - 2x/9 = 675
or, 7x/9 = 675
or, x = 675 × 9/7
or, x = 867.86
If the book is sold for Tk. 810
The loss = Tk. (867.86 - 810) = Tk. 57.86
Therefore loss percentage is
= (57.86/867.86) × 100 %
= 6.666 %
= 6.67%
Question: After a 10% reduction in the price of cooking oil, a family is able to purchase 4 liters more oil for Tk. 720. What was the original price per liter?
Solution:
Let
Original price of cooking oil = x Tk/liter.
Original quantity = 720/x litre
New price = 0.90x Tk/litre
New quantity = 720/0.90x = 720/(9x/10) = (720 × 10)/9x = 800/x liters
ATQ,
(800/x) - (720/x) = 4
⇒ (800 - 720)/x = 4
⇒ 80/x = 4
⇒ x = 80/4
∴ x = 20
∴ Original price of cooking oil = 20 Tk/liter.
ধরি কর্মীর বেতন ছিল 100 টাকা
10% হ্রাসে তার বর্তমান বেতন হবে = (100 - 100 এর 10%) = [100 − {(100×10)/100}] =100 − 10 = 90 টাকা
আবার, 10% বৃদ্ধিতে তার বর্তমান বেতন হবে = (90 + 90 এর 10%) = [90 − {(90×10)/90}] = 90 + 9 = 99 টাকা
∴ তার মোটের উপর ক্ষতি হলো = 100 - 99 = 1 টাকা বা 1%
Question: A machine is sold at a profit of 10%. Had it been sold for Tk. 40 less, there would have been a loss of 10%. What was the cost price?
Solution:
Let, cost price of the machine is x taka
Selling price = 1.1x taka
ATQ,
1.1x - 40 = 0.9x
⇒ 1.1x - 0.9x = 40
⇒ 0.2x = 40
⇒ x = 40/.2
= Tk. 200
Question: A person make a profit of 10% on 25% of the quantity and a loss of 20% on the rest of the quantity. What is the gain or loss in percentage on the whole?
Solution:
Let Cost Price = 100
Profit = 25 x 10%
= 25/10
= 2.5
Loss = 75 x 20%
= 75/5
= 15
Net loss = 15 - 2.5
= 12.5
∴ Net Loss as % = 12.5/100 x 100%
= 12.5%
Question: 120% of 45 + 45% of 120 = ?
Solution:
120% of 45 + 45% of 120
= {(120/100) × 45} + {(45/100) × 120}
= 54 + 54
= 108
Question: The population of a city grows from 175,000 to 262,500. What is the percentage growth in the city's population?
Solution:
জনসংখ্যা বৃদ্ধি পেয়েছে
= (262500 - 175000) = 87500
175000 জনে বৃদ্ধি পায় = 87500 জন
∴ 1 জনে বৃদ্ধি পায় = 87500/175000 জন
∴ 100 জনে বৃদ্ধি পায় = (87500 × 100)/175000 = 50 জন
∴ জনসংখ্যা বৃদ্ধির শতকরা হার = 50%
Let C.P.=Tk. 100
Then,
M.P. = Tk. 135,
S.P. =Tk.108
∴Discount % =(27/135 ×100)% =20%
Question: The school has a total of 800 students. Yesterday, 12% of the boys and 18% of the girls were absent, and today 10% of the boys and 15% of the girls are absent. If today, 20 more students are present than yesterday, then find the total number of boys in the school.
Solution:
Let the Boys = B and the Girls = G
Then B + G = 800 ....... (1)
ATQ,
If absent 10% of boys and 15% of girls
So, present = 90% of boys and 85% of girls
⇒ 90% B + 85% G ........ (2)
If absent = 12% of boys and 18% of girls
So, present = 88% of boys and 82% of girls
⇒ 88% B + 82% G ......... (3)
Subtract equation (3) from (2)
90% B + 85% G - (88% B + 82% G) = 20
⇒ 2% B + 3% G = 20
⇒ 2B + 3G = 2000
⇒ 2B + 3(800 - B) = 2000 [From equation 1]
⇒ 2B - 3B = 2000 - 2400
∴ B = 400
Let the number be x
The problem could be 40 is subtracted from 60% of a number, the result is 50.
60% of x = 60/100×x= 60x/100
60x/100 - 40 = 50
(60x - 4000) /100 = 50
Cross multiplication
60x - 4000 = 50 ×100
60x -4000 = 5000
60x = 5000 + 4000
60x = 9000
x = 9000/60
x = 150
Hence, the number is 150
Cost of each share = (20 + 2.5% of 20) = tk.20.5
Therefore, number of shares = 8200/20.5 = 400
Let total quantity of original milk = 1000 gm
Milk after first operation = 80% of 1000 = 800 gm
Milk after second operation = 80% of 800 = 640 gm
Milk after third operation = 80% of 640 = 512 gm
∴ Strength of final mixture = 51.2%
Question: Fedora Technologies acquired 60 hard-drives and tried selling them at BDT 2400 apiece at 20 percent markup on cost price. After 3 months, 6 remained unsold and were returned to manufacturer at 50 percent refund of cost. Find out Fedora's approximate profit margin as a percentage of initial acquisition cost of the 60 hard-drives.
Solution:
ধরি,
প্রতি ইউনিটের ক্রয়মূল্য = x
Markup ২০%, অর্থাৎ,
বিক্রয়মূল্য = 1.2x = 2400
⇒ x = 2400/1.2
= (2400 × 10)/12
= 2000 টাকা
অতএব,
প্রতি হার্ডড্রাইভের ক্রয়মূল্য = ২০০০ টাকা
∴ মোট ক্রয়মূল্য = 60 × 2000 = 120000 টাকা
আবার,
বিক্রিত হার্ডড্রাইভ = 60 - 6 = 54
প্রতি হার্ডড্রাইভ বিক্রয়মূল্য = 2400 টাকা
∴ মোট বিক্রয়মূল্য =54 × 2400 = 129600
অবিক্রিত 6টি ফেরত দিয়ে,
রিফান্ড = 6 × (50% × 2000)
= 6 × 1000
= 6000 টাকা
∴ মোট আয় = (বিক্রয় + রিফান্ড)
= 129600 + 6000
= 135600 টাকা
∴ লাভ = 135600 - 120000 = 15600 টাকা
∴ লাভের হার = (15600/120000) × 100 = 13%
At 5% profit, selling price = 100+5 = 105 tk
At 5% loss, selling price = 100-5 = 95 tk
Difference between selling price = 105-95 = 10 tk
When the difference 10, buying price is 100 tk
∴ When the difference is 15, buying price is (100×15)/10 tk = 150 tk
Question: An error 4% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:
Solution:
100 cm is read as 104 cm.
∴ A1 = (100 x 100) sq. cm and A2 (104 x 104) sq. cm
Now,
(A2 - A1) = [(104)2 - (100)2]
= (104 + 100) x (104 - 100)
= 816 sq. cm
Percentage error in area = [(A2 - A1)/A1] × 100
= [816/(100 x 100)] × 100%
= 8.16%
Question: A shopkeeper sells 15 notebooks for Tk. 720 and incurs a loss equal to the cost price of 5 notebooks. What is the cost price of one notebook?
Solution:
Let,
Cost price of 1 notebook = Tk. x
∴ Cost price of 15 notebooks = Tk. 15x
∴ Cost price of 5 notebooks = Tk. 5x
We know,
Loss = Cost price − Selling price
According to the question,
5x = 15x − 720
⇒ 15x − 5x = 720
⇒ 10x = 720
⇒ x = 720/10
⇒ x = 72
∴ The cost price of 1 notebook is Tk. 72
Since he make 8% profit so his purchase = 100 + 8 = 108
He make 8% more profit during sales so his sales = (108/100) × 108 = 116.64
so profit = 116.64 - 100
= 16.64
Short Cut (with increase decrease short cut)
X + Y + (xy/100)
= 8 + 8 + (8×8/100) ( since he his making profit so count is as a increase)
= 16.64
Question: A shopkeeper incurs a loss by selling an article for Tk 550. If he had sold it for Tk 850, he would have made a profit which is four times the initial loss. At what price should he sell the article to make 10% profit?
Solution:
ধরি, পণ্যের ক্রয়মূল্য = x টাকা
550 টাকায় বিক্রি করলে ক্ষতি = x - 550 টাকা
850 টাকায় বিক্রি করলে লাভ = 850 - x টাকা
প্রশ্নমতে,
850 - x = 4(x - 550)
⇒ 850 - x = 4x - 2200
⇒ 850 + 2200 = 4x + x
⇒ 3050 = 5x
∴ x = 610 টাকা
এখন,
10% লাভে,
ক্রয়মূল্য 100 টাকা হলে বিক্রয়মূল্য 110 টাকা
ক্রয়মূল্য 1 টাকা হলে বিক্রয়মূল্য (110/100) টাকা
∴ ক্রয়মূল্য 610 টাকা হলে বিক্রয়মূল্য (110 × 610)/100 টাকা
= 671 টাকা
25% of 25%
= 0.25 × 0.25
= 0.0625
Let C.P. = Tk. 100.
Marked Price = 20% more than C.P.
∴ M.P. = Tk. 120
Discount = 30% on marked price
∴ S.P. = (100-30)% of M.P.
∴ S.P. = (70/100) × 120 = Tk. 84
Loss% = (100 - 84)/100 × 100
= 16%
Question: A shopkeeper marks up his goods by 50% above the cost price. He then offers a discount of 20% on the marked price. What is the overall percentage profit?
Solution:
Let the cost price (CP) be Tk. 100
Marked Price = 50% more than cost price
= 100 + 50
= Tk. 150
Discount = 20% of 150
= (20/100) × 150
= Tk. 30
Selling Price (SP) = 150 - 30 = Tk. 120
∴ Profit = SP - CP = 120 - 100 = Tk. 20
∴ Overall percentage profit = (profit/cost price) × 100%
= (20/100) × 100%
= 20%
Let's, 4A = 6B = 10C = x
Now, A = x/4; B = x/6; C = x/10
So, A : B : C = x/4 : x/6 : x/10
= x/4 × 60 : x/6 × 60 : x/10 × 60
= 15 : 10 : 6
∴ Profit of C = 4650 × 6/(15+10+6) = 900Tk.
Question: What percentage of numbers from 1 to 50 has 2 or 9 in the unit digits?
Solution:
Numbers from 1 to 50 has 2 or 9 in the unit digits
= 2, 9, 12, 19, 22, 29, 32, 39, 42, 49
= 10 Numbers
∴ Amount in percentage
= 10/50 × 100%
= 20%
Question: The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer:
Let,
The cost price of each article is Taka 1
∴ Cost Price of x articles = x Taka
Selling Price of x articles = 20 Taka
∴ Profit = (20 - x) Taka
x টাকায় লাভ হয় 20 - x টাকা
∴ 1 টাকায় লাভ হয় (20 - x)/ x টাকা
∴ 100 টাকায় লাভ হয় = [(20 - x) × 100]/x টাকা
প্রশ্নমতে,
[(20 - x) × 100]/x = 25
⇒ 100(20-x) = 25x
⇒ 125x = 2000
∴ x = 2000/125
= 16
আরেকভাবে,
মনে করি, প্রতিটি আর্টিকেলের ক্রয়মূল্য (cost price) = ১০০ টাকা।
তাহলে ২০টি আর্টিকেলের ক্রয়মূল্য = ২০ × ১০০ = ২০০০ টাকা।
প্রশ্ন অনুসারে, এই ২০০০ টাকা x টি আর্টিকেলের বিক্রয়মূল্য (selling price) এর সমান।
লাভ ২৫% হলে,
ক্রয়মূল্য (cost price) = ১০০ টাকা। হলে,
অর্থাৎ, প্রতি আর্টিকেলের বিক্রয়মূল্য (SP) = ১২৫ টাকা।
তাহলে x টি আর্টিকেলের SP = x × ১২৫
ATQ,
x × ১২৫ = ২০০০
⇒ x = ২০০০/১২৫
∴ x = ১৬ টাকা
Let his initial income is 100 taka
He spends = 75 taka
So, his savings is = 100 - 75 = 25 taka
Income increases by 20%
So new income is 120 taka
At 10% increase, the expense is = 75 + 10% of 75 = 83.5
So, now the savings is = 120 - 83.5 = 37.5
His savings increases = 37.5 - 25 = 12.5 taka
In percent = (12.5×100) / 25 = 50%
(C1 × Q1 + C2 × Q2)/(Q1 + Q2) = P
or, (8 × 124 + 4 × Q2)/(24 + Q2) = 5
or, 192 + 4 × Q2 = 120 + 5 × Q2
or, Q2 = 72
Question: A buys a product for Tk. 500 and sells it to B at a profit of 25%. B then sells it to C at a profit of 20%. How much does C pay to B?
সমাধান:
A এর 25% লাভে বিক্রয়মূল্য = 500 + 500 এর 25%
= 500 + (500 × 25 / 100)
= 500 + 125
= 625
A এর বিক্রয়মূল্য = B এর ক্রয়মূল্য
B এর 20% লাভে বিক্রয়মূল্য = 625 + 625 এর 20%
= 625 + (625 × 20 / 100)
= 625 + 125
= 750
সুতরাং, B এর বিক্রয়মূল্য = C এর ক্রয়মূল্য = Tk. 750
A = 150% of B
⇒ A = 150/100 B
⇒ A/B = 3/2
⇒ A/B + 1 = 3/2 + 1
⇒ (A + B)/B = 5/2
⇒ B/(A + B) = 2/5
∴ Required percentage:
= {B / (A + B)} × 100 %
= (2/5 × 100) %
= 40%
Question: The ratio of the number of boys and girls in a college is 7 ∶ 8. If the percentage increase in the number of boys and girls be 20% and 10% respectively, what will be the new ratio?
Solution:
ধরি,
কলেজে ছেলে এবং মেয়ের সংখ্যা যথাক্রমে 7x এবং 8x
∴ ছেলেদের বর্ধিত সংখ্যা = 120% × 7x
= (120/100) × 7x
= (6/5) × 7x
= (42x)/5
এবং, মেয়েদের বর্ধিত সংখ্যা = 110% × 8x
= (110/100) × 8x
= (11/5) × 4x
= (44x)/5
∴ বর্ধিত সংখ্যার অনুপাত (New ratio) = (42x)/5 ∶ (44x)/5
= 21 ∶ 22