ব্যাখ্যা
Solution:
পরীক্ষার্থী = ৭৫০০ জন
অনুপস্থিত = ১৫০০ জন
উপস্থিত = ৭৫০০ - ১৫০০ জন
= ৬০০০ জন
শতকরা উপস্থিত = ৬০০০ ×১০০%/৭৫০০
= ৮০%
PrepBank · বিষয়ভিত্তিক প্রশ্ন
PrepBank · পাতা ১২ / ১৭ · ১,১০১–১,২০০ / ১,৬৯৬
Question: A reduction of 20% in the price of sugar enables a housewife to purchase 6 kg more for Tk. 240. What is original price per kg of sugar?
Solution:
Given that,
Price of sugar reduced by 20%.
With Rs. 240, she can buy 6 kg more sugar than before.
Let the original price per kg of sugar be x Rs.
Now,
Original quantity she could buy for Tk. 240,
∴ Quantity = 240/x kg
After 20% reduction, new price per kg = Tk. 0.8x
∴ Quantity = 240/0.8x = 240/(4x/5) = 1200/4x = 300/x kg
ATQ,
⇒ (300/x) - (240/x) = 6
⇒ (300 - 240)/x = 6
⇒ 60/x = 6
⇒ x = 60/6
∴ x = 10
So the original price per kg of sugar = Tk. 10
Question: A student mistakenly multiplied a number by 7/10 instead of 7/5. Find the percentage error in the result.
Solution:
Let
The number is 100.
ATQ,
The actual calculation be: (7/5) × 100 = 140
and error calculation be: (7/10) × 100 = 70
∴ Difference = 140 - 70 = 70
∴ Percentage error = (70/140) × 100 = 50%
Question: A candidate scoring 25% marks in an examination fails by 10 marks while another candidate who score 50% marks get 15 marks more than the minimum pass marks. What is the minimum pass mark?
Solution:
Let total mark = m
ATQ,
(m × 25%) + 10 = (m × 50%) – 15
⇒ (m/4) + 10 = (m/2) - 15
⇒ (m/2) - (m/4) = 15 + 10
⇒ m/4 = 25
⇒ m = 100
∴ minimum pass mark = (m/4) + 10
= (100/4) + 10
= 25 + 10
= 35
Question: A man purchases two clocks A and B at a total cost of Tk. 650. He sells A with a 20% profit and B at a loss of 25% and gets the same selling price for both clocks. What are the purchasing prices of A and B respectively?
Solution:
Let
selling price for both clocks is x taka
Purchasing price of A is = x/1.2 taka
Purchasing price of B is = x/0.75 taka
Now
(x/1.2) + (x/0.75 ) = 650
⇒ (100x/120) + (100x/75) = 650
⇒ x/120 + x/75 = 650/100
⇒ x (5 + 8)/600 = 650/100
⇒ x = (650 × 600)/ (100 × 13)
= 300 Taka
Purchasing price of A is = x/1.2 taka = 300/1.2 taka = 250 taka
Purchasing price of B is = x/0.75 taka = 300/0.75 = 400 taka
Question: (a% of b) + (b% of a) is equal to:
Solution:
According to question
(a% of b) + (b% of a)
= b × (a/100) + a × (b/100)
= (ab/100) + (ab/100)
= 2ab/100
= 2% of ab
Question: A book is listed at Tk. 920. A customer pays Tk. 742.90 for it after receiving two successive discounts. If the first discount is 15%, what is the rate of the second discount?
Solution:
MP = 920
After first discount Marked Price (MP) become,
= 920 - 15% of 920 = 782
The Selling Price (SP) = 742.90
Let,
second discount was x% on 782
⇒ 782 - x% of 782 = 742.90
⇒ 782x/100 = 39.1
⇒ 782x = 3910
⇒ x = 5%
∴ Second Discount = 5%
15% of 3200 = 480
MP = 3200 + 480 + 320 = 4000
P = 4000 - 3200 = 800
P% = 8003200 × 100
Question: A retailer purchases a TV at a discount of 25% from the wholesaler. He marks it up by 50% on the discounted price and then offers a discount of 20% to the customer. What is his percentage profit?
Solution:
Let the original price of the TV be 1000 Taka.
Wholesaler’s discount = 25%
Retailer’s purchase price:
1000 − 25% of 1000 = 1000−250 = 750 Taka
Retailer’s markup = 50% on Taka 750
New marked price:
750 + 50% of 750 = 750 + 375 = 1125 Taka
Customer’s discount = 20% on Taka 1125
Selling price:
1125 − 20% of 1125 = 1125 − 225 = 900 Taka
So, Profit = {(900 - 750)/750} × 100%
= 20%
Question: The price of a book is Tk. 200. Its price is increased by 15% and then decreased by 20%. What is the present price of the book?
Solution:
Initial Cost = Tk. 200
After 15% increase in the cost, it becomes,
(200 + 15% of 200)
= 200 + 30
= Tk. 230
Now, Cost is decreased by 20%, So cost will become,
(230 - 20% of 230)
= 230 - 46
= Tk. 184
So, present cost is Tk. 184.
Question: If the price of an article is increased by 25% and then decreased by 20%, the net change in the price is -
Solution:
Let,
The price of an article is 100 Tk.
If the price increased by 25%,
So, the new price will be after increase = 100 + {100 × (25/100)} Tk.
= 100 + 25 Tk.
= 125 Tk.
Then the new price decreased by 20%,
So, the new price will be after decrease = 125 - {125 × (20/100)} Tk.
= 125 - 25 Tk.
= 100 Tk.
∴ The net effect on the price of the article is = (100 - 100)
= 0 Taka
So, after both the increase and the decrease, the price remains the same.
Profit earned by manufacturer = 20%
Profit earned by wholesaler = 25%
Profit earned by retailer = 30%
S.P. of shoes = Tk. 50
Therefore, 130% of 125% of 120% of x = 50.50
⇒ 120/100 × 125/100 × 130/100 × x = 5050/100
⇒ (195/100) x = 5050/100
⇒ x = (5050 × 100)/(195 × 100)
⇒ x = 25.89
Cost price of shoes = Tk. 25.89
Question: The length and breadth of a square are increased by 40% and 30% respectively. The area of the resulting rectangle exceeds the area of the square by:
Solution:
Let, old length 100 m and breadth 100m
Old area = 100 × 100 m2
= 10000 m2
New length = 100 + 40
= 140 m
New breadth = 100 + 30
= 130 m
New area = 140 × 130 m2
= 18200 m2
The area of the resulting rectangle exceeds the area of the square by = {(18200 - 10000)/10000} × 100%
= (8200/10000)× 100%
= 83%
Question: A person buys certain number of gems at 20 per taka and an equal number at 30 per taka. He mixes them and sells them at 25 per taka. His gain or loss in the transaction is-
Solution:
The cost price of each gem is 20 per Tk. = Tk. 1/20
The price of each gem is 30 per Tk. = Tk. 1/30
∴ Average cost of gem = {(1/20) + (1/30)}/2
= (3 + 2)/(2 × 60)
= 5/120
= 1/24
The selling price of mixed gem = Tk. 1/25
∴ Loss = (1/24) - (1/25) = 1/600
Cost price 1/24 then loss Tk. 1/600
Cost price 1 then loss Tk. (1/600)/(1/24)
∴ Cost price 1 then loss Tk. {(1/600)/(1/24)} × 100
= 4%
∴ There is a loss of 4%
Question: If A's income is 20% less than that of B, then by what percent is B's income more than that of A?
Solution:
Let B’s income be Tk. x
∴ A's income = x - 20% of x
= x - 0.20x
= 0.80x
So, A's icome = 0.80x
Difference between B's and A's income,
= x - 0.80x
= 0.20x
∴ Percentage = (Difference/A's income) × 100%
= (0.20x/0.80x) × 100%
= (1/4) × 100%
= 25%
Question: A sells an article which costs him Tk. 400 to B at a profit of 20%. B then sells it to C, making a profit of 10% on the price he paid to A. How much dose C pay to B?
Solution:
A এর 20% লাভে বিক্রয়মূল্য = 400 + 400 এর 20%
= 400 + 400 এর 20/100
= 400 + 80
= 480
A এর বিক্রয়মূল্য = B এর ক্রয়মূল্য
B এর 10% লাভে বিক্রয়মূল্য = 480 + 480 এর 10%
= 480 + 480 এর 10/100
= 480 + 48
= 528
B এর বিক্রয়মূল্য = C এর ক্রয়মূল্য = 528 টাকা
The cost price of 12 toys = Tk. 375
The selling price of 12 toys = 33 × 12
= Tk. 396
profit = 396 - 375
= Tk. 21
Profit percentage = (21 × 100)/375
= (7 × 100)/125
= (7 × 4)/5
= 5.6%
Question: A shopkeeper incurs a loss by selling an article for Tk 800. If he had sold it for Tk 1200, he would have made a profit which is four times the initial loss. At what price should he sell the article to make 25% profit?
Solution:
ধরি, পণ্যের ক্রয়মূল্য = x টাকা
800 টাকায় বিক্রি করলে ক্ষতি = x - 800 টাকা
1200 টাকায় বিক্রি করলে লাভ = 1200 - x টাকা
প্রশ্নমতে,
1200 - x = 4(x - 800)
⇒ 1200 - x = 4x - 3200
⇒ 1200 + 3200 = 4x + x
⇒ 4400 = 5x
∴ x = 880 টাকা
এখন, 25% লাভে,
ক্রয়মূল্য 100 টাকা হলে বিক্রয়মূল্য 125 টাকা
ক্রয়মূল্য 1 টাকা হলে বিক্রয়মূল্য 125/100 টাকা
∴ ক্রয়মূল্য 880 টাকা হলে বিক্রয়মূল্য = (125 × 880)/100 টাকা
= 1100 টাকা
∴ বিক্রয়মূল্য: Tk. 1100
Question: A fruit seller sells 20 oranges for Tk. 900 and suffers a loss equal to the cost price of 5 oranges. Find the cost price of one orange.
Solution:
Let,
cost price of 1 orange is = Tk. x
∴ cost price of 20 oranges is = Tk. 20x
∴ cost price of 5 oranges is = Tk. 5x
We know,
Cost price - Selling price = Loss
20x - 900 = 5x
⇒ 20x - 5x = 900
⇒ 15x = 900
⇒ x = 900/15
∴ x = 60
∴ Cost price of 1 orange is Tk. 60
Question: 70 grams is what percentage of 20 kilograms?
Solution:
We know,
20 kg = 20 × 1000
= 20000 grams
∴ Percentage = (70 ÷ 20000) × 100
= 0.35%
∴ 70 grams is 0.35% of 20 kg.
প্রশ্ন: ৫৫০ এর ৯২.৫% সমান কত?
সমাধান:
৫৫০ এর ৯২.৫%
= ৫৫০ × (৯২.৫/১০০)
= ৫৫০ × (৯২৫/১০০০)
= ৫০৮.৭৫
84% = 264
So, 100% = (264 × 100) / 84
= 314.29 ≈ 314
Question: If the side of a square is increased by 20%, by what percent will the area be increased?
Solution:
Let the original side length = 10 units.
∴ Area = 10 × 10 = 100 square units
Again,
After a 20% increase, the new side length = 10 + (20% of 10)
= 10 + 2 = 12 units
∴ New area = 12 × 12 = 144 square units
∴ Increase in area = (144 - 100) square units
= 44 square units
∴ Percentage increase in area = (44/100) × 100%
= 44%
So the area will increase by 44%
প্রশ্ন: হাসান একটি পণ্য বিক্রি করে ২০% লাভ করে। যদি সে উক্ত পণ্যটি ১০% কম দামে কিনত এবং ৪০% লাভে বিক্রি করত, তাহলে সে ২৪ টাকা বেশি পেত। তাঁর প্রকৃত বিক্রয়মূল্য কত ছিল?
সমাধান:
ধরি, প্রকৃত ক্রয়মূল্য = x টাকা
∴ ২০% লাভে বিক্রয়মূল্য = x + x এর ২০%
= x + ২০x/১০০
= ১২০x/১০০
= ১২x/১০
= ৬x/৫
নতুন ক্রয়মূল্য = x − x এর ১০%
= x − ১০x/১০০
= ৯০x/১০০
= ৯x/১০
৪০% লাভে নতুন বিক্রয়মূল্য = (৯x/১০) + (৯x/১০) এর ৪০%
= (৯x/১০) + (৩৬x/১০০)
= (৯০x + ৩৬x)/১০০
= ১২৬x/১০০
= ৬৩x/৫০
প্রশ্নমতে,
নতুন বিক্রয়মূল্য − পূর্ব বিক্রয়মূল্য = ২৪
⇒ ৬৩x/৫০ − ৬x/৫ = ২৪
⇒ (৬৩x - ৬০x)/৫০ = ২৪
⇒ ৩x/৫০ = ২৪
⇒ ৩x = ২৪ × ৫০
⇒ x = (২৪ × ৫০)/৩
∴ x = ৪০০
∴ প্রকৃত বিক্রয়মূল্য = ৬x/৫ = (৬×৪০০)/৫
= ৪৮০ টাকা
25% of A = 35% of B
⇒ (25/100)A = (35/100)B
⇒ A/4 = 7B/20
⇒ A/B = (7/20)×4 = 7/5
⇒ A:B = 7:5
Question: In a factory, there are workers, executives and clerks. 70% of the employees are workers, 596 are executives and the remaining 334 employees are clerks. How many employees are there in the factory?
Solution:
Let
Total employee 100%
Executive and clerks (100 - 70)% = 30%
executive and clerks employee = 596 + 334 = 930
Now
30% employee = 930
∴ 1% employee = 930/30
∴ 100% employee = ( 930 × 100)/30 = 3100