ব্যাখ্যা
Solution:
C.P of 1 Pineapple = Tk. 200/score = 200/20 = 10 (Note: 1 score = 20)
∴ Profit of 1 Pineapple = 13 - 10 = 3
PrepBank · বিষয়ভিত্তিক প্রশ্ন
PrepBank · পাতা ৫ / ১৭ · ৪০১–৫০০ / ১,৬৯৬
Say both egg and apple cost $10 each per unit
An increase of 10% for the eggs would bring the new total to $11
And an increase of 2% for the apples would bring the new total to $10.2
The original total was $20 and the new total is $21.2.
Change in price = 21.2 - 20 = 1.2
∴ Percentage increased in price = 1.2/20 × 100 = 6%.
Here,
(r × 100)/(100 + r)
= (20 × 100)/(100 + 20)
= 16.67
Question: A shopkeeper marks an article 40% above the cost price and allows a discount of 10%. What is his profit percentage?
Answer:
Cost Price 100 Taka
Then Mark Price = 140, (40% above the cost price)
10% discount
If marked price is 100, then discount is 10 taka
If marked price is 1, then discount is 10/100 taka
If marked price is 140, then discount is 140/10 = 14 taka
Selling Price = 140 - 14 = 126,
As the Cost Price = 100
Then, the Profit percentage is = 26%
মোট খরচ = (80 × 40 + 40 × 50) টাকা
= (3200 + 2000) = 5200 টাকা
10% লাভে বিক্রয়মূল্য (5200 + 5200×10/100) = 5720 টাকা
∴ প্রতি কেজির বিক্রয়মূল্য (5720 ÷ 120) টাকা = 47.7 টাকা
Question: In an examination, 32% is the pass mark. If an examinee gets 14 marks and fails by 10 marks, what is the maximum mark?
Solution:
If the candidate fails by 10 marks, it means the pass marks = 14 + 10
= 24
Let the maximum marks be x
ATQ,
32% of x = 24
⇒ x × (32/100) = 24
⇒ 32x = 2400
⇒ x = 2400/32
⇒ x = 75
Question: X buys a product for Tk. 400 and sells it to Y at a profit of 30%. Y then sells it to Z at a profit of 15%. How much does Z pay to Y?
সমাধান:
X এর 30% লাভে বিক্রয়মূল্য = 400 + 400 এর 30%
= 400 + (400 × 30/100)
= 400 + 120
= 520
X এর বিক্রয়মূল্য = Y এর ক্রয়মূল্য
Y এর 15% লাভে বিক্রয়মূল্য = 520 + 520 এর 15%
= 520 + (520 × 15/100)
= 520 + 78
= 598
সুতরাং, Y এর বিক্রয়মূল্য = Z এর ক্রয়মূল্য = Tk. 598
Question: If 75% of the students in a school are boys and the number of girls is 520, the number of boys is:
Solution:
No. of boys = 75%
No. Girls = 25% = 520
Now
25% = 520
1% = 520/25
75% = (520 × 75)/25
= 1560
According to the question,
10% of 20 = 2 mangoes were damaged
∴ বিক্রি করলো 20 - 2
=18
= 1(1/2) dozen.
বিক্রয় মূল্য = 54 × 1(1/2)
= 81
∴ Profit = 81 - 55
= 26.
Team won 40 games out of 60 and the remaining games were 32.
Total games = 60 + 32
= 92
75% of 92 = 69
Team has to win 69 games in total.
Team has already won 40.
∴ Games to win = 69 - 40
= 29
Question: In an examination A got 25% marks more than B, B got 10% less than C and C got 25% more than D. If D got 320 marks out of 500, the marks obtained by A were :
Solution:
Marks obtained by D = 320
Marks obtained by C = 320 × (125/100)
= 400
Marks obtained by B
= 400 × (100 - 10)/100
= 360
Marks obtained by A
= 360 × (125/100)
= 450
∴ Hence, required marks obtained by A = 450
Question: A and B are two fixed points 10 cm apart and C is a point on AB such that AC is 6cm. if the length of AC is increased by 10%, by what percentage is CB decreased?
Solution:
দেওয়া আছে
AB = 10 cm
AC = 6 cm
CB = (10 - 6) = 4
AC 10% বৃদ্ধিতে = 6 + 6 এর 10%
= 6 + 6 এর 10/100
= 6 + .6
= 6.6
CB এর নতুন দৈর্ঘ্য = 4 - . 6
= 3.4
CB এর দৈর্ঘ্য হ্রাস পায় = 4 - 3.4
= .6
শতকরা হ্রাস পায় = (.6/4) × 100%
= 15%
Question: P scored 30% marks and failed by 15 marks. Q scored 45% marks and obtained 30 marks more than the pass marks. What is the pass percentage?
Solution:
Let the total marks be x.
Given,
P scored 30% marks and failed by 15 marks:
0.30x + 15 = Pass marks
Q scored 45% marks and obtained 30 marks more than the pass marks:
0.45x - 30 = Pass marks
Now,
0.30x + 15 = 0.45x - 30
⇒ 0.45x - 0.30x = 15 + 30
⇒ 0.15x = 45
⇒ x = 45/0.15
∴ x = 300
Pass marks = 0.30 × 300 + 15
= 90 + 15 = 105
∴ Pass percentage = (105/300) × 100% = 35%
Question: The price of a mobile set is Tk 8,000 and that of a tab is 50% more than the price of a mobile set. If a total of 18 mobiles and tabs were sold for a total of Tk 188,000, how many tabs were sold?
Solution:
Given that,
Price of mobile = Tk. 8,000
Price of tab = 50% more than mobile
= 8,000 + (50/100) × 8,000
= 8,000 + 4000 = Tk. 12,000
Total items sold = 18 (mobiles + tabs)
Total sales = Tk 188,000
Now, Let, Number of mobiles = m,Number of tabs = t
Then we get,
m + t = 18
∴ m = 18 - t .......(1)
And,
8000m + 12000t = 188,000
⇒ 2m + 3t = 47 ; [Dividing by 4,000]
⇒ 2(18 - t) + 3t = 47 ; [From (1)]
⇒ 36 - 2t + 3t = 47
⇒ t = 47 - 36
∴ t = 11
∴ The number of tabs sold is 11.
Question: A man buys an article for 20% more than its value and sells it for 20% less than its value. His gain or loss percentage is –
Solution:
Let the original value of the article = 100 টাকা
∴ Cost Price (CP) = 100 + 20% of 100 টাকা
= 100 + 20 = 120 টাকা
∴ Selling Price (SP) = 100 - 20% of 100 টাকা
= 100 - 20 = 80 টাকা
Since SP (80 টাকা) is less than CP (120 টাকা), there is a Loss.
∴ Loss = CP - SP = 120 - 80 = 40 টাকা
∴ Loss percentage = (Loss/CP) × 100%
= (40/120) × 100%
= (1/3) × 100%
= 33.33% loss
Question: A wholesaler buys a television for Tk. 18,000 and sells it to a retailer at a profit of 30%. The retailer then sells it to a customer at a profit of 25%. How much does the customer pay to the retailer?
সমাধান:
পাইকারের 30% লাভে বিক্রয়মূল্য = 18,000 + 18,000 এর 30%
= 18,000 + (18,000 × 30/100)
= 18,000 + 5,400 = 23,400 টাকা
পাইকারের বিক্রয়মূল্য = খুচরা বিক্রেতার ক্রয়মূল্য = 23,400 টাকা
খুচরা বিক্রেতার 25% লাভে বিক্রয়মূল্য = 23,400 + 23,400 এর 25%
= 23,400 + (23,400 × 25/100)
= 23,400 + 5,850 = 29,250 টাকা
সুতরাং, খুচরা বিক্রেতার বিক্রয়মূল্য = ক্রেতার ক্রয়মূল্য = Tk. 29,250
Let the number of the remaining games be x
then,
0.8×100 + 0.5×x = 0.7×(100+x)
⇒ 80 - 70 = 0.7x - 0.5x = 0.2x
⇒ x = 50
∴ total number of games thus equal to = 100+x
= 100+50
= 150
Question: Rafiq bought 120 storybooks at Tk. 250 each and sold them at a profit of 15%. Find the total profit he made.
Solution:
Cost Price of 120 storybooks = 120 × Taka 250
= Taka 3,0000
Profit Percentage = 15%
∴ Profit Amount = Profit Percentage × Cost Price
= 15% × Taka 3,0000
= Taka 4500
∴ Total Profit = Profit Amount = 4500
দৈর্ঘ্য ও প্রস্থ দ্বিগুণ হলে ক্ষেত্রফল হবে = ২ক × ২খ বর্গএকক
= ৪কখ বর্গএকক
ক্ষেত্রফল বৃদ্ধি পায় = (৪কখ - কখ) বর্গএকক
= ৩কখ
কখ বর্গএকক এ বৃদ্ধি পায় ৩কখ বর্গএকক
∴ ১ বর্গএকক এ বৃদ্ধি পায় (৩কখ)/(কখ) = ৩ বর্গএকক
∴ ১০০ বর্গএকক এ বৃদ্ধি পায় ৩ × ১০০ বর্গএকক
= ৩০০ বর্গএকক
∴ আয়তক্ষেত্রের ক্ষেত্রফল ৩০০% বৃদ্ধি পাবে।
Question: A merchant marks up his goods by 25% above the cost price. He then offers a discount of 10% on the marked price. What is the overall percentage profit?
Solution:
Let,
The cost price (CP) be Tk. 100
Marked Price = 25% more than the cost price
= 100 + 25
= Tk. 125
Discount = 10% of 125
= (10/100) × 125
= Tk. 12.5
Selling Price (SP) = 125 - 12.5 = Tk. 112.5
∴ Profit = SP - CP = 112.5 - 100 = Tk. 12.5
∴ Overall percentage profit = (profit/cost price) × 100%
= (12.5/100) × 100%
= 12.5%
Question: A shopkeeper incurs a loss by selling an article for Tk 600. If he had sold it for Tk 900, he would have made a profit which is three times the initial loss. At what price should he sell the article to make 20% profit?
Solution:
ধরি, পণ্যের ক্রয়মূল্য = x টাকা
600 টাকায় বিক্রি করলে ক্ষতি = x - 600 টাকা
900 টাকায় বিক্রি করলে লাভ = 900 - x টাকা
প্রশ্নমতে,
900 - x = 3(x - 600)
⇒ 900 - x = 3x - 1800
⇒ 900 + 1800 = 3x + x
⇒ 2700 = 4x
∴ x = 675 টাকা
এখন, 20% লাভে,
ক্রয়মূল্য 100 টাকা হলে বিক্রয়মূল্য 120 টাকা
ক্রয়মূল্য 1 টাকা হলে বিক্রয়মূল্য 120/100 টাকা
∴ ক্রয়মূল্য 675 টাকা হলে বিক্রয়মূল্য = (120 × 675)/100 টাকা
= 810 টাকা
∴ বিক্রয়মূল্য: Tk. 810
Let the price paid by Prateek be Tk. x
Then,
140% of 120% of x=10500
⇒(140/100)×(120/100)×x=10500
⇒ x=(10500×25/42)=6250
Question: If two numbers are respectively 30% and 40% more than a third number, what percent is the first of the second?
Solution:
Let the third number be 100
Then,
1st number = 100 + 30 = 130
2nd number = 100 + 40 = 140
To find what percent the first number is of the second number is,
=(130 × 100)/140
= 650/7
=92.86%
∴ The first number is 92.86% of the second number.
Question: A dishonest dealer marks up the price of his goods by 20% and gives a discount of 10% to the customer. He also uses a 900 gram weight instead of a 1 kilogram weight. Find his percentage profit due to these maneuvers?
Solution:
Let Cost Price, CP = Tk. 1 per gram
Dealer marks up by 20%,
Then the Marked Price of 1000 gram is = 1000 + 20% of 1000
= 1000 + 200 =Tk. 1200
Now Dealer gives 10% discount,
So, Selling price after discount = 1200 - 10% of 1200
= 1200 - 120 = Tk. 1080
Then, Dealer is dishonest and sells 900 grams for the price of 1080 Tk.
The Cost Price of 900 grams is Tk. 900 (since the cost price per gram is Tk. 1).
Profit = 1080 - 900 = 180
so, Percentage profit = (Profit/Cost Price) × 100%
= (180/900) × 100%
= 20%
Suppose, Cost Price = x & Profit = y
So, x + y = 30,000.......... (i)
x + 0.9y = 29,500....... (ii)
(i) - (ii), we get
y = 5000
So, Cost Price = 30,000 - 5000 = 25,000 Taka
বিকল্প পদ্ধতিঃ
লাভ কমলো = ৩০,০০০ - ২৯,৫০০ = ৫০০ টাকা।
প্রশ্নমতে,
১০ % = ৫০০
∴ ১০০ % = (৫০০ × ১০০)/১০ = ৫০০০ টাকা।
অর্থাৎ,
বিক্রয়মূল্য = ৩০, ০০০ টাকা।
মোট লাভ = ৫,০০০ টাকা।
∴ ক্রয়মূল্য = (৩০,০০০ - ৫,০০০) টাকা।
= ২৫,০০০ টাকা।
Question: A man sells 2 commodities for Tk. 3500 each, neither losing nor gaining in the deal. If he sold one commodity at a gain of 25%, then what is the cost price of another commodity?
Solution:
Total S.P. = Tk. 7000 and
Total C.P. = Tk. 7000
Let,
S.P. of 1st commodity = Tk. 3500
Gain on it = 25%
∴ C.P. of 1st commodity
= Tk. {(100/125)×3500}
= Tk. 2800
C.P. of 2nd commodity = Tk. (7000 - 2800) = TK. 4200
Question: The percentage profit earned by selling an article for TK 1730 is equal to the percentage loss incurred by selling the same article for TK 1270. At what price should the article be sold to make 20% profit?
Solution:
Let C.P. = x TK
Profit = (1730 - x) TK
Loss = (x - 1270) TK
ATQ,
{(1730 - x)/x}100 = {(x - 1270)/x}100
⇒ 1730 - x = x - 1270
⇒ 2x = 3000
⇒ x = 1500
Required selling price for 20% profit = (1500 × 120%) TK
= 1500 × (120/100)
= 1500 × (6/5)
= 1800 TK
Population of the city 3 years ago = P = 128000 and n = 3
And,
The decreasing percentage = R = 5%
The present population = P × (1 - R/100)n [Population after n years = P × (1 - R/100)n]
128000 x (1 - 5/100)3
= 128000 × (19/20) × (19/20) × (19/20)
= 16 × 6859 = 109744.
Hence the answer is 109744.
Question: If a man was to sell his table for Tk. 600, he would lose 20%. To gain 20% he should sell it for:
Solution:
Let the Cost price of the table be = x.
∴ Selling price = x - 20% of x
⇒ 600 = x - (20x/100)
⇒ 600 = 80x/100
⇒ 80x = 60000
⇒ x = 60000/80
∴ x = 750
Now, To gain 20% = 750 + 20% of 750
= 750 + 150
= Tk. 900
Given that, Total employed people are 64% of the population, out of that population 48% are employed males, hence 16% are employed females.
So, (employed females)/(total employed people)
= 16/64
= (1/4)
= 25%
Let the initial expenses on Sugar was Tk. 100.
Now, Price of Sugar rises 25%. So, to buy same amount of Sugar, they need to expense,
= (100 + 25% of 100) = Tk. 125.
But, They want to keep expenses on Sugar, so they have to cut Tk. 25 in the expenses to keep it to Tk. 100.
Now, % decrease in Consumption,
(25/125)×100=20%
Let the labeled price of TV = Tk. R
∴ SP of the TV = [R x (100 - 20)] / 100
= Tk. 4R/5
But 16,800 - 800 = 4R/5
∴ x = (16,000 x 5)/4
= Tk. 20,000
Discount = 40%
S.P. = (100-40)% of M.P. = 60% of M.P.
Profit = 20%
∴ S.P. = (100+20)% of C.P.
∴ 60% x MP = 120% of C.P.
∴ C.P. = (1/2) M.P.
∴ MP = 2CP
Since MP should be twice of C.P. to fit into the criteria, we need to increase C.P. by 100% to make it MP.
Question: What percent is 3% of 5%?
Solution:
3% = 3/100
5% = 5/100 = 1/20
percentage = {(3/100)/(1/20)} × 100%
= 60%
In 3 minutes, 4 liters is poured
In, 120 minutes = (120×4)/3 = 160 liters
So, percentage filled = (160×100)/2000 = 8%